- 2081 Bhadra · 2+5 marks
Propagation delay; 3-input CMOS NOR
Short answer
Propagation delay is the time between input and output changes measured at 50% points, with tPHL and tPLH; average tpd = (tPHL+tPLH)/2. A 3-input CMOS NOR gate has three PMOS in series and three NMOS in parallel; output is low if any input is high, high only when all inputs are low.
Explain propagation delay. Explain briefly the operation of 3-input CMOS NOR gate with its neat circuit diagram.
Propagation delay
Propagation delay is the time between a change at a gate's input and the resulting change at its output, measured between the 50% points of the input and output edges.
- : delay when the output goes from HIGH to LOW.
- : delay when the output goes from LOW to HIGH.
- Average delay: .
In ____/--------\______
50% 50%
Out -------\________/----
|<->| |<->|
tPHL tPLH
It limits the maximum operating speed (typical: about 10 ns for 74LS TTL, about 8–10 ns for 74HC CMOS).
3-input CMOS NOR gate
It uses 3 PMOS transistors in series between and the output (pull-up network) and 3 NMOS transistors in parallel between the output and ground (pull-down network). Each input A, B, C drives the gates of one PMOS and one NMOS.
VDD
|
A --o| P1
|
B --o| P2
|
C --o| P3
|
+------------- Y = (A+B+C)'
| | |
A --| N1 B --| N2 C --| N3
| | |
GND GND GND
Operation:
- All inputs 0: all three PMOS are ON (gate low) and all NMOS are OFF. The series PMOS chain connects Y to , so Y = 1.
- Any input 1: that input's NMOS turns ON and pulls Y to ground, and its PMOS turns OFF, breaking the pull-up chain. So Y = 0.
- In every case only one network conducts, so no steady current flows from to ground: static power is almost zero.
| A | B | C | P1 P2 P3 | N1 N2 N3 | Y |
|---|---|---|---|---|---|
| 0 | 0 | 0 | ON ON ON | OFF OFF OFF | 1 |
| 0 | 0 | 1 | ON ON OFF | OFF OFF ON | 0 |
| 0 | 1 | 0 | ON OFF ON | OFF ON OFF | 0 |
| 0 | 1 | 1 | ON OFF OFF | OFF ON ON | 0 |
| 1 | 0 | 0 | OFF ON ON | ON OFF OFF | 0 |
| 1 | 0 | 1 | OFF ON OFF | ON OFF ON | 0 |
| 1 | 1 | 0 | OFF OFF ON | ON ON OFF | 0 |
| 1 | 1 | 1 | OFF OFF OFF | ON ON ON | 0 |
Hence .
✓ Answer checked by Claude Opus 5.5 (high effort)
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