- Asked 3/20
- 2078 Chaitra · 8 marks
Capacitance and charge matrices (9.81 m clearance)
Short answer
Equivalent bundle radius is 12.04 cm. Maxwell's matrix inversion gives capacitance matrix (diagonals 11.13 and 11.31 pF/m). With 230.94 kV rms phase voltages, the RMS charge matrix is 2.795∠4.3°, 2.949∠-120°, 2.795∠115.7° μC/m (peak 3.95, 4.17, 3.95 μC/m).
A 400 kV, three phase transmission has flat horizontal configuration with two sub-conductors per bundle. The average ground clearance is 9.81 m and the inter phase spacing is 11.3 m. The radius of each sub-conductor in the bundle is 3.17 cm and the separation between the sub-conductors is 45.72 cm. Calculate the capacitance and charge matrices of this line.
The capacitance matrix is , where is Maxwell's coefficient matrix built with the image method and the equivalent bundle radius. The charge matrix is .
Data
- 400 kV, flat horizontal, m, m (average)
- Sub-conductor radius cm; cm;
- pF/m
Step 1: Equivalent radius
Step 2: Maxwell coefficients ( m)
Step 3: Inverse and capacitance matrix
Step 4: Charge matrix
Balanced phase voltages kV rms at ; :
Peak values: 3.95, 4.17 and 3.95 μC/m.
If the line is transposed (for reference)
| Item | Value |
|---|---|
| 12.04 cm | |
| 11.13 pF/m | |
| 11.31 pF/m | |
| , | −1.46, −0.41 pF/m |
| outer / centre | 2.79 / 2.95 μC/m rms |
Answer: as above; charges ≈ 2.79∠4.3°, 2.95∠−120°, 2.79∠115.7° μC/m rms.
✓ Answer checked by Claude Opus 5.5 (high effort)
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