- 2070 Chaitra · 8 marks
Reactor schemes in stations and substations
Short answer
Reactor schemes include generator reactors in series with each generator, feeder reactors in series with outgoing feeders, and bus-bar reactors that divide the bus into sections. Bus-bar schemes are ring and tie-bar; the tie-bar puts two reactors in the fault path, allowing smaller reactors.
Explain different reactor schemes used in generating station and substations.
Current-limiting reactors are placed at chosen points of a station so that the short-circuit current is limited and a fault in one part does not collapse the voltage of the whole station. The main schemes are below.
1. Generator reactor scheme
Reactor in series with each generator, between the generator and the bus.
G1 G2 G3
[X] [X] [X]
| | |
=+===+===+===+===+= bus
| |
feeders
- Protects the generator against faults beyond it.
- Disadvantage: full load current always flows, so constant voltage drop and loss; a feeder fault still lowers the whole bus voltage. Now seldom used, as modern machines have high reactance.
2. Feeder reactor scheme
Reactor in series with each outgoing feeder.
G1 G2
| |
=+===+===+===+= bus
[X] [X]
| |
feeder feeder
- A feeder fault is limited by its own reactor; the bus voltage stays nearly normal, so other feeders are not disturbed.
- Disadvantage: no protection against bus faults; constant drop and loss in each feeder.
3. Bus-bar reactor schemes
The bus is divided into sections, each with a generator; sections are joined through reactors. In normal operation little current passes between sections, so losses are small.
(a) Ring system: each section connected to the next through a reactor, forming a ring.
G1 G2 G3
=S1===[X]===S2===[X]===S3=
| |
+----------[X]-----------+
A fault on one section is fed by the other generators only through reactors. Each section is fed from both sides, so it is more reliable than a straight in-line arrangement.
(b) Tie-bar system: each section is connected through its own reactor to a common tie-bar.
=S1= =S2= =S3= sections
[X] [X] [X]
| | |
=+=======+=======+= tie-bar
Fault current from any other section passes through two reactors in series, so each reactor can be about half the value needed in a ring system. New sections are added easily. It needs an additional bus-bar.
Comparison
| Scheme | Normal loss/drop | Main merit | Main demerit |
|---|---|---|---|
| Generator | High | Protects generator | Constant loss |
| Feeder | High | Bus voltage held on feeder fault | No bus-fault protection |
| Ring bus | Low | Fault confined to section | Unbalanced loads cause section voltage difference |
| Tie-bar | Low | Two reactors in fault path; easy extension | Extra tie-bar cost |
✓ Answer checked by Claude Opus 5.5 (high effort)
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