Chapter 3 · 3 hours
Properties of Manufactured Products
Practice questions
Practice questions and answers
3 exam-style questions on this chapter, written for this site from the official syllabus. We haven’t found past IOE papers for this subject yet; if you have some, share them in the community.
- Practice · 3+5 marks
(a) Differentiate between unilateral and bilateral tolerance, and explain geometric tolerance with any four characteristic symbols. (b) A hole is dimensioned mm. Three shafts are available: (i) , (ii) , (iii) . For each, find the maximum and minimum clearance (or interference) and state the type of fit.
Answer
(a) Unilateral and bilateral tolerance; geometric tolerance
| Point | Unilateral | Bilateral |
|---|---|---|
| Variation | In one direction only from basic size | On both sides of basic size |
| Example | ||
| Use | Hole basis / shaft basis systems, easy fits | Positioning, centre distances |
Geometric tolerance limits the form, orientation, location and run-out of a feature, not just its size. It is given in a feature control frame on the drawing. Characteristic symbols:
- Straightness (a straight line) and flatness (a parallelogram) - form.
- Parallelism (two parallel lines) and perpendicularity (a right-angle) - orientation.
- Concentricity (two circles) and position - location.
- Circular run-out (arrow) - run-out.
(b) Fit calculation
Hole: maximum size mm, minimum size mm.
Maximum clearance hole max shaft min; minimum clearance hole min shaft max (negative value = interference).
Shaft (i): shaft max , min
Both positive, so it is a clearance fit (running fit).
Shaft (ii): shaft max , min
Both negative, so maximum interference mm and minimum interference mm: an interference (press) fit.
Shaft (iii): shaft max , min
The result can be clearance or interference, so it is a transition fit.
| Shaft | Max clearance (mm) | Min clearance (mm) | Fit |
|---|---|---|---|
| (i) | 0.089 | 0.025 | Clearance |
| (ii) | Interference | ||
| (iii) | 0.013 | Transition |
Answer: (i) clearance fit, 0.089 to 0.025 mm; (ii) interference fit, 0.004 to 0.059 mm; (iii) transition fit, 0.013 mm clearance to 0.042 mm interference.
- Practice · 5 marks
Define centre-line average roughness and root-mean-square roughness . The heights of 10 equally spaced points of a surface profile measured from the mean line within a sampling length are (in micrometre): +2.0, -1.5, +3.5, -2.5, +1.0, -3.0, +2.5, -1.0, +3.0, -4.0. Calculate , and the maximum peak-to-valley height. Name two factors that cause surface roughness in machining.
Answer
Surface texture has roughness (fine irregularities from the process), waviness (longer wavelength, from vibration or deflection) and lay (direction of the pattern).
Definitions
is the arithmetic mean of the absolute deviations of the profile from the mean line:
(also RMS) is the square root of the mean of the squares of the deviations:
Check of the mean line
Sum of ordinates: , so the reference line is the mean line.
Calculation of
Calculation of
Maximum peak-to-valley height
Factors causing roughness in machining
- Feed marks: in turning the theoretical roughness is where is the feed and the nose radius.
- Built-up edge, tool wear, vibration (chatter) and machine tool rigidity.
Answer: m, m, m.
- Practice · 5 marks
What are residual stresses? Explain how they are produced in manufacturing processes, their effects on the product, and the methods of reducing or removing them.
Answer
Residual stresses are stresses that remain in a body after all external loads and temperature gradients have been removed. They are self-balancing: tensile stress in one region is balanced by compressive stress in another.
Origin
Residual stress appears whenever different parts of a body deform plastically by different amounts, or cool at different rates.
- Non-uniform plastic deformation: in bending, the outer fibres are plastically stretched and when the load is removed the elastic core pushes them back, leaving compressive stress on the surface that was in tension. Rolling, drawing and shot peening also leave surface compression.
- Thermal gradients: in quenching, the surface cools first and contracts; later the core contracts against a rigid shell, leaving surface compression and core tension. In welding, the weld region shrinks against cold parent metal and is left in tension.
- Phase transformation: martensite formation causes volume expansion in some regions (hardening of steel).
- Machining and grinding: mechanical deformation under the tool and heat generated leave a thin surface layer in tension (grinding heat) or compression (sharp tools, low feed).
Effects
- Distortion and warping when material is machined away or heated.
- Compressive residual stress at the surface improves fatigue life and resists crack growth.
- Tensile residual stress at the surface reduces fatigue strength and causes stress-corrosion cracking and cold cracks in welds.
- Dimensional instability of precision parts with time.
Methods of reduction or removal
| Method | Principle |
|---|---|
| Stress-relief annealing | Heat below the transformation temperature (about 550-650 degree C for steel), hold, cool slowly |
| Tempering | After hardening, relieves quench stresses |
| Stretching / light cold work | Small plastic deformation (about 1-2 percent) levels the stress |
| Vibratory stress relief | Vibration at resonance redistributes stress |
| Shot peening | Introduces beneficial surface compression |
| Controlled cooling and proper process design | Reduces thermal gradient |
Written from the official syllabus. Questions and answers are written for this site; check them against your class notes.
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