Chapter 3 · 4 hours
Soil Identifications and Classification
IOE past exam questions
Past questions and answers
24 questions set from this chapter, 6 of them more than once; 3 are most repeated (set, or a close variant set, in 3 or more exams). Most repeated first.
- Most repeated · 4 of 12 exams
- Asked 4 times
- 2073 Magh · 5 marks
- 2074 Bhadra · 1 mark
- 2077 Chaitra · 4 marks
- 2078 Poush · 2 marks
Describe the field identification tests used to identify fine-grained soils and to distinguish between clay and silt.
Answer
Field identification tests are quick hand tests on a small moist sample, used to tell fine-grained soils apart without laboratory equipment. They use the dry strength, dilatancy, toughness, plasticity, and appearance of the soil. They are carried out on the fraction finer than 0.425 mm (No. 40 sieve).
1. Dilatancy (shaking) test
Make a pat of moist soil (soft putty consistency) and shake it in the palm. Then squeeze it.
- Silt: water rises quickly to the surface giving a shiny look; it disappears on squeezing (rapid reaction).
- Clay: no change (no reaction).
2. Dry strength (crushing) test
Dry a moulded pat and crush it between the fingers.
- Clay: high dry strength, cannot be crushed easily.
- Silt: low dry strength, crumbles easily to powder.
3. Toughness (thread) test
Roll the soil into a thread about 3 mm diameter, fold and re-roll repeatedly until it crumbles at the plastic limit.
- Clay: strong, stiff thread; tough lump after crumbling.
- Silt: weak thread, soft lump, loses coherence quickly.
4. Plasticity / sticking
Clay is plastic and sticky in hand and cannot be easily washed off; silt feels gritty or floury and washes off easily.
5. Other tests
- Visual and touch: clay feels smooth, silt feels slightly gritty on the teeth.
- Shine test: a cut surface of clay shows a shiny surface when scratched; silt stays dull.
- Sedimentation test: shaken in water, silt settles in 30 - 60 seconds, clay stays in suspension for hours.
| Test | Silt | Clay |
|---|---|---|
| Dilatancy | Rapid | None |
| Dry strength | Low | High to very high |
| Toughness | Low | Medium to high |
| Feel | Gritty/floury | Smooth, sticky |
- Most repeated · 3 of 12 exams
- Asked 3 times
- 2079 Jestha · 2 marks
- 2078 Chaitra · 3 marks
- 2078 Poush · 2 marks
What is the purpose (importance) of soil classification?
Answer
Soil classification groups soils of similar engineering behaviour into the same class, using simple index properties (grain size and plasticity).
Purposes and importance
- Common language: engineers share a standard name and symbol for a soil (e.g. SC, CH), so reports are understood by everyone.
- Prediction of behaviour: from the group, the probable strength, compressibility, permeability, compaction and swelling can be estimated.
- Preliminary design: gives approximate design values (bearing capacity, subgrade suitability, frost susceptibility) before costly tests are done.
- Selection of construction material: helps to select borrow soil for embankments, dam cores, and road subgrades.
- Site investigation planning: helps decide what tests are needed.
- Use of past experience: data from similar soils elsewhere can be applied.
- Economy: avoids costly lab tests for small or simple projects.
- Correlation: index properties correlate with engineering properties (e.g. with compression index).
- Most repeated · 3 of 12 exams
- Asked 3 times
- 2074 Bhadra · 2 marks
- 2076 Baisakh · 1 mark
- 2078 Poush · 1 mark
What are the common (important engineering) soil classification systems? Write down the types of soil classification.
Answer
Types of soil classification
- Textural (particle size) classification: based on percent of sand, silt and clay, e.g. USDA/triangular chart, MIT system.
- Classification based on plasticity and size (engineering classification): Unified Soil Classification System (USCS), Indian Standard Soil Classification System (ISSCS, IS 1498), AASHTO, Casagrande's airfield system.
- Classification based on origin and genesis: residual, transported, alluvial, etc.
- Classification for specific purposes: AASHTO for highways, Federal Aviation Administration (FAA) for airfields, and agricultural (pedological) classification.
Important engineering systems
| System | Main use |
|---|---|
| Unified (USCS) | General engineering, foundations, dams |
| IS Soil Classification (IS 1498) | Indian/Nepali practice |
| AASHTO | Highways, subgrade |
| Textural (MIT, USDA) | Based on grain size only |
- Asked 2 times
- 2079 Asoj · 3 marks
- 2073 Magh · 3 marks
Describe the soil classification according to the MIT classification system, giving the grain size ranges of the different soil types.
Answer
The MIT (Massachusetts Institute of Technology) classification is a textural system that names a soil only by its particle size. It was proposed by Gilboy and Casagrande and later adopted by the British Standards. The soil is divided into gravel, sand, silt and clay.
| Soil type | Particle size (mm) |
|---|---|
| Gravel | > 2.0 |
| Coarse sand | 2.0 - 0.6 |
| Medium sand | 0.6 - 0.2 |
| Fine sand | 0.2 - 0.06 |
| Coarse silt | 0.06 - 0.02 |
| Medium silt | 0.02 - 0.006 |
| Fine silt | 0.006 - 0.002 |
| Clay | < 0.002 |
- The system has the same limits for sand, silt, and clay as the International classification, except for the sand boundaries.
- The mixture is named by its major fraction, for example "silty sand" or "sandy clay".
- Limitation: it ignores plasticity, so soils with the same size distribution can behave very differently.
- Asked 2 times
- 2078 Poush · 2 marks
- 2076 Baisakh · 1 mark
What are the basic requirements of soil classification?
Answer
A good soil classification system should:
- Be simple, easy to learn and to use, with a few clear groups.
- Use standard index tests that are quick and cheap (grain size, Atterberg limits).
- Place soils of similar engineering behaviour in the same group.
- Use clear boundaries so that different engineers get the same classification.
- Use a systematic nomenclature (symbols) that conveys properties of the soil.
- Be accepted widely and linked to experience, so that behaviour can be predicted.
- Cover all types of soil, coarse and fine, organic and inorganic.
- Asked 2 times
- 2077 Chaitra · 2 marks
- 2074 Bhadra · 3 marks
Draw neatly the plasticity chart (IS / USCS) and label the group symbols of the various soil regions in the chart.
Answer
The plasticity chart (Casagrande) plots plasticity index (vertical) against liquid limit (horizontal). It is used for the fine-grained fraction (passing 75 micron).
Lines
- A-line: , separating clays (above) from silts and organic soils (below).
- U-line: , the upper limit of natural soils.
- Vertical line at (USCS) separates low and high plasticity. IS adds for low (L), medium (I), and high (H) plasticity.
Ip
60| /U
50| CH /
40| /
30| CI CH / A
20| CL / /
10| CL-ML / MH & OH
7|--/--------/
4|ML & OL MI MH & OH
0+---+---+---+---+---+--- wL
0 10 20 35 50 60 70 80
Group symbols
| Region | Symbol | Name |
|---|---|---|
| Above A-line, (IS) / 50 (USCS) | CL | Inorganic clay of low plasticity |
| Above A-line, (IS) | CI | Clay of medium plasticity |
| Above A-line, | CH | Inorganic clay of high plasticity |
| Below A-line, / 50 | ML (OL) | Silt (organic silt) of low plasticity |
| Below A-line, | MI (OI) | Silt of medium plasticity |
| Below A-line, | MH (OH) | Silt of high plasticity / organic clay |
| Hatched zone, 4 - 7 above A-line | CL-ML | Silty clay |
- 2078 Baisakh · 2 marks
Name the tests generally done to identify sandy soil and clayey soil in the field.
Answer
Sandy soil
- Visual and touch: coarse, gritty, grains visible to the naked eye.
- Dry strength test: crumbles easily; no strength.
- Dilatancy test: quick reaction with water rising to the surface (for fine sand).
- Sedimentation test: settles in less than a minute.
- Does not form a thread (no plasticity).
Clayey soil
- Dry strength test: high strength; hard to crush.
- Dilatancy test: no or very slow reaction.
- Toughness (thread) test: rolls into 3 mm thread; tough and cohesive.
- Stickiness/shine test: sticky, smooth, with shiny cut surface.
- Sedimentation test: stays in suspension for a long time.
- 2078 Baisakh · 2 marks
Name the soil classification systems which use both particle size and plasticity characteristics of soil.
Answer
Soil classification systems that use both particle size and plasticity are:
- Unified Soil Classification System (USCS) - Casagrande.
- Indian Standard Soil Classification System (ISSCS) - IS 1498.
- AASHTO classification system - uses sieve analysis and Atterberg limits (also gives a group index).
- Casagrande's airfield classification (the origin of the USCS).
- British Soil Classification System (BSCS).
- 2075 Bhadra · 3 marks
Write down the names of soil classification systems based on particle size and plasticity of soil. Define the plasticity chart of a soil based on ISSCS (Indian Standard Soil Classification System).
Answer
Systems based on particle size and plasticity
- Unified Soil Classification System (USCS)
- Indian Standard Soil Classification System (ISSCS, IS 1498)
- AASHTO classification system
- British Soil Classification System (BSCS)
Plasticity chart of ISSCS
The plasticity chart is a graph of plasticity index (y-axis) against liquid limit (x-axis), used for classifying the fine-grained soils (passing 75 micron).
- A-line: . Inorganic clays (C) lie above it; silts (M) and organic soils (O) lie below it.
- Vertical lines at and divide the soils into low (L, ), intermediate (I, 35 - 50) and high plasticity (H, ).
- The hatched area above the A-line with between 4 and 7 gives dual symbol CL-ML.
The resulting groups are CL, CI, CH (clays), ML, MI, MH (silts), and OL, OI, OH (organic soils).
- 2078 Poush · 3 marks
Describe in detail one important engineering soil classification system, clearly bringing out its limitations.
Answer
Unified Soil Classification System (USCS)
Proposed by A. Casagrande (1948) and adopted by the US Army Corps of Engineers and Bureau of Reclamation; it is the most widely used engineering system. Soil is classified by grain size distribution and plasticity.
Procedure
- Coarse-grained if more than 50% is retained on the 75 micron (No. 200) sieve; fine-grained if 50% or more passes.
- Coarse-grained: G (gravel) if more than half of the coarse fraction is retained on 4.75 mm sieve, else S (sand).
- Fines < 5%: GW, GP, SW, SP. Well graded if (gravel) or (sand) and .
- Fines > 12%: GM, GC, SM, SC using Atterberg limits (A-line).
- Fines 5 - 12%: dual symbols (e.g. GW-GC).
- Fine-grained: use the plasticity chart. Below A-line: M (silt); above: C (clay); organic: O; gives L, gives H: ML, CL, OL, MH, CH, OH. Pt is peat.
| Major division | Groups |
|---|---|
| Gravels | GW, GP, GM, GC |
| Sands | SW, SP, SM, SC |
| Silts and clays, | ML, CL, OL |
| Silts and clays, | MH, CH, OH |
| Highly organic | Pt |
Limitations
- Only the fraction smaller than 75 mm is considered; cobbles and boulders are not classified.
- Gives no direct measure of engineering properties such as strength or compressibility.
- Dual symbols and borderline cases cause ambiguity.
- Particle shape, density and structure (in-situ condition) are not considered.
- Single boundary at gives no medium plasticity class (the IS system corrects this).
- Based on the remoulded soil, so natural structure effects are ignored.
- 2078 Poush · 2 marks
Point out similarities and differences between the USCS system and the AASHTO system of soil classification.
Answer
Both classify soil using grain size distribution and Atterberg limits.
Similarities
- Both use sieve analysis and liquid and plastic limits.
- Both are based on the fraction of soil finer than 75 mm.
- Both separate coarse-grained from fine-grained soil using the 75 micron sieve, though at different percentages.
- Both are used widely in engineering practice.
Differences
| Basis | USCS | AASHTO |
|---|---|---|
| Purpose | General engineering | Highway subgrade |
| Coarse/fine boundary | 50% passing 75 micron | 35% passing 75 micron |
| Symbols | Letters (GW, SC, CH) | A-1 to A-7 with group index |
| Plasticity chart | Used (A-line) | Not used |
| Organic soil | Separate OL, OH, Pt | No separate group |
| Group index | Not used | Used to rate subgrade |
| Rating | Order of groups not numerical | Subgrade quality worsens from A-1 to A-7 |
- 2074 Bhadra · 2 marks
For finding the suitability of soils as subgrade for highways, which soil classification is generally used? Write down the name of each group according to that classification. Show the general rating of those groups as a suitability of subgrade.
Answer
The AASHTO classification system (American Association of State Highway and Transportation Officials) is generally used for rating soil as a highway subgrade.
Groups
Granular materials (35% or less passing 75 micron):
- A-1-a: stone fragments, gravel and sand
- A-1-b: stone fragments, gravel and sand
- A-3: fine sand
- A-2-4, A-2-5, A-2-6, A-2-7: silty or clayey gravel and sand
Silt-clay materials (more than 35% passing 75 micron):
- A-4: silty soils
- A-5: elastic (micaceous or diatomaceous) silty soils
- A-6: clayey soils
- A-7-5, A-7-6: elastic clayey soils (A-7-5 moderate plasticity; A-7-6 high change in volume)
General rating as subgrade
| Group | Rating |
|---|---|
| A-1-a, A-1-b | Excellent to good |
| A-3 | Excellent to good |
| A-2 | Excellent to good (A-2-6, A-2-7 fair) |
| A-4, A-5 | Fair to poor |
| A-6 | Fair to poor |
| A-7-5, A-7-6 | Fair to poor (poor, very poor in swelling) |
Within each group, a lower group index (0 for best soils) indicates a better subgrade.
- 2075 Baisakh · 2 marks
How is the plasticity chart useful for classifying fine-grained soils?
Answer
The plasticity chart plots plasticity index () against liquid limit () and has the A-line () and a vertical line at .
It is useful because:
- It classifies fine-grained soils (more than 50% passing 75 micron) into clay (C), silt (M) or organic (O) by position relative to the A-line (above = clay; below = silt/organic).
- It divides them into low () and high () plasticity (L or H), giving CL, CH, ML, MH, OL, OH.
- The hatched zone above A-line with to 7 gives the borderline class CL-ML.
- It is also used to classify the fines of coarse-grained soils with more than 12% fines (GM, GC, SM, SC).
- It indicates relative engineering behaviour: compressibility, swelling and strength rise with position upward and right.
- 2079 Asoj · 5 marks
The sieve analysis of a soil gave the following results:
% passing 75 micron sieve = 4
% retained on 4.75 mm sieve = 35
Coefficient of curvature = 2
Coefficient of uniformity = 5
Classify the soil according to the USCS system.
Answer
Given
Passing 75 micron ; retained on 4.75 mm ; ; .
Step 1: Coarse or fine?
Only 4% passes 75 micron, so more than 50% is retained: coarse-grained.
Step 2: Gravel or sand?
- Gravel (retained on 4.75 mm)
- Sand
Coarse fraction ; gravel is of it, less than half. So the soil is a sand (S).
Step 3: Fines content
4% is less than 5%, so only the grading is needed (symbols SW or SP).
Step 4: Grading
For well-graded sand: and .
- satisfies the condition.
- fails.
The soil is not well graded.
Answer: SP, poorly graded sand (with gravel).
- 2079 Jestha · 6 marks
A soil sample on laboratory test gives the following results. Classify the soil and give its symbol as per the USCS classification system.
Passing through 75-micron sieve = 8%
Passing through 4.75 mm sieve = 42%
Coefficient of uniformity = 6
Coefficient of curvature = 4
Plasticity index = 4
Answer
Given
Passing 75 micron ; passing 4.75 mm ; ; ; .
Step 1: Coarse or fine?
92% is retained on the 75 micron sieve, so the soil is coarse-grained.
Step 2: Gravel or sand?
- Retained on 4.75 mm (gravel)
- Sand
Gravel is more than half of the coarse fraction (), so the soil is gravel (G).
Step 3: Fines content
8% is between 5% and 12%, so a dual symbol is required.
Step 4: Grading
For well-graded gravel: and .
- : OK
- is greater than 3: fails
So the gravel is poorly graded (GP).
Step 5: Nature of fines
is at the lower limit of the hatched zone. Since is not above 4 (the fines plot as silt, ML or CL-ML), the fines are taken as silty (M).
Answer: GP-GM, poorly graded gravel with silt and sand.
- 2078 Chaitra · 5 marks
Classify the soils A and B with the properties shown below according to the unified soil classification system.
Soil (%) (%) % passing through 4.75 mm sieve % passing through 75 µ sieve A 45 29 100 59 B 55 15 100 85
Answer
Both soils have 59% and 85% passing the 75 micron sieve (more than 50%), so both are fine-grained. Use the plasticity chart with the A-line .
Soil A: ,
: the soil lies above the A-line (clay), and (low plasticity).
Soil A: CL, inorganic clay of low plasticity (lean clay). It is also sandy, since 41% is coarse.
Soil B: ,
: the soil lies below the A-line (silt), and (high plasticity).
Soil B: MH, inorganic silt of high plasticity (elastic silt).
(Both are taken as inorganic, since no data on organic content is given.)
- 2078 Poush · 4 marks
Classify the given soil according to the USCS classification system.
% of soil passing through sieve no. 200 (0.075 mm) = 40%
% of soil retained in sieve no. 4 (4.75 mm sieve) = 55%
The grading characteristics of soil were: = 1.2 mm, = 3.8 mm, = 2.6 mm
Answer
Given
Passing 75 micron (No. 200) ; retained on 4.75 mm (No. 4) ; mm, mm, mm.
Step 1: Coarse or fine?
60% is retained on the 75 micron sieve, so the soil is coarse-grained.
Step 2: Gravel or sand?
- Gravel
- Sand
Gravel is more than half of the coarse fraction, so the soil is gravel (G).
Step 3: Grading parameters
The gravel fraction is poorly graded (), but is in the range 1 - 3.
Step 4: Fines content
The fines are 40%, which is more than 12%. So the grading is not used; the symbol depends on the type of fines (GM or GC) found from and using the A-line. The plasticity data are not given.
Answer: a gravel with fines, GM or GC (silty or clayey gravel). If the fines are silty the symbol is GM; if the fines plot above the A-line with it is GC. The grading (, ) of the coarse fraction is poor.
- 2078 Baisakh · 4 marks
Classify the following soil if the test results obtained from sieve analysis and consistency tests are given below: Percentage passing No. 4 sieve (4.75 mm) = 70%, percentage passing No. 200 sieve (0.075 mm) = 30%; liquid limit = 33% and plastic limit = 11%.
Answer
Given
Passing No. 4 ; passing No. 200 ; ; .
Step 1: Coarse or fine?
70% is retained on the No. 200 sieve, so the soil is coarse-grained.
Step 2: Gravel or sand?
- Gravel (retained on No. 4)
- Sand
Gravel is 30/70 = 43% of the coarse fraction (less than half), so the soil is sand (S).
Step 3: Fines
Fines are 30% (more than 12%), so classify the fines with the plasticity chart.
is above the A-line and greater than 7: clayey fines (C).
Answer: SC, clayey sand (with gravel).
- 2075 Bhadra · 5 marks
Particle size distribution curves for two types of soil, Soil A and Soil B, are shown in the figure [Figure: percentage passing versus particle size (mm), log scale; labelled points on the curves: 99% and 55% for soil A, 63% and 13% for soil B, with the 0.075 mm and 4.75 mm sizes marked on the axis]. Water contents measured at the boundaries between the liquid state-plastic state and plastic state-semi solid for soil A are 45% and 15% respectively. Similarly, for Soil B, they are 25% and 10% respectively. Classify these soils based on the Unified Soil Classification System. Draw the plasticity chart if required.
Answer
Reading the curves
For each soil the larger percent is taken as the percent passing the 4.75 mm sieve and the smaller as the percent passing the 0.075 mm sieve.
| Soil | Passing 4.75 mm | Passing 0.075 mm | |||
|---|---|---|---|---|---|
| A | 99% | 55% | 45 | 15 | 30 |
| B | 63% | 13% | 25 | 10 | 15 |
Soil A
Fines , so it is fine-grained.
: above the A-line (clay); (low plasticity).
Soil A: CL, lean clay (sandy).
Soil B
Fines and less than 50%, so it is coarse-grained with fines.
- Gravel
- Sand
Sand is more than half of the coarse fraction (), so it is S.
and above the A-line: clayey fines.
Soil B: SC, clayey sand.
Plasticity chart
Ip
30| * A
20| / A-line
15| * B /
7|----/-----------
4| /
0+----+----+----+---- wL
0 25 45 50
Point A (45, 30) lies above the A-line; B (25, 15) lies above it as well.
- 2075 Baisakh · 6 marks
A soil has the following characteristics:
a) Percentage of soil passing No. 200 sieve = 55
b) Percentage of coarse fraction passing No. 4 sieve = 60
c) Liquid limit = 68%
d) Plastic limit = 22%
Classify the given soil according to ISSCS.
Answer
Given
Passing No. 200 ; ; (the percentage of coarse fraction passing No. 4 is not needed).
Step 1: Coarse or fine?
Since 55% passes the 75 micron sieve (more than 50%), the soil is fine-grained.
Step 2: Plasticity group (IS 1498)
- : low (L); : medium (I); : high (H).
- : high plasticity (H).
Step 3: Position relative to the A-line
: the soil plots above the A-line, so it is a clay (C) (inorganic).
Answer: CH, inorganic clay of high plasticity (fat clay). Because 45% is coarse, it may be described as a sandy or gravelly clay.
- 2076 Baisakh · 6 marks
A sample of inorganic soil has the following grain size characteristics:
Size (mm) Percent passing 0.075 (No. 200) 58 0.425 (No. 40) 80 2 mm (No. 10) 100
The liquid limit is 30% and PI is 10%. Classify the soil according to the AASHTO classification system.
Answer
Given
Passing No. 200 ; passing No. 40 ; passing No. 10 ; ; .
Step 1: Granular or silt-clay?
58% passes the No. 200 sieve, which is more than 35%, so the soil is in the silt-clay group (A-4 to A-7).
Step 2: Check groups from the left of the table (AASHTO)
| Group | max | Result | |
|---|---|---|---|
| A-4 | 40 | 10 max | Satisfied: , |
| A-5 | 41 min | 10 max | Not satisfied () |
| A-6 | 40 max | 11 min | Not satisfied () |
| A-7 | 41 min | 11 min | Not satisfied |
So the soil is A-4.
Group index
Answer: A-4(3), silty soil; fair to poor subgrade.
- 2073 Bhadra · 3 marks
Classify the following soil as per the unified soil classification system: soil passing from 75 µ sieve = 4%, soil passing from 4.75 mm sieve (coarse fraction) = 62%, coefficient of uniformity = 5, coefficient of curvature = 2.6.
Answer
Given
Passing 75 micron ; passing 4.75 mm ; ; .
- Fines are only 4%, so the soil is coarse-grained.
- Gravel (retained on 4.75 mm) ; sand . Sand is more than half of the coarse fraction (58/96 = 60%), so it is sand (S).
- Fines are < 5%, so grading decides: well-graded sand needs and . Here passes, but fails.
Answer: SP, poorly graded sand (with gravel).
- 2073 Bhadra · 3 marks
Classify the following soil as per the unified soil classification system: soil passing from 75 µ sieve = 62%, liquid limit = 54%, plastic limit = 23%.
Similar questions: USCS classification, 75 micron 39% (2073 Bhadra)
Answer
Given
Passing 75 micron ; ; .
- 62% passes the 75 micron sieve (more than 50%), so the soil is fine-grained.
- : high plasticity (H).
- A-line at : . Since , the soil is above the A-line: clay (C).
Answer: CH, inorganic clay of high plasticity (fat clay).
- 2073 Bhadra · 2 marks
Classify the following soil as per the unified soil classification system: soil passing from 75 µ sieve = 39%, liquid limit = 33%, plastic limit = 18%.
Similar questions: USCS classification, 75 micron 62% (2073 Bhadra)
Answer
Given
Passing 75 micron ; ; .
- Only 39% is finer than 75 micron (less than 50%), so the soil is coarse-grained, with more than 12% fines.
- Fines classification: A-line at : . lies above the A-line and is greater than 7, so the fines are clayey (C).
- The gravel/sand split is not given. Assuming the coarse fraction is mainly sand (the usual case), the symbol is SC; if gravel dominates it would be GC.
Answer: SC, clayey sand (GC if gravel exceeds sand).
Questions from Old Question Collection (CE 552) (IOE BCE Soil Mechanics (CE552) papers from 2073 Bhadra to 2079 Asoj). Answers are written for this site; check them against your class notes.
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