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Fault cleared at 30°, Pe = 2.1 sin δ

Short answer

The fault at the generator bus reduces electrical power to zero. Clearing at 30° leaves a very small accelerating area, so the system is stable. The maximum (critical) clearing angle to maintain synchronism is about 81.7°.

A synchronous machine is connected to an infinite bus and the following condition exists during normal operation and the following relationship is valid during that period: Pe = 2.1 sinδ, Pm = 1.0 pu. Following a three phase symmetrical fault at the bus of synchronous generator, and fault is cleared at δ = 30°. Check the stability. Calculate the maximum fault clearing angle so as to maintain synchronism.

Data: Pe=2.1sin⁡δP_e = 2.1\sin\delta (normal and, assuming a temporary fault, also post-fault), Pm=1.0P_m = 1.0 pu. The fault is at the generator bus, so Pe=0P_e = 0 during the fault.

Step 1: Initial and maximum angles

δ0=sin⁡−11.02.1=28.44∘=0.4963 radδmax=180∘−28.44∘=151.56∘\begin{aligned} \delta_0 &= \sin^{-1}\frac{1.0}{2.1} = 28.44^\circ = 0.4963\ \text{rad} \\ \delta_{max} &= 180^\circ - 28.44^\circ = 151.56^\circ \end{aligned}

Step 2: Stability check for clearing at 30∘30^\circ

A1=Pm(δc−δ0)=1.0(0.5236−0.4963)=0.0273 pu⋅radA2,max=2.1(cos⁡30∘−cos⁡151.56∘)−1.0(2.6453−0.5236)=1.5436 pu⋅rad\begin{aligned} A_1 &= P_m(\delta_c - \delta_0) = 1.0(0.5236 - 0.4963) = 0.0273\ \text{pu·rad} \\ A_{2,max} &= 2.1(\cos30^\circ - \cos151.56^\circ) - 1.0(2.6453 - 0.5236) = 1.5436\ \text{pu·rad} \end{aligned}

Since A2,max≫A1A_{2,max} \gg A_1, the system is stable. Clearing occurs only 1.56∘1.56^\circ after the fault.

Step 3: Maximum (critical) clearing angle

With Pmax2=0P_{max2} = 0 and Pmax3=Pmax1P_{max3} = P_{max1}:

cos⁡δcr=(π−2δ0)sin⁡δ0−cos⁡δ0=(3.1416−0.9926)(0.4762)−0.8793=0.1440δcr=81.72∘\begin{aligned} \cos\delta_{cr} &= (\pi - 2\delta_0)\sin\delta_0 - \cos\delta_0 \\ &= (3.1416 - 0.9926)(0.4762) - 0.8793 \\ &= 0.1440 \\ \delta_{cr} &= 81.72^\circ \end{aligned}

Answer: Stable when cleared at 30°; maximum (critical) clearing angle ≈ 81.7°.

✓ Answer checked by Claude Sonnet 5.5

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