- 2082 Bhadra (new course) · 3 marks
Excitation system and changing excitation at constant load
Short answer
Excitation system supplies dc field current, determining back emf and power factor. At constant load, changing excitation alters only reactive power: underexcitation gives lagging pf, normal excitation gives unity pf and minimum current, overexcitation gives leading pf, following V-curves.
Define excitation system in synchronous motor. Explain briefly with neat phasor diagram about the effect of changing excitation with constant load in synchronous motor.
The excitation system of a synchronous motor is the DC source and its control (DC exciter, static rectifier or brushless exciter, with field regulator) that supplies the field current to the rotor poles; it decides the back emf and hence the motor's power factor.
Effect of changing excitation at constant load
With constant load, and are constant. Only the reactive part of changes.
Ia3 (over: lead)
\ Ia2 (normal: upf)
\ |
-----------\------+--------> V
\ |
Ia1 (under: lag)
tip of Ia moves on a line normal to V
| Excitation | pf | ||
|---|---|---|---|
| Under | large | lagging | |
| Normal | minimum | unity | |
| Over | large | leading |
The phasor diagram for the voltages shows the same effect. Since is constant, the tip of moves on a line parallel to as excitation changes:
Ef1 (under) Ef2 (normal) Ef3 (over)
.-----------.-------------. <- locus of Ef tip (parallel to V)
| | |
O----------------------------> V
Er = V - Ef joins the tip of Ef to the tip of V;
Ia = Er / jXs lags Er by 90 deg
As field current rises, first falls to a minimum (unity pf) and then rises with leading pf, giving the V-curve.
✓ Answer checked by Claude Sonnet 5.5
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