Chapter 9 · 8 hours
Limits, Fits and Tolerance
Practice questions
Practice questions and answers
6 exam-style questions on this chapter, written for this site from the official syllabus. We haven’t found past IOE papers for this subject yet; if you have some, share them in the community.
- Practice · 8 marks
Define the following terms with a neat sketch: basic size, actual size, limits of size, deviation (upper and lower), fundamental deviation, tolerance, allowance, hole and shaft, zero line, and clearance and interference.
Answer
+ ------------------ upper limit
| tolerance zone | (upper deviation)
------------------ lower limit
0 ============================ zero line
(basic size) (lower deviation
- if below the line)
Deviations are measured from the zero line: positive above, negative below.
| Term | Meaning |
|---|---|
| Basic (nominal) size | The size from which limits are derived; the theoretical size on the drawing, e.g. 40 mm |
| Actual size | The size found by measurement of the finished part |
| Limits of size | The two extreme permissible sizes: maximum limit and minimum limit |
| Deviation | Algebraic difference between a size and the basic size: upper deviation = max. limit - basic size (ES for hole, es for shaft), lower deviation = min. limit - basic size (EI, ei) |
| Fundamental deviation | The deviation (upper or lower) nearest to the zero line; it fixes the position of the tolerance zone, given by a letter (A to ZC for holes, a to zc for shafts) |
| Tolerance | Difference between the maximum and minimum limits = upper deviation - lower deviation; the permissible variation in size. Size of zone is given by IT grade (IT01 to IT16) |
| Allowance | The intentional difference between the dimensions of the mating parts; the minimum clearance (positive) or the maximum interference (negative). It is the difference between the maximum material limits of hole and shaft |
| Hole / shaft | The internal and external features of a part; a hole is not necessarily round (e.g. a keyway width), a shaft includes any external feature |
| Zero (reference) line | The line representing the basic size; deviations are positive above and negative below |
| Clearance | The positive difference between the hole size and the shaft size (hole larger than shaft) |
| Interference | The negative difference (shaft larger than hole before assembly) |
Tolerance zone: the zone between the upper and lower limits, defined by the grade (size) and the fundamental deviation (position), as in .
- Practice · 8 marks
Explain clearance, transition and interference fits with sketches and give one application of each. Write the hole basis and shaft basis fits in the ISO system with an example for each type.
Answer
A fit is the relationship between a hole and a shaft that are assembled, resulting from the difference of their sizes before assembly.
Types
Clearance Transition Interference
|hole| |hole| |shaft|
| | | | | |
|shaft| |hole|
|shaft| | |
(hole zone (zones (shaft zone
above shaft overlap) above hole)
- Clearance fit: the shaft is always smaller than the hole, so there is always a gap (minimum clearance ). The parts can slide or rotate. Example: shaft in a plain bearing (H7/g6, H8/f7), sliding fit of a piston in a cylinder (running fits).
- Interference (force/press) fit: the shaft is always larger than the hole, so the assembly needs force (pressing, or heating or cooling the parts) and they are fixed together by friction. Example: bush in a housing, gear on a shaft, wheel on an axle (H7/p6, H7/s6).
- Transition fit: the sizes overlap, so, depending on the actual dimensions, there may be a small clearance or a small interference. It is used for accurate location without much load: pulley on shaft with a key, spigot location, coupling hub (H7/k6, H7/n6).
Hole basis and shaft basis
- Hole basis system: the hole has zero lower deviation (H); the fits are obtained by changing the shaft's fundamental deviation. Examples: H7/g6 (clearance), H7/k6 (transition), H7/p6 (interference).
- Shaft basis system: the shaft has zero upper deviation (h); the fits are obtained by changing the hole's deviation. Examples: G7/h6 (clearance), K7/h6 (transition), P7/h6 (interference).
The minimum clearance is the difference between the lower limit of hole and the upper limit of shaft; the maximum clearance is the difference between the upper limit of hole and the lower limit of shaft.
- Practice · 5 marks
Differentiate between the hole basis system and the shaft basis system of fits. Why is the hole basis system more commonly used?
Answer
In the hole basis system the basic size is the minimum limit (lower limit) of the hole, so the lower deviation of the hole is zero (letter H). Different fits are obtained by varying the size of the shaft. In the shaft basis system the basic size is the maximum limit of the shaft, so the upper deviation of the shaft is zero (letter h). Different fits are obtained by varying the size of the hole.
| Point | Hole basis | Shaft basis |
|---|---|---|
| Fixed member | Hole (H, lower deviation 0) | Shaft (h, upper deviation 0) |
| Varying member | Shaft | Hole |
| Example | 40 H7/g6, H7/k6, H7/p6 | 40 G7/h6, K7/h6, P7/h6 |
| Tools for the fixed part | Standard reamers, broaches and plug gauges are limited in number | Standard shafts, ground bars |
| Cost | Lower for general use | Higher: many hole sizes need many reamers |
| Used | Machine tools, general engineering | Where long drawn or ground bars of a standard size carry many parts, e.g. line shafting, textile and agricultural machines |
Why hole basis is preferred
- Holes are made by drills, reamers, boring and broaches whose sizes are fixed; one reamer size of H7 covers all fits.
- Shafts are easily turned and ground to any size, so the changing member is the cheaper one to change.
- Fewer tools and gauges are needed, so the cost of production and inspection is lower.
The shaft basis is used when a single shaft carries several parts with different fits (for example a bar on which several bearings, collars, and pulleys are fitted) because cutting steps on a shaft would weaken it and cost more.
- Practice · 5 marks
Differentiate between unilateral and bilateral tolerance with examples and state when each is used. Convert the bilateral dimension mm into a unilateral form with the same limits, and state the type of tolerance in mm.
Answer
| Point | Unilateral | Bilateral |
|---|---|---|
| Definition | Tolerance on one side of the basic size only | Tolerance on both sides of the basic size |
| Example | or | or |
| Basic size | One of the limits | Lies between the limits |
| Use | Interchangeable parts, hole and shaft systems (the basic size is the datum of fits); allows fixed tools to be used and the tolerance to be changed without changing the datum | Where variation on either side is acceptable, e.g. positions of holes, centre distances, and in machining and assembly dimensions |
| Gauging | Easier to adjust setting and to change tolerance | Symmetrical; the setting at the mean size |
Conversion: the limits of are and mm; the total tolerance is mm. As a unilateral dimension with the same limits:
Type of : both deviations are positive, so the limits are and mm and the basic size 60 mm lies outside the tolerance zone. It is a unilateral tolerance (both limits are on the same side of the basic size), with a tolerance of mm.
- Practice · 8 marks
For a 40 mm H7/g6 fit calculate the limits of the hole and the shaft, the tolerances, the maximum and minimum clearance, and state the type of fit. Use the standard tolerance unit (m, in mm), IT6 , IT7 and the fundamental deviation for shaft 'g' (m); is the geometric mean of the diameter step 30 to 50 mm. Round tolerances and deviation to the nearest standard value.
Answer
Step 1: diameter step
Step 2: tolerance unit
- IT7 m, standard value 25 m
- IT6 m, standard value 16 m
Step 3: fundamental deviation of shaft g
Step 4: limits
Hole 40 H7 (lower deviation zero):
- Lower limit mm
- Upper limit mm
- Tolerance mm
Shaft 40 g6 (upper deviation mm):
- Upper limit mm
- Lower limit mm
- Tolerance mm
Step 5: clearances
Check: .
Both clearances are positive, so this is a clearance fit (close running or sliding fit).
Answer: hole 40.000 to 40.025 mm; shaft 39.975 to 39.991 mm; = 0.050 mm, = 0.009 mm; clearance fit.
- Practice · 6 marks
The limits of size of three hole-shaft pairs are given below. For each, find the tolerances, the maximum and minimum clearance (or interference), and state the type of fit. (a) Hole 30.000 to 30.021 mm; shaft 29.967 to 29.980 mm. (b) Hole 50.000 to 50.025 mm; shaft 50.002 to 50.018 mm. (c) Hole 25.000 to 25.021 mm; shaft 25.035 to 25.048 mm.
Answer
Use: hole max shaft min; hole min shaft max. A negative value is interference.
| (a) | (b) | (c) | |
|---|---|---|---|
| Hole tolerance | |||
| Shaft tolerance | |||
| = hole max - shaft min | |||
| = hole min - shaft max | |||
| Fit type | Clearance | Transition | Interference |
Results
- (a) Clearance fit: the clearance is always between 0.020 mm and 0.054 mm. The shaft is always smaller than the hole, so it is a running fit (like H7/f7).
- (b) Transition fit: the maximum clearance is 0.023 mm and the maximum interference is 0.018 mm. Depending on actual sizes it may be a clearance or an interference. Used for accurate location (like H7/k6).
- (c) Interference fit: the minimum interference is 0.014 mm and the maximum is 0.048 mm. Always a press fit (like H7/s6).
The three pairs are on the hole basis, as the hole lower limit equals the basic size in all of them (lower deviation zero).
Answer: (a) clearance, 0.020 to 0.054 mm; (b) transition, +0.023 to -0.018 mm; (c) interference, 0.014 to 0.048 mm.
Written from the official syllabus. Questions and answers are written for this site; check them against your class notes.
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