- Asked 4/22
- 2072 Kartik · 20 marks
Design: 150 kVA single phase transformer
Short answer
Core diameter 233.9 mm, limb 198.9×124.0 mm; window 132.6×331.6 mm; yoke depth 198.9 mm, height 205.5 mm. Overall frame 742.6×565.4×198.9 mm. Leakage reactance calculation is not fully provided.
Design a 150 kVA, 50 Hz, 6600/400 V, 1-phase, core type oil immersed natural cooled distribution transformer. Given that: Maximum flux density in core = 1.35 Wb/m²; Current density = 2.75 A/mm²; Core type = cruciform two stepped; Window space factor = 0.27; Stacking factor = 0.9; Ratio of window height to width = 2.5; Take hot rolled steel sheet and area of yoke is 20% greater than area of core; Axial depth of LV winding = 268 mm; Axial depth of HV winding = 276 mm; Inside diameter of LV winding = 255 mm; Radial depth of LV winding = 14 mm; Radial depth of HV winding = 18 mm; Width of insulation between LV and HV = 11 mm; Outside diameter of LV winding = 293 mm; Inside diameter of HV winding = 314 mm; Outside diameter of HV winding = 351 mm. Calculate: i) Dimensions of the core, window and yoke ii) Overall dimensions of the frame iii) Leakage reactance of the transformer iv) Draw overall dimension of the transformer
Standard method (A.K. Sawhney, A Course in Electrical Machine Design): , net core area ratio for the core type, output equation for the window, yoke depth = width of largest stamping. In a single-phase core type transformer half of each winding is on each limb, so the ampere-turns per limb are . is not given; = 0.75 is taken (single-phase core type). Winding data are given: LV 255/293 mm (inside/outside diameter), HV 314/351 mm, radial depths = 14 mm, = 18 mm, gap = 11 mm. Axial length taken as the mean of 268 and 276 mm, = 272 mm.
i) Dimensions of core, window and yoke
Voltage per turn, ( in kVA):
For a cruciform (two-stepped) core with stacking factor 0.9, (standard ratio, Sawhney):
Gross core area m².
Output equation (single phase):
Check: = 234 mm < LV inside diameter 255 mm; HV outside diameter 351 mm < = 367 mm; coil height 276 mm < = 332 mm. The given windings fit.
Yoke:
Yoke area 20% more than core area (hot-rolled steel, to reduce yoke loss and magnetising current). Yoke depth = width of largest stamping:
ii) Overall dimensions of frame
iii) Leakage reactance
Currents: A; A.
Radial depths: mm (LV), mm (HV), duct mm.
Mean lengths of turn:
Leakage reactance (per unit), with per limb and axial winding length mm:
iv) Overall dimensions (sketch)
+-----------------------+ ---
| yoke, Hy = 206 mm | ^
+-----+-----------+-----+ |
|limb | window |limb | H = 743 mm
|d=234| 133 x 332 | | |
+-----+-----------+-----+ |
| yoke | v
+-----------------------+ ---
|<--------- W --------->|
W = 565 mm, D = 367 mm (limb centres)
Depth = 199 mm
Answer: = 234 mm; window 133 × 332 mm; yoke 206 × 199 mm; frame 743 × 565 × 199 mm; leakage reactance ≈ 7.89 Ω referred to HV (2.72%).
✓ Answer checked by Claude Sonnet 5.5
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