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Guide bund design, 7000 m3/s

Short answer

Waterway W=4.75√7000≈397 m, shank 1.25W=496 m, tail 99 m. Pitching t=1.15 m. Scour R=8.71 m. Straight apron width 1.5×8.06=12.10 m, depth below bed 8.06 m; nose width 1.5×12.42=18.63 m, depth 12.42 m; laid thickness √5 t≈2.57 m.

Design a guide bund for a flood discharge of 7000 cumecs, the high flood depth is 5 m and the silt factor is 1.1.

Data and design basis

  • Silt factor given: f=1.10f = 1.10
  • Flood depth: h=5.00h = 5.00 m
  • Design discharge for scour/apron: Q=7000Q = 7000 m³/s

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.757000=397.41W = 4.75\sqrt{Q} = 4.75\sqrt{7000} = 397.41 m. Adopt W≈397W \approx 397 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×397=496 mLds=0.25W=99 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 397 = 496\ \text{m} \\ L_{ds} &= 0.25W = 99\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=198R_u \approx 0.5W = 198 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=99R_d \approx 0.25W = 99 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=198×2.094=416= R_u\theta = 198\times 2.094 = 416 m, so total length on the upstream side ≈912\approx 912 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×70001/3=0.06×19.13=1.15 mt = 0.06\,Q^{1/3} = 0.06\times 7000^{1/3} = 0.06\times 19.13 = 1.15\ \text{m}

Adopt t≈1.2t \approx 1.2 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(70001.10)1/3=8.71 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{7000}{1.10}\right)^{1/3} = 8.71\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R17.42 m12.42 m18.63 m
Shank (straight)1.5R13.06 m8.06 m12.10 m

Thickness: pitching t=1.15t = 1.15 m, so the launched apron thickness is 1.5t=1.5×1.15=1.721.5t = 1.5\times1.15 = 1.72 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.57T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.57 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW397.41 m (adopt 397 m)
Length of guide bund (u/s)496 m; d/s tail 99 m
Pitching thickness tt1.15 m
Apron at shank: width 1.5D′1.5D' / thickness12.10 m / 1.72 m launched (2.57 m laid)
Apron at nose: width / thickness18.63 m / 1.72 m launched (2.57 m laid)

Sketches

Plan of guide bunds:

 U/S                                          D/S
                       bridge / weir axis
   Shank (straight)                |
 ________________________________  |  ___
/  1.0-1.5 W upstream            \ | /   \  tail
\________________________________/=|=\___/  0.25 W
 curved head                       |
 R, sweep 120 deg    <-- waterway W -->
 ________________________________  |  ___
/                                \ | /   \
\________________________________/=|=\___/

Section at the shank (straight portion):

           top width 6 m
         ___________  <- HFL + 1.5 m
        /           \
 HFL ---/-------------\---  2:1 slopes
       / pitching t    \
 bed__/__ filter ______ \___
      \_ launching apron _/ (launches at 2:1)

✓ Answer checked by Claude Opus 5.5 (high effort)

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