- 2075 Baisakh · 6 marks
Fault clearing process with trip circuit
Short answer
The fault current via CT energizes the relay coil; relay contacts close, allowing DC from battery through trip coil to release the breaker latch. The breaker opens, arc extinguishes, and the auxiliary switch resets the trip circuit. Total fault clearing time = relay time + opening time + arcing time.
Explain the fault clearing process with the help of trip circuit.
Fault clearing is the sequence of events from the instant the fault occurs to the final interruption of fault current by the circuit breaker. It uses the trip circuit, which links the relay to the breaker.
Trip circuit
Line ═══[ CB main contacts ]═══════
│ ▲
CT │ opens
│ │
┌─────▼─────┐ ┌──────────┴──┐
│ Relay coil│ │ Trip coil │
└─────┬─────┘ └──┬──────────┘
│ closes │
(+)───┤ Relay contact ├──[52a]──(−)
DC battery aux. switch
- CT/VT: reduce line current and voltage to relay level.
- Relay operating coil: energised by the CT secondary.
- Relay contact: in the DC trip circuit.
- Trip coil: solenoid that releases the breaker mechanism.
- Auxiliary switch (52a): closed when breaker is closed; opens with the breaker and breaks trip-coil current.
- Battery (station DC supply): independent of the AC system, which may collapse during the fault.
Fault clearing process
- Fault occurs: current in the line rises sharply.
- Sensing: the CT secondary current rises proportionally and flows through the relay coil.
- Relay operation: when current exceeds the pick-up setting, the relay (after its set time) closes its contacts. This time is the relay time.
- Trip coil energised: DC current flows from the battery through relay contacts, trip coil and the auxiliary switch.
- Breaker opens: the trip coil plunger releases the latch; stored energy (spring/pneumatic) separates the main contacts. This is the opening time.
- Arc extinction: an arc forms between the contacts and is extinguished at a current zero by the arc-quenching medium (SF₆, vacuum, oil, air). This is the arcing time.
- Trip circuit reset: the auxiliary switch opens, de-energising the trip coil to prevent it burning.
Total fault clearing time = relay time + breaker opening time + arcing time, e.g. 1 cycle + 1.5 cycles + 0.5–1 cycle ≈ 3–4 cycles (60–80 ms at 50 Hz) for a modern EHV breaker.
✓ Answer checked by Claude Opus 5.5 (high effort)
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