- 2069 Poush · 6 marks
Long line sending end voltage derivation
Short answer
Derivation starts with dV/dx = zI, dI/dx = yV, leading to V = K1 e^{gamma x} + K2 e^{-gamma x}. Using receiver-end conditions, V_S = V_R cosh gamma l + Z_c I_R sinh gamma l, obtained by setting x=l. This expression is the exact distributed-parameter sending-end voltage.
Starting from a suitable point, derive the expression of sending end voltage in terms of the receiving end voltage and current for a long length transmission line.
For a long line (above about 250 km) the resistance, inductance and capacitance are distributed uniformly along the length, so the line is analysed with differential equations rather than lumped circuits. Measure from the receiving end.
IS x <------ measured from receiving end
o-->--z.dx--+--z.dx--+-- ... --z.dx--+--> IR
| | |
VS y.dx y.dx y.dx VR
| | |
o-----------+--------+-- ... --------+----o
sending receiving
Starting point and solution
For an element at distance from the receiving end, with and per km:
Differentiating the first and substituting the second:
The general solution and the current (from ) are:
At : and , so and :
So, at any point :
Sending-end voltage
At the sending end, and :
Similarly, .
Hence , , , where:
- is the propagation constant (per km),
- is the characteristic impedance (Ω),
- is the line length.
In the exponential form, the first term is the incident wave (travelling from sending to receiving end) and the second the reflected wave. When the line is terminated in , , the reflected wave is zero and .
✓ Answer checked by Claude Opus 5.5 (high effort)
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