Chapter 3 · 4 hours
Static Characteristics of Measurement System
Practice questions
Practice questions and answers
4 exam-style questions on this chapter, written for this site from the official syllabus. We haven’t found past IOE papers for this subject yet; if you have some, share them in the community.
- Practice · 3+3 marks
(a) Differentiate between accuracy and precision with a suitable example.
(b) Define sensitivity, threshold, resolution and tolerance of a measuring instrument.
Answer
(a) Accuracy and precision
Accuracy is the closeness of a measured value to the true value. Precision is the closeness of repeated readings of the same quantity to each other (repeatability).
| Point | Accuracy | Precision |
|---|---|---|
| Meaning | Nearness to true value | Nearness of readings to one another |
| Error type | Affected by systematic error | Affected by random error |
| Expressed as | % of full scale or % of reading | Standard deviation, repeatability |
| Improved by | Calibration | Better design, averaging |
| Possible alone? | Average of scattered readings can be accurate | Readings can be precise yet wrong |
Example: a target shot. Shots all clustered far from the bullseye are precise but not accurate. Shots scattered evenly around the bullseye are accurate on average but not precise. A voltmeter reading 4.98, 4.99, 4.98 V for a true 5.50 V is precise but inaccurate.
(b) Definitions
- Sensitivity: ratio of the change in output to the change in input, (slope of the calibration curve). Example: 5 mV/bar.
- Threshold: the smallest input change from zero that produces a detectable output.
- Resolution: the smallest change in input (from a non-zero value) that the instrument can detect. For a digital meter it is one least-count digit.
- Tolerance: the maximum permitted departure from a specified value, usually given as value or ; it is the permissible error, not the instrument's inherent accuracy.
- Practice · 6 marks
Write short notes on (a) hysteresis, (b) dead space, and (c) linearity of a measuring instrument. Explain the terms independent, terminal and least-squares linearity with a sketch.
Answer
(a) Hysteresis
Hysteresis is the difference in output for the same input depending on whether the input is increasing or decreasing. It is caused by friction, backlash, elastic after-effect and magnetic hysteresis. It is quoted as the maximum difference between the up-scale and down-scale outputs, as a percentage of full-scale output.
Output | ___--- up
| _--/ _--- down
| _-/ _--/ <- hysteresis band
| _/ _-/
| /_-/
+------------------ Input
(b) Dead space
Dead space (dead band) is the range of input over which there is no change in output, even though the input changes, usually because of backlash, friction or a preload. The instrument responds only after the input leaves this band. Hysteresis is not the same: it exists at all points, while dead space is a flat zone.
(c) Linearity
Linearity is the closeness of the calibration curve to a straight line. Nonlinearity is the maximum deviation from the reference line, expressed as % of full-scale output. The reference line can be defined in three ways.
- Terminal (end-point) linearity: a line joining the zero and full-scale points. It is simple but gives large deviations.
- Independent linearity: two parallel lines enclose the curve with minimum spacing; the line midway is the reference. Nonlinearity is half the spacing.
- Least-squares linearity: the line that minimizes . It gives the smallest overall error and is the most used.
Output | . . . actual curve
| . / <- best straight line
| . /
| ./
+----------------- Input
- Practice · 8 marks
A pressure transducer was calibrated with the following data.
Pressure (bar) 0 2 4 6 8 10 Output (V) 0.02 0.98 2.05 3.00 3.98 5.01
Fit the least-squares straight line, find the sensitivity and the zero offset, and calculate the maximum nonlinearity as a percentage of full-scale output (FSO).
Answer
Method: fit by least squares, then find the largest difference between data and the line.
Least-squares fit
For points: , , , (units bar, V).
| x (bar) | y (V) | Fitted (V) | Deviation (V) |
|---|---|---|---|
| 0 | 0.02 | 0.0138 | +0.0062 |
| 2 | 0.98 | 1.0110 | -0.0310 |
| 4 | 2.05 | 2.0082 | +0.0419 |
| 6 | 3.00 | 3.0053 | -0.0052 |
| 8 | 3.98 | 4.0024 | -0.0224 |
| 10 | 5.01 | 4.9996 | +0.0105 |
So the line is .
Nonlinearity
Maximum deviation V at 4 bar.
Full-scale output V.
Answer: sensitivity V/bar, zero offset V, maximum nonlinearity of FSO.
- Practice · 2+2 marks
(a) Explain sensitivity to disturbance, with zero drift and sensitivity drift (scale-factor drift) as the two forms.
(b) A pressure transducer has a sensitivity of 5 mV/bar at 20 C. The zero drift is 0.2 mV/C and the sensitivity drift is 0.01 mV/bar per C. Find the output when it reads 6 bar at 40 C.
Answer
(a) Sensitivity to disturbance
Environmental inputs such as ambient temperature, supply voltage, vibration or humidity can change the output of an instrument even when the measurand is constant. These are called disturbances (interfering and modifying inputs). Two effects are described.
- Zero drift (zero shift): the whole calibration line moves up or down by a constant amount, so the output at zero input changes. It is quoted per unit disturbance, e.g. mV/C.
- Sensitivity drift (scale-factor drift): the slope of the calibration line changes, so the error grows with input. Quoted as, e.g., (mV/bar) per C.
Output | / <- sensitivity drift (slope change)
| //
| ///_/ <- zero drift (parallel shift)
|_/_/
+---------------- Input
(b) Numerical
Temperature change C.
Nominal output mV.
Zero drift mV.
Sensitivity drift effect mV.
Answer: output mV, an error of mV (17%) due to temperature.
Written from the official syllabus. Questions and answers are written for this site; check them against your class notes.
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