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Chapter 3 · 3 hours

Bio energy

Practice questions

Practice questions and answers

4 exam-style questions on this chapter, written for this site from the official syllabus. We haven’t found past IOE papers for this subject yet; if you have some, share them in the community.

  • Practice · 8 marks

Explain the process of biogas generation by anaerobic digestion. Discuss the factors that affect the production of biogas in a digester.

Answer

Biogas is a mixture of about 55–65 % methane, 35–45 % carbon dioxide and traces of H₂S, H₂ and N₂, produced when organic matter decomposes without oxygen. Its calorific value is about 20–24 MJ/m³.

Stages of anaerobic digestion

  1. Hydrolysis: extracellular enzymes of bacteria break complex polymers (cellulose, proteins, fats) into soluble sugars, amino acids and fatty acids.
  2. Acidogenesis (fermentation): acid-forming bacteria convert these into volatile fatty acids, alcohols, CO₂ and H₂.
  3. Acetogenesis: the acids are converted into acetic acid, H₂ and CO₂.
  4. Methanogenesis: methane-forming bacteria produce methane: CH3COOH→CH4+CO2CH_3COOH \rightarrow CH_4 + CO_2 and CO2+4H2→CH4+2H2OCO_2 + 4H_2 \rightarrow CH_4 + 2H_2O.

The first two stages are done by acid formers; the methanogens are slow growing and sensitive.

Factors affecting gas production

FactorEffect and usual value
TemperatureMesophilic range 30–40 °C is best; gas output drops sharply below 15 °C. Thermophilic 50–60 °C needs heating.
pH6.8–7.5; below 6.5 methanogens are inhibited.
Retention time30–60 days for cattle dung (depends on temperature).
C/N ratio20:1 to 30:1. Too high gives little gas, too low gives ammonia toxicity.
Total solids7–10 % in the slurry (dung:water about 1:1).
Nutrients and toxic materialsNeeds N, P, K; detergents, antibiotics, heavy metals, high ammonia inhibit bacteria.
AgitationPrevents scum and gives contact of bacteria with feed.
Loading rateOverloading causes acid build-up (digester sours).
SeedingAdding digested slurry with active bacteria speeds starting.
Particle sizeFine material digests faster.
  • Practice · 6 marks

With neat sketches, explain the working of a floating drum type and a fixed dome type biogas plant. Differentiate between them.

Answer

A biogas plant has an inlet (mixing tank), a digester where bacteria act on the slurry, a gas holder and an outlet for digested slurry.

Floating drum plant (KVIC / Indian type)

        gas out
          |
      ___ | ___ <- steel drum (moves
     |  gas   |     up/down on guide)
  ---|--------|---
  inlet  \   /  outlet
  --->|  slurry  |--->
      |__________|
       digester well

Slurry is fed into an underground cylindrical digester. The gas collects in an inverted mild steel drum that floats on the slurry and rises or falls with the gas stored, so the gas pressure stays constant (about 8–10 cm of water). A partition wall helps slurry flow.

Fixed dome plant (Chinese / Deenbandhu type)

        gas pipe
           |
        _.-'-._   <- fixed brick dome
       /  gas   \
  --->|  slurry  |---> outlet/displacement
       \_______ /      chamber
        digester

The digester and gas holder are one masonry (brick or concrete) structure. Gas collects under the fixed dome and pushes slurry into the outlet (displacement) chamber, so gas pressure varies with the amount of gas stored (up to 1 m of water column).

PointFloating drumFixed dome
Gas holderMoving steel drumFixed dome, no moving part
Gas pressureConstantVariable
CostHigher (steel drum)Lower
Life8–15 yr (drum corrodes)20 yr or more
MaintenancePainting, drum repairHard to find and repair cracks
Gas leakEasy to seeDifficult to detect
Heat lossHigherUnderground, less variation
Skilled labourLessMore needed for construction
  • Practice · 5 marks

What is biomass? Explain the biochemical conversion processes used to produce fuels from biomass, with the chemical reactions where relevant.

Answer

Biomass is organic matter of recent plant or animal origin (wood, crop residues, animal dung, sewage, energy crops, municipal organic waste) that stores solar energy by photosynthesis. It is renewable and nearly carbon-neutral.

Conversion routes are thermochemical (combustion, gasification, pyrolysis) and biochemical, where microbes or enzymes act on wet biomass at low temperature.

1. Anaerobic digestion (biogas)

Bacteria decompose wet biomass such as dung and sewage sludge in absence of air giving methane-rich biogas (see the four stages: hydrolysis, acidogenesis, acetogenesis, methanogenesis). The digested slurry is a good fertiliser.

2. Alcohol fermentation (ethanol)

Sugar and starch crops (sugarcane, molasses, maize, cassava) are fermented by yeast. Starch is first converted to glucose by enzymes (hydrolysis), then:

C6H12O6→yeast2C2H5OH+2CO2C_6H_{12}O_6 \xrightarrow{\text{yeast}} 2C_2H_5OH + 2CO_2

The dilute product (8–12 % ethanol) is distilled up to about 95 % and dehydrated to anhydrous ethanol for blending with petrol (E10). Cellulosic biomass needs pre-treatment and cellulase enzymes (second-generation ethanol). Theoretical yield is 0.51 kg ethanol per kg glucose.

3. Other biochemical routes

  • Biodiesel by transesterification of vegetable oil with methanol and a catalyst (a chemical process, often grouped with these).
  • Biohydrogen by dark fermentation or photo-fermentation.
  • Composting to produce soil conditioner.

Biochemical routes suit biomass with moisture above 50 %, which would waste energy in drying for thermochemical routes.

  • Practice · 6 marks

A farmer keeps 6 cattle producing 10 kg of fresh dung per animal per day. The gas yield is 0.036 m³ per kg of dung. The dung is mixed with an equal mass of water, the retention time is 40 days and the gas holder is to store 60 % of the daily gas production. Estimate (a) the daily gas production, (b) the digester volume, (c) the gas holder volume, and (d) the number of persons whose cooking needs (0.34 m³ per person per day) can be met.

Answer

Data

Dung per day =6×10=60= 6 \times 10 = 60 kg.

(a) Gas production

Vg=60×0.036=2.16 m3/dayV_g = 60 \times 0.036 = 2.16\ \text{m}^3/\text{day}

(b) Digester volume

Slurry = dung + equal water =60+60=120= 60 + 60 = 120 kg/day. Taking slurry density about 1000 kg/m³, the feed is 0.12 m³/day.

Vd=feed rate×retention time=0.12×40=4.8 m3V_d = \text{feed rate} \times \text{retention time} = 0.12 \times 40 = 4.8\ \text{m}^3

About 10 % extra may be added for gas space and scum, giving about 5.3 m³ in practice.

(c) Gas holder volume

Vh=0.60×2.16=1.30 m3V_h = 0.60 \times 2.16 = 1.30\ \text{m}^3

(d) Persons served

2.160.34=6.35≈6 persons\frac{2.16}{0.34} = 6.35 \approx 6\ \text{persons}

Energy content (at about 22 MJ/m³): 2.16×22=47.52.16 \times 22 = 47.5 MJ per day.

Answer: gas = 2.16 m³/day; digester = 4.8 m³ (about 5.3 m³ with allowance); gas holder = 1.30 m³; cooking for about 6 persons.

Written from the official syllabus. Questions and answers are written for this site; check them against your class notes.

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