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Generator reactive power at constant terminal voltage

Short answer

With constant prime mover power, adjusting field excitation changes internal emf Ef, shifting the reactive power output while terminal voltage Vt stays fixed by the infinite bus. Over-excitation supplies lagging reactive power; under-excitation absorbs leading reactive power, subject to field heating and stability limits.

For a synchronous generator connected to infinite bus, discuss how the generator can supply or consume variable reactive power keeping its terminal voltage constant.

A synchronous generator on an infinite bus has its terminal voltage VtV_t and frequency fixed by the bus. With constant mechanical input (constant P), it can still be made to supply or absorb any reactive power within limits by changing its field excitation.

Equations

With synchronous reactance XsX_s (R neglected), internal emf EfE_f and load angle δ\delta:

Ef=Vt+jXsIa,P=EfVtXssin⁡δ,Q=EfVtcos⁡δ−Vt2XsE_f = V_t + jX_sI_a,\qquad P = \frac{E_fV_t}{X_s}\sin\delta,\qquad Q = \frac{E_fV_t\cos\delta - V_t^2}{X_s}
  • P depends on the turbine input; since VtV_t and XsX_s are fixed, Efsin⁡δE_f\sin\delta = constant. So as EfE_f changes, the tip of EfE_f moves along a line parallel to VtV_t.
  • Iacos⁡ϕI_a\cos\phi (active current) also remains constant.
  • Q depends on Efcos⁡δ−VtE_f\cos\delta - V_t, which changes with excitation.

Three cases

ExcitationConditionQPower factor
NormalEfcos⁡δ=VtE_f\cos\delta = V_t0Unity
Over-excitedEfcos⁡δ>VtE_f\cos\delta > V_tSupplied (+)Lagging
Under-excitedEfcos⁡δ<VtE_f\cos\delta < V_tAbsorbed (−)Leading
     locus of Ef tip (P constant)
   --------x-------x--------x-------
          /       /        /
     Ef1 /   Ef2 /    Ef3 /     Ef1 < Ef2 < Ef3
        /       /        /
       O--------------------> Vt
   Ef1: under-excited (absorbs Q)
   Ef3: over-excited (supplies Q)

Explanation

  • Increasing field current raises EfE_f; δ\delta decreases and IaI_a swings to lagging. The generator sends Q into the bus.
  • Decreasing field current lowers EfE_f; δ\delta increases and IaI_a becomes leading. The generator draws Q from the bus.
  • Terminal voltage remains constant because the infinite bus holds it.

Limits

Maximum Q is set by field heating (maximum EfE_f) and armature current; minimum Q (maximum absorption) by the steady-state stability limit (δ\delta near 90°) and stator end heating. This is how generators are used for voltage/Q support in a real grid.

✓ Answer checked by Claude Sonnet 5.5

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