- 2066 Bhadra (old course) · 5 marks
Road earthwork, upward grade 1:100
Short answer
Earthwork in cutting = 15,610.65 m³; earthwork in filling = 0.00 m³.
Estimate the quantity of earth work for a portion of road, when formation width is 10 m. Side slope in cutting and filling are 1:1 and 2:1 respectively.
| Distance | 0 m | 30 m | 60 m | 90 m |
|---|---|---|---|---|
| R.L.G | 100 m | 110 m | 111 m | 112 m |
| R.L.F | 100 m, upward grade (1:100) | |||
| (as printed; the ground level row is hard to read) |
Given data and assumptions
- Formation width m; side slopes: cutting , filling . Ground is level across the road.
- Ground levels are read as printed (100, 110, 111, 112 m at 0, 30, 60, 90 m, the scan is hard to read) and formation level starts at 100.00 m, rising 1 in 100.
Method
Level (plain-ground) sections are used. With centre height , formation width and side slope :
Volume between two sections = mean area × distance; where a section changes from cutting to filling, the length of each part is found by proportion of the depths and the volume of each part = ½ × end area × length.
| Chainage | GL (m) | FL (m) | Depth of cutting / height of filling (m) |
|---|---|---|---|
| 0+000 | 100.000 | 100.000 | 0.000 |
| 0+030 | 110.000 | 100.300 | cutting 9.700 |
| 0+060 | 111.000 | 100.600 | cutting 10.400 |
| 0+090 | 112.000 | 100.900 | cutting 11.100 |
Sectional areas
| Chainage | Centre ht. (m) | Cutting area (m²) | Filling area (m²) |
|---|---|---|---|
| 0+000 | 0.00 | 0.000 | 0.000 |
| 0+030 | cut 9.70 | 191.090 | 0.000 |
| 0+060 | cut 10.40 | 212.160 | 0.000 |
| 0+090 | cut 11.10 | 234.210 | 0.000 |
Volumes
| Between | Distance (m) | Cutting (m³) | Filling (m³) |
|---|---|---|---|
| 0+000 – 0+030 | 30.0 | 2,866.35 | 0.00 |
| 0+030 – 0+060 | 30.0 | 6,048.75 | 0.00 |
| 0+060 – 0+090 | 30.0 | 6,695.55 | 0.00 |
| Total | 90.0 | 15,610.65 | 0.00 |
Answer: Earthwork in cutting = 15,610.65 m³; earthwork in filling = 0.00 m³.
✓ Answer checked by Claude Opus 5.5 (high effort)
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