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Chapter 1 · 3 hours

Concrete Structures and Design Methods

IOE past exam questions

Past questions and answers

5 questions set from this chapter, 2 of them more than once; 2 are most repeated (set, or a close variant set, in 3 or more exams). Most repeated first.

  • Most repeated · 6 of 25 exams
  • Asked 6 times
  • 2081 Bhadra · 4 marks
  • 2079 Bhadra · 2 marks
  • 2074 Chaitra · 5 marks
  • 2072 Chaitra · 5 marks
  • 2066 Bhadra (old course) · 5 marks
  • 2065 Shrawan (old course) · 7 marks

Differentiate between the working stress method and the limit state method of design (explain with stress and strain diagrams where needed).

Answer

The working stress method (WSM) designs a member so that stresses under working (service) loads stay within permissible elastic limits. The limit state method (LSM) designs a member so that it will not reach any limit state (collapse or serviceability) when factored loads act, using partial safety factors for loads and materials.

PointWorking stress methodLimit state method
BasisElastic theory, stress-strain linear for both materialsInelastic behaviour; concrete uses parabolic-rectangular curve up to failure
LoadsService (working) loadsCharacteristic loads multiplied by γf\gamma_f (factored loads)
SafetySingle factor of safety applied to material strength (permissible stress)Partial safety factors: γf\gamma_f on loads, γm\gamma_m on materials (1.5 concrete, 1.15 steel)
Stress in concreteLinear, maximum σcbc\sigma_{cbc}Non-linear, 0.446fck0.446 f_{ck} design stress block
Modular ratioUsed (m=280/3σcbcm = 280/3\sigma_{cbc})Not used
Reserve strengthNot known; may be uneconomical or unsafe at failureKnown margin against collapse
ServiceabilityNot checked explicitlyDeflection and cracking checked explicitly
EconomyLess economical for the same safetyMore economical, rational
Code statusKept in IS 456:2000 Annex B (alternative)Main method of IS 456:2000

Stress and strain diagrams at section level

   WSM (service load)        LSM (collapse)
   strain    stress          strain    stress
   |\        |\              0.0035    0.446fck
   | \       | \ f_c<=σcbc    |\        |========|
 x |  \    x |  \           xu |  \    xu |        |
 --+---  ----+---        ----+---    ----+--------+
   |  /      |   T=σst.Ast    |  /       |   T=0.87fy.Ast
   | /       |                | /        |
   linear   linear      linear   parabola+rectangle

In WSM, a triangular concrete stress block with fc≤σcbcf_c \le \sigma_{cbc} and steel stress ≤σst\le \sigma_{st} is used. In LSM, the strain at the extreme concrete fibre is 0.00350.0035 and the compressive block is parabola plus rectangle (average stress 0.36fck0.36 f_{ck}, centroid at 0.416xu0.416x_u from the top), with steel at 0.87fy0.87 f_y.

  • Most repeated · 3 of 25 exams
  • Asked 3 times
  • 2082 Baisakh · 3 marks
  • 2078 Bhadra · 1+1 marks
  • 2079 Bhadra · 2 marks

Define/explain characteristic strength and characteristic load.

Answer

Characteristic strength

The characteristic strength of a material is the value of strength below which not more than 5 percent of the test results are expected to fall (95 percent reliability). It is the basis of design in limit state method (IS 456:2000, cl. 36.1).

  • Concrete: characteristic compressive strength fckf_{ck} is the 28-day strength of 150 mm cubes. For M20, fck=20f_{ck} = 20 N/mm2^2.
  • Steel: characteristic strength fyf_y is the yield stress (or 0.2% proof stress). For Fe415, fy=415f_y = 415 N/mm2^2.
  • Statistically, fck=fm−1.65 sf_{ck} = f_m - 1.65\,s, where fmf_m is the mean strength and ss the standard deviation.

Characteristic load

The characteristic load is the value of a load which has a 95 percent probability of not being exceeded during the life of the structure (IS 456:2000, cl. 36.2). Since statistical data are rarely available, the loads given in the codes are taken as characteristic loads: dead load from IS 875 (Part 1), live load from IS 875 (Part 2), wind load from IS 875 (Part 3), and earthquake load from IS 1893.

Use in design

Design values are obtained with partial safety factors:

  • Design strength =fkγm= \dfrac{f_k}{\gamma_m}, with γm=1.5\gamma_m = 1.5 for concrete and 1.151.15 for steel.
  • Design load =γf×= \gamma_f \times characteristic load, with γf=1.5\gamma_f = 1.5 for DL+LL, for example.
  • 2069 Chaitra · 6 marks

Explain the different types of design methods used in reinforced concrete structure design.

Answer

Reinforced concrete members can be designed by the following methods.

1. Working stress method (WSM)

  • Based on elastic theory; concrete and steel are assumed to behave elastically, with strain proportional to distance from the neutral axis.
  • Concrete tension is ignored; steel is transformed into an equivalent concrete area using modular ratio m=280/(3σcbc)m = 280/(3\sigma_{cbc}).
  • Safety is obtained by limiting stresses under service load to permissible values (σcbc\sigma_{cbc}, σst\sigma_{st}) which are fractions of the strength.
  • Drawbacks: ignores non-linear behaviour, creep and shrinkage effects, gives no idea of true load factor.

2. Ultimate load method (load factor method)

  • Design is based on the ultimate strength of the section at failure, using non-linear stress-strain of concrete.
  • Working loads are multiplied by a load factor (e.g. 1.5 for DL, 2.2 for LL in the older ACI/CP114 practice) to get ultimate loads, and section strength is compared with it.
  • Gives a realistic factor of safety against collapse but does not control deflection and cracking at working loads.

3. Limit state method (LSM)

  • Adopted as the main method of IS 456:2000. The structure is designed so that it does not reach a limit state, i.e. a state beyond which it becomes unfit for use.
  • Limit state of collapse (flexure, shear, torsion, compression) is checked with factored loads and design material strengths (fck/1.5f_{ck}/1.5, fy/1.15f_y/1.15).
  • Limit state of serviceability (deflection, cracking, durability, vibration) is checked at service loads.
  • Uses partial safety factors for loads and materials, so safety is more rational and economical.

4. Probabilistic method

  • Loads and strengths are treated as random variables; design is done for a target probability of failure (reliability). It is the basis of the partial factors in LSM but is not used directly in routine design.

Summary: IS 456:2000 uses LSM as the primary method, with WSM kept as an alternative (Annex B) mainly for liquid-retaining and special cases.

  • 2071 Chaitra · 8 marks

Discuss in detail the working stress method versus limit state method of design with their respective advantages and disadvantages. Compare balanced, under-reinforced and over-reinforced sections in limit state and working stress design methods.

Answer

Working stress method (WSM)

Stresses under working load are limited to permissible values, using linear elastic theory and modular ratio mm.

Advantages

  • Simple, quick calculations; long experience in use.
  • Stresses at service load are known, so deflection and cracking are reasonably controlled.
  • Suitable for liquid-retaining structures (cracking governs).

Disadvantages

  • Real stress-strain behaviour is non-linear, so the method does not predict true strength.
  • Single factor of safety; the margin against collapse is unknown and varies with the load combination.
  • Ignores creep, shrinkage and different variability of dead and live loads.
  • Uneconomical sections.

Limit state method (LSM)

The structure is designed for the limit states of collapse and serviceability using characteristic loads, partial safety factors and the non-linear stress-strain curves.

Advantages

  • Realistic, uses ultimate strength so a known margin against collapse.
  • Different partial factors for loads and materials reflect their different uncertainty.
  • Serviceability (deflection, cracking) is checked explicitly.
  • More economical sections.

Disadvantages

  • More complex; separate checks for several limit states.
  • Serviceability checks may need trial and revision.

Comparison of balanced, under-reinforced and over-reinforced sections

SectionIn WSMIn LSM
Balancedx=xc=mσcbcmσcbc+σstdx = x_c = \dfrac{m\sigma_{cbc}}{m\sigma_{cbc}+\sigma_{st}}d; concrete and steel reach σcbc\sigma_{cbc} and σst\sigma_{st} togetherxu=xu,maxx_u = x_{u,max} (0.48d0.48d for Fe415); concrete strain 0.0035 and steel strain 0.87fy/Es+0.0020.87f_y/E_s + 0.002 reached together
Under-reinforcedx<xcx < x_c; steel stress reaches σst\sigma_{st} first, Mr=σstAst(d−x/3)M_r = \sigma_{st}A_{st}(d-x/3)xu<xu,maxx_u < x_{u,max}; steel yields first, Mu=0.87fyAst(d−0.416xu)M_u = 0.87f_yA_{st}(d-0.416x_u); ductile failure, preferred
Over-reinforcedx>xcx > x_c; concrete reaches σcbc\sigma_{cbc} first, Mr=12σcbcbx(d−x/3)M_r = \tfrac12\sigma_{cbc}bx(d-x/3)xu>xu,maxx_u > x_{u,max}; concrete crushes before steel yields, brittle failure; not permitted (use Mu,limM_{u,lim} or add compression steel)

Under-reinforced sections are always preferred because they give warning (large deflection and cracks) before failure.

  • 2067 Asar (old course) · 4 marks

Compare the factor of safety used in Working Stress Method and the partial safety factor used in Limit State Method for concrete and steel.

Answer

In WSM safety is given by one factor of safety applied to the material strength to get a permissible stress. In LSM safety is split into partial safety factors, one for material strength (γm\gamma_m) and one for loads (γf\gamma_f).

Working stress method

  • Concrete: σcbc=fckF.O.S.\sigma_{cbc} = \dfrac{f_{ck}}{\text{F.O.S.}}. For M20, σcbc=7\sigma_{cbc} = 7 N/mm2^2, so the factor of safety is about 20/7≈2.8620/7 \approx 2.86 (nearly 3 on cube strength).
  • Steel: σst=fyF.O.S.\sigma_{st} = \dfrac{f_y}{\text{F.O.S.}}. For Fe415, σst=230\sigma_{st} = 230 N/mm2^2, giving 415/230≈1.8415/230 \approx 1.8; for mild steel, σst=140\sigma_{st} = 140, so 250/140≈1.8250/140 \approx 1.8.
  • Loads are taken at working value with no factor.

Limit state method (IS 456:2000, cl. 36.4)

ItemPartial safety factor
Concrete, γmc\gamma_{mc}1.5
Steel, γms\gamma_{ms}1.15
Load (DL + LL), γf\gamma_f1.5

Design strengths: concrete 0.67fck/1.5=0.446fck0.67f_{ck}/1.5 = 0.446f_{ck} in the stress block; steel 0.87fy0.87f_y (as fy/1.15f_y/1.15).

Comparison

PointWSMLSM
FactorOne factor on materialSeparate factors on material and load
ConcreteAbout 31.5 (material)
SteelAbout 1.81.15 (material)
Load1.01.5
Overall marginNot knownKnown: about 1.5×1.5=2.251.5\times1.5 = 2.25 on concrete and 1.5×1.15=1.731.5\times1.15 = 1.73 on steel

A lower material factor is acceptable in LSM because uncertainty in loads is accounted separately by γf\gamma_f.

Questions from Old Question Collection (CE 702) (IOE exam papers from 2065 to 2082 (CE 702, BCE IV/I)) and Old Question Collection (CE 702) (4 IOE papers 2075 to 2079 (only 2079 Baisakh not already in the other file)). Answers are written for this site; check them against your class notes.

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