- 2073 Bhadra · 10 marks
Monthly energy loss in four secondary lines
Short answer
Each line carries 20 kVA, current 28.87 A, resistance 1.5 Ω, peak loss per line I²R=1250 W; total peak loss 5 kW. LLF = 0.3×0.4+0.7×0.4² = 0.232. Monthly energy loss = 5×0.232×720 = 835.2 kWh.
A 11 kV/0.4 kV, 100 kVA distribution transformer has 4 outgoing secondary distribution lines of 1.5 km each. The conductor used has resistance of 1 Ω/km. Determine the monthly energy loss in the lines if the peak demand of the load centre has 80 kVA at the load factor of 0.4. Given LLF = 0.3LF + 0.7LF².
Assumptions: the 80 kVA peak is shared equally by the four lines, load on each line is uniformly distributed, lines are 3-phase at 400 V, and a month = 30 days = 720 h.
Step 1: Current per line
Peak load per line kVA.
Step 2: Peak power loss per line (UDL)
For a uniformly distributed load, 3-phase loss , where per phase.
Total peak loss in 4 lines:
Step 3: Loss load factor
Step 4: Monthly energy loss
Summary
| Quantity | Value |
|---|---|
| Current per line | 28.87 A |
| Peak loss per line | 1.25 kW |
| Total peak loss | 5 kW |
| LLF | 0.232 |
| Monthly loss | 835.2 kWh |
Note: if the whole line load were assumed lumped at the far end, the loss would be three times larger (2505.6 kWh); the uniform-load assumption is the usual one for LT distribution lines serving houses along the route.
Answer: Monthly energy loss in the lines ≈ 835 kWh.
✓ Answer checked by Claude Opus 5.5 (high effort)
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