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Settling basin 40 m³/s, 0.15 mm

Short answer

For 40 m³/s trapping particles >0.15 mm (w=0.015 m/s), Camp's v=0.17 m/s, depth 5 m. Three chambers each 16 m wide, turbulence-adjusted length 175 m. Basin: 3 chambers 16 m × 175 m × 5 m settling depth.

Find out the dimension of a settling basin with turbulent flow for a high-head hydropower plant, which utilizes a discharge of 40 m³/s. The sediment particles coarser than 0.15 mm (w = 1.5 cm/s) have to be trapped in the basin. Draw plan and sections (cross and longitudinal) showing major components and flushing arrangement.

Given: design discharge Q=40.0Q=40.0 m³/s; particles of size d≥0.15d\ge 0.15 mm to be trapped, fall velocity w=1.50w=1.50 cm/s =0.0150=0.0150 m/s (given). Turbulence is considered; the plan and both sections are sketched.

Step 1: Horizontal velocity (Camp)

For 0.1<d<10.1<d<1 mm, v=adv=a\sqrt d with a=44a=44 (v in cm/s, d in mm):

v=440.15=17.04 cm/s=0.1704 m/sv=44\sqrt{0.15}=17.04\ \text{cm/s}=0.1704\ \text{m/s}

This is within the usual 0.1-0.4 m/s range, so deposited sediment is not re-suspended.

Step 2: Cross-section and width

Assume a flow depth H=5.0H=5.0 m in the settling zone (sediment storage is extra).

B=QvH=40.00.1704×5.0=46.95 mB=\frac{Q}{vH}=\frac{40.0}{0.1704\times5.0}=46.95\ \text{m}

Provide n=3n=3 chambers so that one can be flushed while the others work: b=B/n=15.65b=B/n=15.65 m each, adopt 16.0 m.

Step 3: Length without turbulence

L0=vHw=0.1704×5.00.0150=56.8 mL_0=\frac{vH}{w}=\frac{0.1704\times5.0}{0.0150}=56.8\ \text{m}

Step 4: Effect of turbulence

Turbulence reduces the effective fall velocity: w′=w−αw'=w-\alpha, with α=0.132 v/H\alpha=0.132\,v/\sqrt{H}.

α=0.132×0.17045.0=0.0101 m/sw′=0.0150−0.0101=0.0049 m/sL=vHw′=0.1704×5.00.0049=172.5 m\begin{aligned} \alpha&=\frac{0.132\times0.1704}{\sqrt{5.0}}=0.0101\ \text{m/s}\\ w'&=0.0150-0.0101=0.0049\ \text{m/s}\\ L&=\frac{vH}{w'}=\frac{0.1704\times5.0}{0.0049}=172.5\ \text{m} \end{aligned}

Adopted dimensions

ItemValue
Flow velocity vv0.170 m/s
Settling depth HH5.0 m (plus about 1.0 m sediment storage in the hopper)
Number of chambers3
Width of each chamber16.0 m
Length of settling zone175 m
Length/width ratio10.9
Inlet transitiongradual, with guide vanes (side slope not steeper than about 1:5)

Total volume of water in the basin ≈42000\approx 42000 m³.

PLAN (flushing gates at the downstream end)
          inlet        settling chambers      outlet
 canal   transition  +=================+   transition
 =====>  \         / |  chamber 1      | \         /===> to
         /  guide  \ +-----------------+ /  weir   \    headrace
 =====>  \  vanes  / |  chamber 2      | \         /
         /         \ +-----------------+ /         \
                     |  chamber 3      |
                     +=================+
  trash-                  |  |  |  flush gates
  rack                    v  v  v  --> flushing channel --> river
LONGITUDINAL SECTION
 inlet          settling zone (depth H)      outlet
 ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~  WL
 \    --->   --->   --->   --->   --->   --->  |
  \  ______________________________________   | weir
   \/   sediment storage / hopper slope 1:30 \__|__ to headrace
          flush gate -> flushing channel -> river
CROSS-SECTION (across the three chambers)
      |<-- 16.0 m -->|<-- 16.0 m -->|<-- 16.0 m -->|
  WL ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~  free board 0.5 m
      |              |              |              |   ^
      |  chamber 1   |  chamber 2   |  chamber 3   |   | H = 5.0 m
      |              |              |              |   v
      \              /\             /\             /   ^ sediment storage
       \____    ____/  \____  ____/  \____    ____/    v (hopper, ~1.0 m)
            |__|            |__|          |__|
       flushing channel under each chamber (to its flush gate)

Flushing arrangement: the floor of each chamber slopes at about 1:30-1:50 to a longitudinal flushing channel with a flushing gate at the downstream end. A flushing velocity of at least 3 m/s is maintained in the channel. The chamber to be flushed is closed at the inlet, drained and flushed to the river, while the other chambers continue to supply the plant.

Answer: 3 chambers, each about 16.0 m wide x 175 m long x 5.0 m deep (settling zone), with v=0.170v=0.170 m/s.

✓ Answer checked by Claude Opus 5.5 (high effort)

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