Reactance diagram: two generators, two motors, j50 Ω line

Choice of base: 50 MVA (transformer rating) and 220 kV on the line. Then the generator side base is 33 kV (T1 33/220 kV) and the motor side base is 11 kV (T2 220/11 kV). The reactance of T2 is not printed; it is assumed to be 15 % on its own rating (same as T1).

$$Z_{b,line} = \frac{220^2}{50} = 968\ \Omega$$

Per-unit reactances (50 MVA base)

$$\begin{aligned} X_{G1} &= 0.20\times\frac{50}{20}\times\left(\frac{25}{33}\right)^2 = 0.2870\ \text{pu}\\ X_{G2} &= 0.30\times\frac{50}{30}\times\left(\frac{25}{33}\right)^2 = 0.2870\ \text{pu}\\ X_{T1} &= 0.15\ \text{pu}\\ X_{line} &= \frac{50}{968} = 0.0517\ \text{pu}\\ X_{T2} &= 0.15\ \text{pu (assumed)}\\ X_{M1} &= 0.30\times\frac{50}{20} = 0.75\ \text{pu}\\ X_{M2} &= 0.20\times\frac{50}{30} = 0.3333\ \text{pu} \end{aligned}$$

Reactance diagram

        j0.15   j0.0517   j0.15
 +--+---/\/\/---/\/\/-----/\/\/---+------+
 |  |    T1      line      T2     |      |
j0.287 j0.287                  j0.75  j0.3333
 |  |                             |      |
(E1)(E2)                        (Em1)  (Em2)
 |  |                             |      |
 +--+-----------------------------+------+
             reference bus

Answer: On 50 MVA with 33 / 220 / 11 kV bases: $X_{G1} = X_{G2} = 0.287$, $X_{T1} = 0.15$, $X_{line} = 0.0517$, $X_{T2} = 0.15$ (assumed), $X_{M1} = 0.75$, $X_{M2} = 0.333$ pu.