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AVR control of bus voltage

Short answer

The generator equivalent circuit shows Vt ≈ Ef – XsIq; reactive load reduces Vt. An AVR senses terminal voltage via a PT, compares it to a reference, amplifies the error, and adjusts field current to vary Ef and reactive power, thereby restoring Vt to the setpoint.

Starting from the equivalent circuit of a synchronous generator, explain the Principle how AVR (Automatic voltage regulator) control the bus voltage magnitude in a power system.

An Automatic Voltage Regulator (AVR) holds the generator terminal (bus) voltage at a set value by automatically adjusting the field excitation, which changes the generator's internal emf and hence its reactive power output.

Equivalent circuit of the synchronous generator

Neglecting armature resistance, the generator is an emf EfE_f behind synchronous reactance XsX_s:

      jXs       Ia
  +--[~~~~]----->----+---- Vt (bus)
  |                  |
 (Ef)               Load
  |                  |
  +------------------+
Vt=Ef−jXsIaV_t = E_f - jX_sI_a

Taking VtV_t as reference and Ia=Ip−jIqI_a = I_p - jI_q (active and reactive components):

Ef=Vt+XsIq+jXsIpE_f = V_t + X_sI_q + jX_sI_p

For small δ\delta, ∣Ef∣≈Vt+XsIq|E_f| \approx V_t + X_sI_q, so

Vt≈∣Ef∣−XsIq=∣Ef∣−XsQVtV_t \approx |E_f| - X_sI_q = |E_f| - \frac{X_sQ}{V_t}

Principle:

  • Terminal voltage falls when reactive load QQ (lagging current IqI_q) increases, because of the drop XsIqX_sI_q.
  • To keep VtV_t constant, ∣Ef∣|E_f| must be raised. Since Ef=4.44fNΦE_f = 4.44fN\Phi and Φ\Phi depends on field current IfI_f, this is done by increasing IfI_f.
  • Active load mainly changes the angle δ\delta, not ∣Vt∣|V_t| (term jXsIpjX_sI_p is at 90°), so voltage control is essentially reactive-power control.

AVR loop

Vref -->(+)--> Amplifier --> Exciter --> Gen field
         ^-                                  |
         |                                   v
       Rectifier <-- PT <-------- Terminal voltage Vt
       & filter
       (+ stabilising feedback)
  1. Sensing: a potential transformer measures VtV_t; it is rectified and filtered.
  2. Comparison: the measured value is compared with VrefV_{ref}; error e=Vref−∣Vt∣e = V_{ref} - |V_t|.
  3. Amplification: the error is amplified (amplifier gain KAK_A, time constant TAT_A).
  4. Exciter: the amplified signal changes the exciter output voltage, hence field voltage and field current IfI_f.
  5. Generator: EfE_f changes, Q output changes, and VtV_t is driven back to VrefV_{ref}.
  6. A stabilising (rate) feedback loop damps oscillations and improves response.

Operation

  • Load Q rises → VtV_t falls → positive error → more IfI_f → higher EfE_f → generator supplies more Q → VtV_t restored.
  • Load Q falls (or line charging high) → VtV_t rises → negative error → less IfI_f → generator absorbs Q → VtV_t restored.

The AVR acts within the generator capability limits (field heating limit for Q supply, under-excitation/stability limit for Q absorption). Being fast (time constants of the order of a second or less), it also improves transient stability by raising excitation during faults.

✓ Answer checked by Claude Sonnet 5.5

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