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Continuous settling basin (10 m³/s)

Short answer

Add 10% flushing, so design flow is 11 m3/s. Camp velocity is 0.1704 m/s; with H=3 m, provide two chambers 11 m wide. Turbulence gives effective fall velocity 0.037 m/s and length 13.8 m, adopt 15 m. Each chamber is 11 m x 15 m with hoppers.

Design a continuous type settling basin with neat sketches for a hydropower plant using the following data: settling velocity = 5 cm/sec; turbine discharge = 10 m³/sec; particle size to be removed = 0.15 mm. Assume other necessary data if necessary.

Given: design discharge Q=10.0Q=10.0 m³/s; particles of size d≥0.15d\ge 0.15 mm to be trapped, fall velocity w=5.00w=5.00 cm/s =0.0500=0.0500 m/s (given). The basin is of the continuous flushing type, so a flushing discharge of 10% (1.0 m³/s) is added. Turbulence is included, and other data are assumed. (A fall velocity of 5 cm/s is high for 0.15 mm sand, so the basin is short; the given value is used.)

Flushing water of 10% is added for continuous flushing, so the design flow of the basin is Q′=10.0+1.0=11.0Q'=10.0+1.0=11.0 m³/s.

Step 1: Horizontal velocity (Camp)

For 0.1<d<10.1<d<1 mm, v=adv=a\sqrt d with a=44a=44 (v in cm/s, d in mm):

v=440.15=17.04 cm/s=0.1704 m/sv=44\sqrt{0.15}=17.04\ \text{cm/s}=0.1704\ \text{m/s}

This is within the usual 0.1-0.4 m/s range, so deposited sediment is not re-suspended.

Step 2: Cross-section and width

Assume a flow depth H=3.0H=3.0 m in the settling zone (the hopper depth is extra).

B=Q′vH=11.00.1704×3.0=21.52 mB=\frac{Q'}{vH}=\frac{11.0}{0.1704\times3.0}=21.52\ \text{m}

Provide n=2n=2 chambers, so that one can be taken out for inspection while the other works: b=B/n=10.76b=B/n=10.76 m each, adopt 11.0 m.

Step 3: Length without turbulence

L0=vHw=0.1704×3.00.0500=10.2 mL_0=\frac{vH}{w}=\frac{0.1704\times3.0}{0.0500}=10.2\ \text{m}

Step 4: Effect of turbulence

Turbulence reduces the effective fall velocity: w′=w−αw'=w-\alpha, with α=0.132 v/H\alpha=0.132\,v/\sqrt{H}.

α=0.132×0.17043.0=0.0130 m/sw′=0.0500−0.0130=0.0370 m/sL=vHw′=0.1704×3.00.0370=13.8 m\begin{aligned} \alpha&=\frac{0.132\times0.1704}{\sqrt{3.0}}=0.0130\ \text{m/s}\\ w'&=0.0500-0.0130=0.0370\ \text{m/s}\\ L&=\frac{vH}{w'}=\frac{0.1704\times3.0}{0.0370}=13.8\ \text{m} \end{aligned}

Adopted dimensions

ItemValue
Flow velocity vv0.170 m/s
Settling depth HH3.0 m (plus about 1.0 m for the flushing hoppers)
Number of chambers2
Width of each chamber11.0 m
Length of settling zone15 m
Length/width ratio1.4
Inlet transitiongradual, with guide vanes (side slope not steeper than about 1:5)

Total volume of water in the basin ≈990\approx 990 m³. Because the basin is short and wide, a good inlet transition with guide vanes is essential to spread the flow evenly.

PLAN (continuous flushing outlets along each chamber)
          inlet        settling chambers      outlet
 canal   transition  +=================+   transition
 =====>  \         / |  chamber 1      | \         /===> to
         /  guide  \ +-----------------+ /  weir   \    headrace
 =====>  \  vanes  / |  chamber 2      | \         /
         /         \ +=================+ /         \
  trash-                  |  |  flushing conduits (0.5 m3/s each)
  rack                    v  v  --> flushing channel --> river
LONGITUDINAL SECTION
 inlet          settling zone (depth H)      outlet
 ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~  WL
 \    --->   --->   --->   --->   --->   --->  |
  \  ______________________________________   | weir
   \/ \/ \/ \/ \/ \/ hoppers with bottom outlets \__|__ to headrace
   ==== flushing conduit (continuous flow) ====> river

Flushing arrangement: the floor of each chamber is formed into hoppers with bottom openings leading to a flushing conduit. About 0.5 m³/s per chamber (1.0 m³/s in total) is drawn off continuously through these openings and carries the settled sediment back to the river, so the chambers do not have to be taken out of service for flushing. A gate on each conduit controls the flushing flow, and inlet gates allow one chamber to be isolated for inspection while the other keeps supplying the plant.

Answer: 2 chambers, each about 11.0 m wide x 15 m long x 3.0 m deep (settling zone), with v=0.170v=0.170 m/s and 1.0 m³/s of continuous flushing water.

✓ Answer checked by Claude Opus 5.5 (high effort)

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