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Chapter 13 · 7 hours

Valuation

IOE past exam questions

Past questions and answers

17 questions set from this chapter, 4 of them more than once; 2 are most repeated (set, or a close variant set, in 3 or more exams). Most repeated first.

  • Most repeated · 3 of 19 exams
  • Asked 3 times
  • 2078 Chaitra · 2 marks
  • 2077 Chaitra · 2 marks
  • 2070 Magh · 3 marks

Explain the different factors (parameters) affecting the value of property.

Answer

The value of a property is not fixed; it depends on many factors.

  1. Location: nearness to the city centre, market, roads, schools, hospitals and public transport raises value; a remote area gives lower value.
  2. Demand and supply: a high demand and a short supply of land or houses increases value.
  3. Utility and purpose: the usefulness of the property, the type of use (residential, commercial or industrial) and permitted land use.
  4. Size, shape and orientation of the plot: a regular shape and frontage on a main road have a higher value.
  5. Physical features: soil, topography, drainage, flood risk, view and environment.
  6. Age, condition and life of the building: the remaining life, quality of construction, maintenance and the depreciation.
  7. Income (rent): the net income that the property gives.
  8. Legal factors: ownership and title, tenancy, restrictions, building bye-laws, FAR, setbacks and taxes.
  9. Services and infrastructure: water, electricity, sewage, road access, telephone and internet.
  10. Economic conditions: inflation, interest rates, availability of loans, and the general economy.
  11. Political and social factors: law and order, development plans, neighbourhood, and future planning.
  12. Disasters and risks: earthquake, flood, landslide.
  13. Scarcity and fashion; amenities such as parking and garden.
  • Most repeated · 3 of 19 exams
  • Asked 3 times
  • 2074 Bhadra · 6 marks
  • 2073 Bhadra · 4 marks
  • 2072 Asoj

What is valuation? Write different methods of valuation of properties.

Answer

Valuation

Valuation is the technique of estimating the fair price or worth of a property (land, building, plant) at a given date, in terms of money, for a stated purpose.

Methods of valuation of properties

  1. Rental (income) method: the net annual income of the property is capitalised using the year's purchase (YP): Value = Net income × YP. Used for rented or income-producing property.
  2. Direct comparison (market) method: the value is found from recent sale prices of similar properties nearby, with adjustments. Mostly used for land and for residential houses.
  3. Cost (replacement) method: value = cost of land + present cost of construction less depreciation. Used for buildings that give no income, such as schools, hospitals, and government buildings.
  4. Plinth area (or cubic content) method: the plinth area × local plinth area rate, less depreciation, plus land value. Used for a quick or approximate valuation.
  5. Development method (residual or belting): for large land to be developed: Value = expected sale value of the developed plots − (development cost + profit). Used for land to be sub-divided.
  6. Profit-based method: for business properties such as hotels, cinema halls and petrol pumps, the net profit is capitalised.
  7. Land and building (belting) method: values land and building separately and adds them; belting divides a deep plot into belts of different rates.
  8. Depreciation methods: straight line, constant percentage (declining), sinking fund and quantity survey methods, used for finding the building value.
  9. Rent-based / lease-hold valuation: value of lease-hold or freehold interests, from lease rent and period.
  • Asked 2 times
  • 2078 Chaitra · 2 marks
  • 2070 Magh · 2+3 marks

Define valuation. Why is valuation done (what are the purposes of valuation)?

Answer

Valuation is the estimation of the fair price or worth of a property at a given date, based on the facts about the property, the market and its income.

Purposes of valuation

  1. Buying and selling: to fix a fair price for the buyer and the seller.
  2. Mortgage and bank loans: banks need the value of the security; loan is given as a percentage (e.g. 50–70%) of the value.
  3. Taxation: for property tax, land revenue (malpot), wealth and capital gains tax, and registration fees.
  4. Rent fixation: to fix a fair rent for the property.
  5. Insurance: to know the value to be insured and to settle claims after a loss.
  6. Compensation for land acquisition: to fix the compensation when the government acquires land for a road, project or public work under the Land Acquisition Act.
  7. Partition and inheritance: to divide a property fairly among co-owners or heirs.
  8. Company accounts: to show the assets in the balance sheet, merger, sale or liquidation.
  9. Betterment, development and urban planning: to estimate the increase in value caused by public works.
  10. Court and legal cases: disputes about sale, rent or compensation.
  11. Investment decisions and valuation of assets for auction.
  • Asked 2 times
  • 2077 Chaitra · 2+6 marks
  • 2070 Bhadra · 5 marks

What are the various factors affecting the value of the property? Work out the valuation of a cinema hall with the following:
a) Cost of land = Rs. 15,00,000 b) Gross income = Rs. 90,00,000 c) Expenses undergone per year to run the Cinema including staff salary, electricity charges, municipal taxes, stationary and printing etc 30% of gross income d) Repair and maintenance of machinery, plant and equipment at 5% of their capital cost which is Rs. 55,00,000 e) Sinking fund for machinery, plant and equipment whose life is estimated at 25 years at 5% after allowing 10% scrap value. f) Insurance premium is 60,000 per annum
Assume year's purchase for 60 years at 8% and redemption of capital at 4% and repair of hall at 2% of gross income.

Answer

Factors affecting the value of property

Location, demand and supply, utility and use, size and shape of the plot, age and condition of the building, income (rent), legal restrictions (zoning, FAR, tenancy), services and infrastructure, economic conditions, risk of disasters, and the general neighbourhood and image.

Valuation of the cinema hall (income / profit method)

Method: The net annual income is found after deducting all outgoings, and capitalised by a dual-rate year's purchase. Land is not redeemed, so interest on the land value is deducted from the net income first; the remainder is the income from the building and plant, which is capitalised and added to the land value. (It is assumed that the sinking fund for the machinery is an outgoing of the annual income.)

Annual outgoings

ItemCalculationRs
Running expenses30% × 90,00,00027,00,000
Repair and maintenance of machinery5% × 55,00,0002,75,000
Repair of hall2% × 90,00,0001,80,000
Insurance premium60,000
Sinking fund for machinerysee below1,03,715
Total outgoings33,18,715

Sinking fund for machinery: depreciable amount = 90% × 55,00,000 = Rs 49,50,000 (10% scrap value is recovered). For n = 25 years and i = 5%:

Isf=S i(1+i)n−1=49,50,000×0.05(1.05)25−1=Rs 1,03,715I_{sf} = \frac{S\,i}{(1+i)^n-1} = \frac{49{,}50{,}000 \times 0.05}{(1.05)^{25}-1} = Rs\ 1{,}03{,}715

Net income

Net income=90,00,000−33,18,715=Rs 56,81,285Interest on land at 8%=0.08×15,00,000=Rs 1,20,000Net income from building=56,81,285−1,20,000=Rs 55,61,285\begin{aligned} \text{Net income} &= 90{,}00{,}000 - 33{,}18{,}715 = Rs\ 56{,}81{,}285 \\ \text{Interest on land at 8\%} &= 0.08 \times 15{,}00{,}000 = Rs\ 1{,}20{,}000 \\ \text{Net income from building} &= 56{,}81{,}285 - 1{,}20{,}000 = Rs\ 55{,}61{,}285 \end{aligned}

Year's purchase (60 years, interest 8%, redemption of capital 4%)

YP=1i+r(1+r)n−1=10.08+0.04(1.04)60−1=11.876YP = \frac{1}{i + \dfrac{r}{(1+r)^n - 1}} = \frac{1}{0.08 + \dfrac{0.04}{(1.04)^{60}-1}} = 11.876

Capitalised value of building and plant

55,61,285×11.876=Rs 6,60,47,07255{,}61{,}285 \times 11.876 = Rs\ 6{,}60{,}47{,}072

Value of the property = building value + land = 6,60,47,072 + 15,00,000 = Rs 6,75,47,072

Answer: Value of the cinema hall is about Rs 6.75 crore (Rs 6,75,47,000).

  • 2075 Bhadra · 6 marks

Calculate the value of a building built 20 years ago having plinth area 500 sqm, constructed in the land of 1000 sqm. Current market value of the land is Rs. 25000 per sqm and rate of building is Rs. 50,000 per sqm. Assume suitable data if necessary.

Similar questions: Value of a 10-year-old building (2071 Bhadra)

Answer

Assumptions: RCC building with a total life of 80 years; scrap value = 10% of the cost; straight-line depreciation (an alternative: sinking fund method). Rate of building (Rs 50,000/m²) is the present cost of construction.

Land = 1000 × 25,000 = Rs 2,50,00,000

Present cost of building = 500 × 50,000 = Rs 2,50,00,000

Depreciation (straight line)

Annual depreciation=C−Sn=0.9×2,50,00,00080=Rs 2,81,250Depreciation for 20 years=20×2,81,250=Rs 56,25,000  (22.5%)\begin{aligned} \text{Annual depreciation} &= \frac{C - S}{n} = \frac{0.9 \times 2{,}50{,}00{,}000}{80} = Rs\ 2{,}81{,}250 \\ \text{Depreciation for 20 years} &= 20 \times 2{,}81{,}250 = Rs\ 56{,}25{,}000 \; (22.5\%) \end{aligned}

Present value of building = 2,50,00,000 − 56,25,000 = Rs 1,93,75,000

Value of property = land + building = 2,50,00,000 + 1,93,75,000 = Rs 4,43,75,000

Answer: Value of the property is about Rs 4.44 crore (Rs 4,43,75,000).

  • 2071 Bhadra · 8 marks

Calculate the value of a building built 10 years ago having a plinth area of 450 sqm, constructed in the land of 1000 sqm. Current market value of land is Rs. 15,000 per sqm and rate of building is Rs. 30,000 per sqm. Assume suitable data if necessary.

Similar questions: Value of a 20-year-old building (2075 Bhadra)

Answer

Assumptions: RCC building with a total life of 80 years; scrap value = 10% of the cost; straight-line depreciation. The rate of Rs 30,000/m² is the present rate of construction.

Land = 1000 × 15,000 = Rs 1,50,00,000

Present cost of building = 450 × 30,000 = Rs 1,35,00,000

Depreciation (straight line)

Annual depreciation=0.9×1,35,00,00080=Rs 1,51,875Depreciation for 10 years=10×1,51,875=Rs 15,18,750  (11.25%)\begin{aligned} \text{Annual depreciation} &= \frac{0.9 \times 1{,}35{,}00{,}000}{80} = Rs\ 1{,}51{,}875 \\ \text{Depreciation for 10 years} &= 10 \times 1{,}51{,}875 = Rs\ 15{,}18{,}750 \; (11.25\%) \end{aligned}

Present value of building = 1,35,00,000 − 15,18,750 = Rs 1,19,81,250

Value of property = land + building = 1,50,00,000 + 1,19,81,250 = Rs 2,69,81,250

Answer: Value of the property is about Rs 2.70 crore (Rs 2,69,81,250).

  • 2073 Magh · 6 marks

Differentiate between cost and value. Explain different factors affecting valuation of property.

Answer

Cost vs value

PointCostValue
MeaningThe amount actually spent to produce or buy a propertyThe present worth or utility of the property in the market, or to the owner
BasisPast expenditure: land, material, labour, overheadFuture benefits, income, market demand
TimeHistorical and fixedChanges with time and market
Depends onRates of material and labourDemand, location, income, utility
RelationValue may be more or less than costValue may be more or less than cost
ExampleA house built for Rs 50 lakhThe same house is worth Rs 80 lakh after the area has developed

Factors affecting the valuation of property

  1. Location and accessibility (road, market, services).
  2. Demand and supply in the market.
  3. Utility and purpose (residential, commercial, industrial use).
  4. Plot size, shape, frontage and orientation.
  5. Age, life, quality and condition of the building (depreciation).
  6. Net income or rent obtained from the property.
  7. Legal and planning factors: title, tenancy, bye-laws, FAR, setbacks, taxes.
  8. Physical features: soil, slope, flood or landslide risk, environment.
  9. Services and amenities: water, power, sewerage, parking.
  10. Economic conditions: interest rates, inflation and availability of loans.
  11. Social and political factors: safety, neighbourhood and development plans.
  • 2070 Bhadra · 3 marks

Explain the situation where the following methods of valuation will be used: (i) Cost based method (ii) Plinth area method (iii) Development method.

Answer

(i) Cost-based method

The value is found as the present cost of construction (less depreciation) plus the value of land. It is used where the property gives no rental income and no sale comparison is available, such as schools, hospitals, government offices, temples, factories and public buildings. It is also used for insurance and the valuation of a new building.

(ii) Plinth area method

The plinth area is multiplied by the local plinth area rate (cost per m² of similar buildings) and depreciated for age, and the land is added. It is used for a quick, approximate valuation when a detailed estimate is not required, e.g. for bank loans, preliminary valuation, compensation or when the drawings are not available, and for buildings of a standard type such as residential houses in a colony.

(iii) Development method

Also known as the residual method. Value of land = expected selling value of the developed plots (or building) − (development cost + builder's profit + interest). It is used for large vacant or underused land that can be developed, such as a plot to be sub-divided into small plots, a housing colony or a commercial complex, and for the valuation of the land that has development potential.

  • 2072 Asoj

Elaborate the concept of depreciation.

Answer

Depreciation is the decrease in the value of a property or asset with the passage of time, caused by ageing, wear and tear, decay, weathering, obsolescence and similar causes. It is the loss in value from the original cost to the scrap or salvage value at the end of the useful life.

Causes

  • Physical wear and tear, use and decay.
  • Weathering and the action of the environment.
  • Obsolescence: old design, change of fashion or technology.
  • Accident, fire or earthquake damage.
  • Lack of maintenance; legal restriction.

Land does not depreciate (except in special cases such as mines); buildings, machinery and equipment do.

Methods of calculating depreciation

  1. Straight line method: the same amount each year. D=C−SnD = \dfrac{C - S}{n}, where C is the cost, S the scrap value and n the life in years.
  2. Constant percentage (declining balance) method: a fixed percentage on the reduced book value each year; the depreciation is larger in the early years.
  3. Sinking fund method: a yearly amount is invested at compound interest so that at the end of the life it equals the (C − S): I=(C−S) i(1+i)n−1I = \dfrac{(C-S)\, i}{(1+i)^n - 1}.
  4. Quantity survey method: the building is divided into parts and the depreciation of each part is estimated separately by its life.
  5. Depreciation by the age and life ratio (value method).

Depreciation is used in valuation to find the present value of a building, in accounts, and for deciding replacement.

  • 2075 Bhadra · 3 marks

Write a short note on scrap value and salvage value.

Answer

Scrap value

Scrap value is the value of the material obtained when a structure or machine is dismantled at the end of its life, valued at its sale rate as junk or waste material (for example old steel, bricks, timber, doors and windows, without any further use as a building). It is generally a small percentage of the original cost (about 10% for buildings, as is often assumed).

Salvage value

Salvage value is the value of a property at the end of its useful life without being dismantled, as it still can be used or sold in its present form (for example an old machine or an old building that can be used for some other purpose). It is generally higher than the scrap value, because the thing is not broken down.

PointScrap valueSalvage value
ConditionAfter dismantling the structureWithout dismantling, in its existing form
Value ofMaterials onlyThe asset as a whole
AmountLowerHigher
ExampleSteel and bricks from a demolished buildingAn old usable building sold as it stands

Both are used in depreciation calculation: depreciable amount = cost − (scrap or salvage value). In valuation, this is usually taken as 10% of the cost for buildings and for machines.

  • 2073 Bhadra · 1+6 marks

Define value of any property and what is to be satisfied by any property to have its value. A person desire to sale his property having details as: Gross rent = Rs 5000 per month, total outgoings = 25% of gross rent, estimated future life = 35 yrs, area of land = 200 m2m^2, estimated value of Land = Rs 2000 per square meter. Determine the fare value of property. Take rate of interest on capital as 10% and rate of redemption of capital as 5%. Assume suitable data, if required.

Answer

Value

The value of a property is its present worth in money, i.e. the price a willing buyer would pay and a willing seller would accept. To have value a property must satisfy: utility (it must be useful), scarcity (limited supply), demand (people want it, backed by purchasing power) and transferability (clear legal title that can be sold or transferred).

Numerical (income method with land and building separated)

Gross rent per year = 5000 × 12 = Rs 60,000 Outgoings = 25% × 60,000 = Rs 15,000 Net income = 60,000 − 15,000 = Rs 45,000

Value of land = 200 × 2000 = Rs 4,00,000 Interest on land at 10% = Rs 40,000 (land does not depreciate, so no redemption) Net income from building = 45,000 − 40,000 = Rs 5,000

Year's purchase (dual rate), i = 10%, sinking fund rate r = 5%, n = 35 years:

YP=1i+r(1+r)n−1=10.10+0.05(1.05)35−1=9.003YP = \frac{1}{i + \dfrac{r}{(1+r)^n - 1}} = \frac{1}{0.10 + \dfrac{0.05}{(1.05)^{35}-1}} = 9.003

Value of building = 5,000 × 9.003 = Rs 45,016

Fair value of property = value of land + value of building = 4,00,000 + 45,016 = Rs 4,45,016

Answer: Fair value of the property is about Rs 4,45,000.

  • 2079 Shrawan · 7 marks

A three storied RCC building with expected 65 years of useful life is built on a plot of land measuring 550 m2m^2. The plinth area of each story is 325 m2m^2 and it fetches a gross rent of 12,000 per month. Calculate the capitalized value of property based on 7.5% net yield. The sinking fund is assumed to be computed in 3% interest rate. The cost of land is Rs. 415 per m2m^2. The plinth area rate of similar building in the vicinity was found to be Rs. 22,500 per m2m^2.

Answer

Assumptions: the gross rent of Rs 12,000 per month is for the whole building; outgoings (municipal tax, repairs, management) are taken as 30% of gross rent (data not given). Interest on land is deducted because land does not wear out. The sinking fund (3%) is used for the redemption of the building cost over 65 years, with a net yield of 7.5%.

Data: Land = 550 m² × 415 = Rs 2,28,250. Total plinth area = 3 × 325 = 975 m².

Net income

Gross rent=12,000×12=Rs 1,44,000Outgoings (30%)=43,200Net income=1,00,800Interest on land at 7.5%=0.075×2,28,250=17,119Net income from building=1,00,800−17,119=83,681\begin{aligned} \text{Gross rent} &= 12{,}000 \times 12 = Rs\ 1{,}44{,}000 \\ \text{Outgoings (30\%)} &= 43{,}200 \\ \text{Net income} &= 1{,}00{,}800 \\ \text{Interest on land at 7.5\%} &= 0.075 \times 2{,}28{,}250 = 17{,}119 \\ \text{Net income from building} &= 1{,}00{,}800 - 17{,}119 = 83{,}681 \end{aligned}

Year's purchase (7.5% net yield, 3% sinking fund, 65 years)

YP=10.075+0.03(1.03)65−1=10.075+0.005146=12.477YP = \frac{1}{0.075 + \dfrac{0.03}{(1.03)^{65}-1}} = \frac{1}{0.075 + 0.005146} = 12.477

Capitalised value

Building=83,681×12.477=Rs 10,44,113Land=Rs 2,28,250Total=Rs 12,72,363\begin{aligned} \text{Building} &= 83{,}681 \times 12.477 = Rs\ 10{,}44{,}113 \\ \text{Land} &= Rs\ 2{,}28{,}250 \\ \text{Total} &= Rs\ 12{,}72{,}363 \end{aligned}

Check: the cost of replacement of the building by the plinth area rate is 975 × 22,500 = Rs 2,19,37,500; this is the upper limit for the construction cost, while the value from the income is controlled by the rent.

Answer: Capitalised value of the property is about Rs 12.72 lakh (Rs 12,72,363).

  • 2079 Jestha · 2+6 marks

Assess fair market value of Tata Sipradi Showroom with following information:
  • Covered land area = 14 aana @ Rs 95,00,000 per aana prevailing rate
  • Built up Showroom = 3355 sqft @ Rs 7200/ sqft of current construction
  • Gross monthly income of Showroom = Rs 80,00,000
  • Municipal Tax = 8% of gross income
  • Monthly Staff Salary and administrative expenses = Rs 2,90,000
  • Advertisement expenses (annual) = Rs 60,00,000
  • Lifting and other installed equipment costing Rs 58,00,000 with estimated life of 15 yrs undertaken for salvage value with 30% estimated salvage at the end with 7% interest per annum
  • Electricity, customer courtesy, solid waste disposal, drinking water supply and other miscellaneous cost = 15% of gross income
  • Insurance premium = Rs 40,00,000
  • Maintenance cost = Rs 50,000 per month
Consider year's purchase for 60 yrs with prevailing interest rate 8% and 10% redemption of capital.

Answer

Method: income (profit) method with dual-rate YP. Net income from the showroom is found after all outgoings, interest on land is deducted (land is not redeemed), the balance is capitalised, and land is added. Insurance and advertisement are taken as annual figures.

Annual gross income = 80,00,000 × 12 = Rs 9,60,00,000

Outgoings

ItemCalculationRs
Municipal tax8% × 9,60,00,00076,80,000
Staff and administration2,90,000 × 1234,80,000
Advertisementannual60,00,000
Electricity and other costs15% × 9,60,00,0001,44,00,000
Insurance premiumannual40,00,000
Maintenance50,000 × 126,00,000
Sinking fund for equipmentsee below1,61,566
Total outgoings3,63,21,566

Sinking fund for equipment: depreciable amount = 70% × 58,00,000 = Rs 40,60,000 (30% salvage), n = 15 years, i = 7%:

I=40,60,000×0.07(1.07)15−1=Rs 1,61,566I = \frac{40{,}60{,}000 \times 0.07}{(1.07)^{15} - 1} = Rs\ 1{,}61{,}566

Net income = 9,60,00,000 − 3,63,21,566 = Rs 5,96,78,434

Land: 14 aana × 95,00,000 = Rs 13,30,00,000 Interest on land at 8% = Rs 1,06,40,000 Net income from building and equipment = 5,96,78,434 − 1,06,40,000 = Rs 4,90,38,434

Year's purchase (60 years, 8%, redemption 10%)

YP=10.08+0.10(1.10)60−1=12.449YP = \frac{1}{0.08 + \dfrac{0.10}{(1.10)^{60}-1}} = 12.449

Capitalised value of building = 4,90,38,434 × 12.449 = Rs 61,04,65,996

Market value = building + land = 61,04,65,996 + 13,30,00,000 = Rs 74,34,65,996

(For comparison, the cost of the building = 3355 × 7200 = Rs 2,41,56,000; the market value is far higher because of the business income.)

Answer: Fair market value of the showroom is about Rs 74.35 crore.

  • 2078 Chaitra · 6 marks

A building having estimated future life of 80 years, fetches a gross annual rent of Rs. 2500 per month. Work out its capitalized value on the basis of 8% net yield. The rate of above building measures 1200 m2m^2 and cost of land is taken at Rs. 100 per m2m^2. The other outgoings are: Repair and maintenance (1/12)th of gross income; Municipal tax and property tax - 25% of gross income; Management and miscellaneous charges - 8% of gross income. The plinth area of a building is 600 m2m^2 and plinth area rate of the building is Rs. 200 per m2m^2.

Answer

Given: Gross rent = 2500 × 12 = Rs 30,000 per year. Net yield = 8%.

Outgoings

  • Repair and maintenance = 1/12 × 30,000 = Rs 2,500
  • Municipal and property tax = 25% × 30,000 = Rs 7,500
  • Management and miscellaneous = 8% × 30,000 = Rs 2,400
  • Total outgoings = Rs 12,400

Net income = 30,000 − 12,400 = Rs 17,600

Year's purchase for a net yield of 8% (single rate, as net yield is given):

YP=1008=12.5YP = \frac{100}{8} = 12.5

Capitalised value

=17,600×12.5=Rs 2,20,000= 17{,}600 \times 12.5 = Rs\ 2{,}20{,}000

Check with cost: land = 1200 × 100 = Rs 1,20,000 and building = 600 × 200 = Rs 1,20,000, total new cost Rs 2,40,000; the capitalised value is below this, which is reasonable for an old building.

Answer: Capitalised value of the property is Rs 2,20,000.

  • 2078 Kartik · 5 marks

A building fetches a gross rent of Rs. 20,000.00 per month. Assuming 25% outgoings for taxes, 20% for repairs and maintenance and 5% to set aside to accumulate the cost of building. Determine its capacitised value at the rate of interest on capital as 6% per annum and 4% on sinking fund installment.

Answer

Given: Gross rent = 20,000 × 12 = Rs 2,40,000 per year.

Outgoings and set aside

  • Taxes 25% = Rs 60,000
  • Repairs and maintenance 20% = Rs 48,000
  • Amount set aside for sinking fund (to replace the building cost), 5% = Rs 12,000
  • Total = Rs 1,20,000

Net income = 2,40,000 − 1,20,000 = Rs 1,20,000

The 5% set-aside accumulates at 4% (sinking fund rate) to replace the cost of the building, so it is deducted from the gross rent as an outgoing. The remaining net income is capitalised at the interest rate of 6%.

YP=1006=16.67YP = \frac{100}{6} = 16.67 Capitalised value=1,20,000×16.67=Rs 20,00,000\text{Capitalised value} = 1{,}20{,}000 \times 16.67 = Rs\ 20{,}00{,}000

Answer: Capitalised value of the property is Rs 20,00,000.

  • 2070 Magh · 8 marks

Workout the value of a Cinema hall from the following data.
i) Cost of Land = Rs 5 crore ii) Gross income = Rs. 2 crore iii) Operating Cost = 40% of Gross income iv) Repair and Maintenance of machineries = 5% of Capital Cost where capital cost is Rs. 40 lakh v) Repair of Hall = 5% of Gross income vi) Sinking fund for machineries whose life is estimated 25 years @ 4% after allowing 10% scrap value. vii) Insurance premium = Rs 50000 per year viii) Assume years purchase for 60 years at 8% and redemption of capital at 10%.

Answer

Method: income method with a dual-rate YP. The interest on land is deducted from the net income (land is not redeemed), the remainder is capitalised, and the land is added.

Annual outgoings

ItemCalculationRs
Operating cost40% × 2,00,00,00080,00,000
Repair and maintenance of machines5% × 40,00,0002,00,000
Repair of hall5% × 2,00,00,00010,00,000
Insurance premium50,000
Sinking fund for machinerysee below86,443
Total outgoings93,36,443

Sinking fund for machinery: depreciable amount = 90% × 40,00,000 = Rs 36,00,000, n = 25 years, i = 4%:

I=36,00,000×0.04(1.04)25−1=Rs 86,443I = \frac{36{,}00{,}000 \times 0.04}{(1.04)^{25}-1} = Rs\ 86{,}443

Net income = 2,00,00,000 − 93,36,443 = Rs 1,06,63,557

Interest on land (8% of 5,00,00,000) = Rs 40,00,000 Net income from building and plant = 1,06,63,557 − 40,00,000 = Rs 66,63,557

Year's purchase (60 years, 8%, redemption 10%):

YP=10.08+0.10(1.10)60−1=12.449YP = \frac{1}{0.08 + \dfrac{0.10}{(1.10)^{60}-1}} = 12.449

Capitalised value of building and plant = 66,63,557 × 12.449 = Rs 8,29,52,790

Value of cinema hall = 8,29,52,790 + 5,00,00,000 = Rs 13,29,52,790

Answer: Value of the cinema hall is about Rs 13.30 crore.

  • 2073 Magh · 6 marks

A building having a cubic content of 1500 m3m^3 was constructed 15 years ago on a free hold land measuring 1000 m2m^2. The building fetched a rent of Rs.12000 per month. What amount will you recommend for advancing a loan on a property against the Mortgage, if the rate of land in that area is Rs. 700 per sq meter? The building has following expenditure headings: Insurance premium Rs. 6000 per annum; Repair and maintenance 8% of gross rent; Taxes 25% of gross rent; Management collection charges 5% of gross rent; Redemption of capital is 5%.

Answer

Assumptions (not given in the question): rate of interest on capital = 8%; the redemption of capital is by a sinking fund at 5%; total life of the building = 60 years, so the remaining life = 60 − 15 = 45 years. For a loan on mortgage, a bank normally advances about two-thirds (66.7%) of the value.

Annual income

Gross rent=12,000×12=Rs 1,44,000\text{Gross rent} = 12{,}000 \times 12 = Rs\ 1{,}44{,}000

Outgoings

  • Insurance = Rs 6,000
  • Repair and maintenance 8% = Rs 11,520
  • Taxes 25% = Rs 36,000
  • Management 5% = Rs 7,200
  • Total = Rs 60,720

Net income = 1,44,000 − 60,720 = Rs 83,280

Land: 1000 × 700 = Rs 7,00,000; interest at 8% = Rs 56,000 Net income from building = 83,280 − 56,000 = Rs 27,280

Year's purchase (8%, sinking fund 5%, 45 years):

YP=10.08+0.05(1.05)45−1=11.593YP = \frac{1}{0.08 + \dfrac{0.05}{(1.05)^{45}-1}} = 11.593

Value of building = 27,280 × 11.593 = Rs 3,16,247 Value of property = 3,16,247 + 7,00,000 = Rs 10,16,247

Loan to be advanced (two-thirds) = 2/3 × 10,16,247 = Rs 6,77,498

Answer: Value of the property is about Rs 10.16 lakh, and a loan of about Rs 6.77 lakh may be recommended.

Questions from Old Question Collection (CE 754) (IOE exam papers from 2064 to 2079 (CE 754 and the older Management of Construction and Maintenance course)). Answers are written for this site; check them against your class notes.

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