Chapter 8 · 3 hours
Material Removal Processes: “Abrasive and Non-Traditional”
Practice questions
Practice questions and answers
2 exam-style questions on this chapter, written for this site from the official syllabus. We haven’t found past IOE papers for this subject yet; if you have some, share them in the community.
- Practice · 5 marks
Explain the standard marking system of a grinding wheel with an example, such as A 60 K 5 V. What are glazing and loading of a grinding wheel? How are truing and dressing done?
Answer
A grinding wheel is a bonded mass of abrasive grains. Each grain acts as a tiny cutting tool, and the wheel renews itself as the dull grains break out and fall away.
Standard marking, example A 60 K 5 V
A 60 K 5 V
| | | | |
abrasive grit grade structure bond
| Letter or number | Meaning | Here |
|---|---|---|
| Abrasive | A = aluminium oxide, C = silicon carbide, B = CBN, D = diamond | Aluminium oxide: steels |
| Grain size | Grit number (coarse 10-24, medium 30-60, fine 70-180, very fine 220+) | 60 = medium |
| Grade | Hardness, A (soft) to Z (hard); the strength of the bond | K = medium |
| Structure | Spacing of grains, 1 (dense) to 15 (open) | 5 = medium |
| Bond | V = vitrified, S = silicate, R = rubber, B = resinoid, E = shellac | Vitrified |
Selection guide
- Steel and soft metals use aluminium oxide; cast iron, carbide and non-ferrous use silicon carbide.
- Hard materials need a soft grade so that dull grains drop out; soft materials need hard grades.
- Fine grit for good finish; coarse grit for fast removal.
- Wide contact area or soft material needs open structure.
Glazing and loading
- Glazing: the abrasive grains become blunt and the wheel surface turns smooth and shiny because the grade is too hard. Cutting efficiency falls, heat and burning appear.
- Loading: the spaces between the grains fill with chips of the work material (soft ductile metals such as aluminium or copper). The wheel cuts poorly.
Truing and dressing
- Truing restores the wheel shape and makes it run concentric, using a single-point diamond or a diamond roll.
- Dressing restores sharpness and exposes new grains by removing the glazed or loaded layer, using a dressing stick, star dresser (Huntington) or diamond. Often both are done together.
- Practice · 4+4 marks
(a) Explain the working principle of electrical discharge machining (EDM) with a sketch. State its advantages and limitations. (b) Explain the principle of electrochemical machining (ECM). In ECM of pure iron (atomic weight 55.85, valency 2, density 7.86 g/cm) a current of 1000 A is used with a current efficiency of 90 percent. Calculate the volumetric material removal rate and the tool feed rate if the cross-sectional area of the machined cavity is 400 mm.
Answer
(a) EDM
In EDM, the work and the shaped tool (electrode) are both immersed in a dielectric fluid (kerosene, transformer oil or deionised water) and kept a small gap apart (0.01-0.5 mm). A pulsed DC supply makes a spark discharge across the gap; each spark generates temperature of 8000-12000 degree C in a tiny spot, melting and vaporising a small crater in the work. The dielectric flushes out the debris and re-insulates the gap. A servo system keeps the gap constant as the tool advances, and the tool shape is reproduced in the work.
+---- pulse generator ----+
| |
tool (+/-) spark gap work (-/+)
|__ dielectric fluid + flushing __|
servo feed (down)
Advantages: machines any electrically conductive material regardless of hardness (hardened steel, carbide); complex cavities, dies and small deep holes; no cutting force, no burr; good accuracy.
Limitations: only conductive materials; slow metal removal; tool wear and recast (heat-affected) layer; high power; sharp inside corners not possible.
(b) ECM
In ECM, the work is the anode and the tool is the cathode. A low-voltage (10-20 V), high current (several thousand A/cm) DC flows through a fast electrolyte (NaCl or NaNO solution) in a gap of about 0.1-0.5 mm. The work metal dissolves according to Faraday's law, and the electrolyte carries the hydroxide sludge away. The tool is not worn.
By Faraday's laws, mass removed per second:
Volumetric rate:
with g/mol, , C/mol, g/cm, , A.
This equals (about 2.0 cm/min).
Tool feed rate for the cavity cross-section of 400 mm:
Answer: volumetric removal rate mm/s (1.99 cm/min); feed rate mm/min.
Written from the official syllabus. Questions and answers are written for this site; check them against your class notes.
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