- 2072 Kartik · 8 marks
Fault cleared at 30°, Pe = 2.1 sin δ
Short answer
The fault at the generator bus reduces electrical power to zero. Clearing at 30° leaves a very small accelerating area, so the system is stable. The maximum (critical) clearing angle to maintain synchronism is about 81.7°.
A synchronous machine is connected to an infinite bus and the following condition exists during normal operation and the following relationship is valid during that period: Pe = 2.1 sinδ, Pm = 1.0 pu. Following a three phase symmetrical fault at the bus of synchronous generator, and fault is cleared at δ = 30°. Check the stability. Calculate the maximum fault clearing angle so as to maintain synchronism.
Data: (normal and, assuming a temporary fault, also post-fault), pu. The fault is at the generator bus, so during the fault.
Step 1: Initial and maximum angles
Step 2: Stability check for clearing at
Since , the system is stable. Clearing occurs only after the fault.
Step 3: Maximum (critical) clearing angle
With and :
Answer: Stable when cleared at 30°; maximum (critical) clearing angle ≈ 81.7°.
✓ Answer checked by Claude Sonnet 5.5
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