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Chapter 2 · 4 hours

Engine construction and operation

Practice questions

Practice questions and answers

4 exam-style questions on this chapter, written for this site from the official syllabus. We haven’t found past IOE papers for this subject yet; if you have some, share them in the community.

  • Practice · 6 marks

Explain the working of a four-stroke spark-ignition engine with a neat sketch of the strokes. List the major engine components and state the function of each.

Answer

A four-stroke SI engine completes one power cycle in four piston strokes, i.e. two crankshaft revolutions (720 degrees).

 1 SUCTION    2 COMPRESSION  3 POWER      4 EXHAUST
 IV open      both closed    both closed  EV open
 |  |v| |     |  |  |  |     |  |* |  |   |  |  |^|
 |_ | |_|     |_ |  |_ |     |_ |  |_ |   |_ |  | |
  | |            |||           |||           | |
  piston down    piston up     piston down   piston up
  mixture in     mixture       spark,        burnt gas
                 compressed    expansion     out
  1. Suction: the piston moves from TDC to BDC, the inlet valve is open and a petrol-air mixture from the carburettor or injector enters.
  2. Compression: both valves are closed, the piston rises and compresses the mixture (r = 8-10). Near the end the spark plug ignites it.
  3. Power (expansion): the burning gas pushes the piston down. This is the only stroke giving work.
  4. Exhaust: the exhaust valve opens and the rising piston pushes out the burnt gases.

Major components and functions

ComponentFunction
Cylinder block and linerHolds the cylinder, guides the piston
Cylinder headCloses the cylinder; holds valves, spark plug, combustion chamber
PistonReceives gas force and transmits it to the connecting rod
Piston ringsSeal the gas, control oil film, conduct heat to the wall
Gudgeon pinConnects piston to the small end of the connecting rod
Connecting rodConverts reciprocating motion to the crank
CrankshaftConverts it into rotary motion, delivers torque
FlywheelStores energy, smooths speed fluctuation
Camshaft, valvesOpen and close the inlet and exhaust ports at correct timing
Crankcase / sumpEncloses the crankshaft, stores lubricating oil
GasketsSeal joints against gas, oil and water leakage

Materials: cast iron or aluminium alloy for block and piston, forged steel for the crankshaft and connecting rod.

  • Practice · 5 marks

Differentiate between spark-ignition and compression-ignition engines.

Answer

Both engines are reciprocating internal combustion engines. An SI engine ignites a premixed fuel-air charge with a spark. A CI engine compresses air only and injects fuel into it near the end of compression, when it self-ignites.

BasisSI engineCI engine
Thermodynamic cycleOttoDiesel (or dual)
FuelPetrol (high octane)Diesel (high cetane)
Charge during suctionFuel-air mixtureAir only
Fuel supplyCarburettor or injector in the manifoldInjection pump and injector in the cylinder
IgnitionSpark plug, electrical systemSelf-ignition by hot compressed air
Compression ratio6-10 (limited by knock)14-22
Air-fuel ratioNearly constant (12-18)Varies widely (18-80), quantity governing
Load controlQuality kept, throttle changes quantity of mixtureFuel quantity is changed, air is unthrottled
Thermal efficiency25-30%30-40%
Engine weight and costLighter, cheaperHeavier, costlier (strong build)
SpeedHigh (up to 6000 rpm and above)Lower (up to 4000 rpm)
PollutantsCO, HC, NOx_xNOx_x and particulates (smoke)
KnockPre-ignition and end-gas knockDiesel knock from ignition delay
Fire riskFuel is volatile, higher riskSafer fuel

Use: SI engines in cars and motorcycles; CI engines in trucks, buses, tractors, generators and ships.

  • Practice · 3+3 marks

Explain the working of a two-stroke petrol engine with the help of a sketch. Differentiate between two-stroke and four-stroke engines.

Answer

Two-stroke engine working

A two-stroke engine completes the cycle in two piston strokes (one revolution). It has ports in the cylinder wall instead of valves: the inlet port, the transfer port and the exhaust port. The crankcase acts as a pump.

   spark plug
      |
  +---+---+
  |       |   exhaust port --> E
  |  [P]  |
  |       |   transfer port <-- T
  |_______|
  | crank |<-- inlet port (reed valve) <-- mixture
  +-------+
  1. Upward stroke: the piston covers the transfer and exhaust ports and compresses the charge above it. At the same time the rising piston lowers the crankcase pressure and fresh mixture is drawn in through the inlet port. Near TDC the spark ignites the charge.
  2. Downward stroke: the burning gas expands and pushes the piston down (power). The piston first uncovers the exhaust port, so burnt gas leaves. As it moves further it compresses the mixture in the crankcase and uncovers the transfer port, so the fresh charge flows into the cylinder and pushes out the remaining exhaust gas (scavenging). A deflector on the piston directs the flow upward.

Comparison

BasisTwo-strokeFour-stroke
Power strokeEvery revolutionEvery two revolutions
ValvesPorts, no valve mechanismPoppet valves with cam
Power for same sizeTheoretically double, practically 1.3-1.6 timesLower
Turning momentMore uniform, smaller flywheelLess uniform
Fuel economyPoor, fresh charge escapes with exhaustBetter
Thermal efficiencyLowerHigher
LubricationOil mixed with fuelSeparate sump system
PollutionMore HC and smokeLess
Cost and weightLighter, cheaperHeavier, costlier
UseMopeds, chainsaws, outboardsCars, trucks
  • Practice · 6 marks

A four-cylinder, four-stroke petrol engine has bore 100 mm, stroke 120 mm and compression ratio 9. It runs at 2400 rpm. Calculate (a) the swept volume per cylinder and the engine displacement, (b) the clearance volume of one cylinder, (c) the mean piston speed, and (d) the number of power strokes per second for the engine.

Answer

Given: D=0.1D = 0.1 m, L=0.12L = 0.12 m, z=4z = 4, r=9r = 9, N=2400N = 2400 rpm.

(a) Swept volume and displacement

Vs=π4D2L=π4(0.1)2(0.12)=9.425×10−4 m3=942.5 cm3Vengine=zVs=4×942.5=3770 cm3=3.77 L\begin{aligned} V_s &= \frac{\pi}{4} D^2 L = \frac{\pi}{4}(0.1)^2(0.12) = 9.425 \times 10^{-4}\ \text{m}^3 = 942.5\ \text{cm}^3 \\ V_{engine} &= z V_s = 4 \times 942.5 = 3770\ \text{cm}^3 = 3.77\ \text{L} \end{aligned}

(b) Clearance volume

r=Vc+VsVc⇒Vc=Vsr−1=942.58=117.8 cm3r = \frac{V_c + V_s}{V_c} \Rightarrow V_c = \frac{V_s}{r - 1} = \frac{942.5}{8} = 117.8\ \text{cm}^3

(c) Mean piston speed

The piston travels 2L2L in each revolution:

Sˉp=2LN=2×0.12×240060=9.6 m/s\bar{S}_p = 2LN = 2 \times 0.12 \times \frac{2400}{60} = 9.6\ \text{m/s}

(d) Power strokes per second

In a four-stroke engine each cylinder fires once in two revolutions:

Firing rate=z×N2×60=4×2400120=80 per second\text{Firing rate} = z \times \frac{N}{2 \times 60} = 4 \times \frac{2400}{120} = 80\ \text{per second}

Answer: (a) Vs=942.5V_s = 942.5 cm3^3, displacement 3.77 L; (b) Vc=117.8V_c = 117.8 cm3^3; (c) 9.6 m/s; (d) 80 power strokes per second for the engine (20 per cylinder).

Written from the official syllabus. Questions and answers are written for this site; check them against your class notes.

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