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Excitation system and changing excitation at constant load

Short answer

Excitation system supplies dc field current, determining back emf and power factor. At constant load, changing excitation alters only reactive power: underexcitation gives lagging pf, normal excitation gives unity pf and minimum current, overexcitation gives leading pf, following V-curves.

Define excitation system in synchronous motor. Explain briefly with neat phasor diagram about the effect of changing excitation with constant load in synchronous motor.

The excitation system of a synchronous motor is the DC source and its control (DC exciter, static rectifier or brushless exciter, with field regulator) that supplies the field current to the rotor poles; it decides the back emf EfE_f and hence the motor's power factor.

Effect of changing excitation at constant load

With constant load, VIacos⁡ϕVI_a\cos\phi and Efsin⁡δE_f\sin\delta are constant. Only the reactive part of IaI_a changes.

         Ia3 (over: lead)
           \        Ia2 (normal: upf)
            \       |
  -----------\------+--------> V
              \     |
          Ia1 (under: lag)
   tip of Ia moves on a line normal to V
ExcitationEfE_fIaI_apf
Under<V< Vlargelagging
Normal≈V\approx Vminimumunity
Over>V> Vlargeleading

The phasor diagram for the voltages shows the same effect. Since Efsin⁡δE_f\sin\delta is constant, the tip of EfE_f moves on a line parallel to VV as excitation changes:

  Ef1 (under)  Ef2 (normal)  Ef3 (over)
   .-----------.-------------.   <- locus of Ef tip (parallel to V)
   |           |             |
   O----------------------------> V
   Er = V - Ef joins the tip of Ef to the tip of V;
   Ia = Er / jXs lags Er by 90 deg

As field current rises, IaI_a first falls to a minimum (unity pf) and then rises with leading pf, giving the V-curve.

✓ Answer checked by Claude Sonnet 5.5

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