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Define loss of load factor

Short answer

Loss of load factor is the ratio of average power loss to loss at peak demand. It converts peak loss to annual energy loss (Eloss = Ploss,peak × LLF × hours) and is critical for economic conductor sizing, transformer selection, and setting loss limits.

Define loss of load factor with respect to distribution consumer characteristics and discuss its significance on the design of distribution system.

Loss of load factor (LLF), also called loss factor, is the ratio of the average power loss in a system element over a period to the power loss at peak load during that period:

LLF=Average power lossPower loss at peak load=Energy loss in time TPloss,peak×TLLF = \frac{\text{Average power loss}}{\text{Power loss at peak load}} = \frac{\text{Energy loss in time } T}{P_{loss,peak} \times T}

Since copper loss varies as the square of the current, LLF=1T∫0T(PPmax)2dtLLF = \frac{1}{T}\int_0^T \left(\frac{P}{P_{max}}\right)^2 dt. It always lies between LF2LF^2 and LFLF, and an empirical relation is used in practice:

LLF=0.3 LF+0.7 LF2LLF = 0.3\,LF + 0.7\,LF^2

Significance in distribution design:

  • Energy loss in feeders and transformer windings is found simply as Eloss=Ploss,peak×LLF×8760E_{loss} = P_{loss,peak} \times LLF \times 8760 kWh/year, without a full hourly load curve.
  • It is used to cost the losses over the life of the system, which decides the economic conductor size and transformer rating.
  • Because LLF < LF, the % energy loss is lower than the % peak power loss (%Eloss=%Ploss,peak×LLF/LF\%E_{loss} = \%P_{loss,peak} \times LLF/LF); designers use this to set acceptable peak loss limits.
  • It shows the benefit of improving load factor (flatter load means lower loss per kWh sold).

✓ Answer checked by Claude Opus 5.5 (high effort)

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