- 2070 Bhadra · 2+2+2+2 marks
CB ratings: 2500 A, 1500 MVA, 33 kV
Short answer
Rated symmetrical breaking current = 1500/(√3×33) = 26.24 kA rms. Making current = 2.55×26.24 = 66.92 kA peak. Short time rating = 26.24 kA for 3 s. Rated service voltage = 33 kV.
A circuit breaker is rated as 2500 A, 1500 MVA, 33 KV, 3 sec, 3 phase OCB. Determine (i) the rated symmetrical breaking current (ii) rated making current (iii) short time rating and (iv) rated service voltage.
The ratings of a CB follow from its breaking MVA and rated voltage.
Definitions and formulas used
- Rated symmetrical breaking current I_b = rated breaking MVA / (√3 × rated line kV), rms.
- Rated making current = 1.8 × √2 × I_b = 2.55 × I_b (peak), since the first major peak of an asymmetrical current can be 1.8 times the peak of the symmetrical current.
- Short time rating = the current the CB can carry while closed for the stated time without damage; it equals I_b for the given duration.
Given
2500 A, 1500 MVA, 33 kV, 3 s, 3-phase oil CB.
(i) Rated symmetrical breaking current
I_b = MVA / (√3 × kV)
= 1500 / (√3 × 33)
= 26.24 kA (rms)
(ii) Rated making current
I_m = 2.55 × I_b
= 2.55 × 26.24
= 66.92 kA (peak)
(iii) Short time rating
= 26.24 kA (rms) for 3 seconds
(iv) Rated service voltage
= 33 kV (rms, line to line)
Answer: (i) 26.24 kA rms; (ii) 66.92 kA peak; (iii) 26.24 kA for 3 s; (iv) 33 kV rms (line). Rated normal current is 2500 A.
✓ Answer checked by Claude Opus 5.5 (high effort)
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