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Gross and net potential between two sections

Short answer

Gross potential is computed by summing 9.81 Q_i ΔH_i for sub‑reaches using mean flows and head drops. Net potential uses design discharge from the flow duration curve after environmental release, net head (gross minus hydraulic losses) and overall turbine‑generator efficiency (∼0.8–0.9): P_net = 9.81 η Q_d H_n (kW).

How do you estimate the gross and net hydropower potential between two sections of a river?

Gross potential is the theoretical power of the river between two sections, using all the flow and the full head difference with 100% efficiency. Net potential is the power that can actually be developed after deducting head loss, efficiency and the part of the flow that cannot be used.

Gross potential

Divide the reach into small sub-reaches where the flow is nearly constant (the flow increases downstream with tributaries and catchment area). For each sub-reach:

Pgross=∑ρgQiΔHi=∑9.81 Qi ΔHi  (kW)P_{gross} = \sum \rho g Q_i \Delta H_i = \sum 9.81\, Q_i\, \Delta H_i \ \ (\text{kW})

where QiQ_i is the mean flow (m³/s) and ΔHi\Delta H_i is the drop in elevation (m) of the sub-reach. Annual energy = P×8760P \times 8760 kWh. Flow comes from the flow series at the two sections (area-ratio method for ungauged sites), and elevations from topographic maps or survey.

Net (technical/economic) potential

  • Choose the design discharge QdQ_d from the flow duration curve (e.g. Q40Q_{40} for RoR), after leaving the environmental flow.
  • Net head Hn=Hgross−hfH_n = H_{gross} - h_f, where hfh_f includes the intake, desander, waterway and penstock losses (about 5-10% of gross head).
  • Overall efficiency η\eta of the turbine, generator and transformer (about 80-90%).
Pnet=9.81 η Qd Hn  (kW)P_{net} = 9.81\, \eta\, Q_d\, H_n \ \ (\text{kW})
  • Annual energy is found from the monthly flows up to QdQ_d. Economic potential is the part for which benefit-cost ratio is greater than one.

✓ Answer checked by Claude Opus 5.5 (high effort)

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