- Asked 2/23
- 2071 Magh · 5 marks
Inductance of 4-conductor bundle line, 6 m spacing
Short answer
Using Deq = 7.56 m and square bundle self-GMD = 0.1863 m, inductance = 0.741 mH/km, yielding 148 mH per phase for 200 km.
Compute the inductance per phase for a 200 km line. Each sub-conductor is of 12 mm radius and configured as given below. [Figure: horizontal single-circuit line; each phase is a square bundle of four sub-conductors with 45 cm sides; centres of adjacent phases 6 m apart.]
Each phase is a square 4-conductor bundle. For inductance, its self-GMD is . The line is taken as transposed.
o o o o o o
o o o o o o
A 6 m B 6 m C
d = 45 cm, r = 12 mm
Data: m, m, m, m, 200 km.
Mutual GMD
Self GMD of bundle
Inductance
Answer: mH per phase for 200 km (0.7407 mH/km).
✓ Answer checked by Claude Opus 5.5 (high effort)
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