- 2077 Chaitra · 8 marks
Audible noise of 750 kV line using two formulas
Short answer
For N=2, formula (ii) without the 26.4logN term is appropriate. Using the given conductor diameter 0.30 m (30 cm), the total AN at 20 m from the outer phase is 108.7 dB(A). If the more realistic 3 cm diameter were used, it would be 53.7 dB(A).
A 750 kV flat horizontal configured transmission line has average ground clearance of 20 m and phase spacing of 15 m. The line uses bundle conductor of 2 × 0.30 m diameter. Determine the audible noise at the horizontal distance of 20 m from the outer most conductor. Assume empirical formula from below. (i) 120 log10(Em(i)) + 55 log10(d) − 11.4 log10(D(i)) + 26.4 log10(N) − 128.4 (ii) 120 log10(Em(i)) + 55 log10(d) − 11.4 log10(D(i)) − 115.4 Em = kV/cm, D = m, d = cm
The AN of each phase is computed from the empirical formula and the phase-to-microphone distance, then added on an energy basis. Both given formulas are evaluated. Formula (i), with the term, is meant for bundles with . Formula (ii) is meant for , so (ii) is the appropriate one here ().
Data
- m, m,
- Sub-conductor diameter 0.30 m as printed, so cm
- Gradient not given; assume 20 kV/cm on all phases (the value used in the companion question)
- Microphone at ground, 20 m horizontally beyond the outer phase
Step 1: Distances (horizontal 20, 35, 50 m)
Step 2: Common terms
Formula (i)
This gives 100.37, 98.61 and 97.18 dB(A).
Formula (ii)
This gives 105.42, 103.66 and 102.23 dB(A).
| Phase distance | (i) dB(A) | (ii) dB(A) |
|---|---|---|
| 28.28 m | 100.37 | 105.42 |
| 40.31 m | 98.61 | 103.66 |
| 53.85 m | 97.18 | 102.23 |
| Total | 103.68 | 108.74 |
The two formulas differ by a constant dB per phase.
Note on conductor size
A 30 cm sub-conductor is unrealistic; 0.030 m (3 cm) is probably intended. With cm every value falls by exactly 55 dB, giving 48.68 dB(A) by (i) and 53.74 dB(A) by (ii). These are typical levels for a 750 kV line.
Answer: with d = 30 cm, AN = 103.7 dB(A) by (i) and 108.7 dB(A) by (ii); formula (ii) applies for N = 2. With d = 3 cm, 48.7 and 53.7 dB(A).
✓ Answer checked by Claude Opus 5.5 (high effort)
Related questions
- Audible noise of 750 kV line (20 kV/cm gradient) · High Voltage Engineering, chapter 5 · asked 3×
- Audible noise of 750 kV line (formula with Di) · High Voltage Engineering, chapter 5 · asked 3×
- Audible noise of 735 kV line at 30 m · High Voltage Engineering, chapter 5 · asked 4×
- Total audible noise of 735 kV line · High Voltage Engineering, chapter 5
- Audible noise of 765 kV line (18 kV/cm outer) · High Voltage Engineering, chapter 5 · asked 4×
- Audible noise of 765 kV line (18.4 kV/cm outer) · High Voltage Engineering, chapter 5 · asked 4×
- 400 kV quadruple bundle line, 20 m spacing · Power System Analysis I, chapter 4
- Inductance of 4-conductor bundle line, 6 m spacing · Power System Analysis I, chapter 4 · asked 2×
- 400 kV twin-bundle line: reactances and charging VAR · Power System Analysis I, chapter 4 · asked 2×
- Inductance of 3-conductor bundled line, 6.1 m spacing · Power System Analysis I, chapter 4