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Chapter 12 · 6 hours

Introduction to Earthquake Resistant Design and Provisions for Ductile Detailing

IOE past exam questions

Past questions and answers

15 questions set from this chapter, 4 of them more than once; 2 are most repeated (set, or a close variant set, in 3 or more exams). Most repeated first.

  • Most repeated · 4 of 25 exams
  • Asked 4 times
  • 2082 Baisakh · 3 marks
  • 2080 Bhadra · 2 marks
  • 2075 Chaitra · 6 marks
  • 2072 Kartik · 6 marks

Explain the ductility requirements/ductile detailing for the reinforced concrete beam with neat sketches (requirements on reinforcement detailing in beams to ensure sufficient ductility).

Answer

Ductility is the ability of a member to undergo large inelastic deformation without significant loss of strength. In a beam it is obtained by making the tension steel yield before the concrete crushes and by preventing early shear failure. IS 13920 gives the following detailing rules.

Geometry

  • Width b≥200b \ge 200 mm and b/D≥0.3b/D \ge 0.3.
  • Depth D≤14D \le \tfrac14 of clear span.

Longitudinal steel

  • At least two bars (12 mm or more) continuous at top and at bottom.
  • ρmin=0.24fck/fy\rho_{min} = 0.24\sqrt{f_{ck}}/f_y and ρmax=2.5%\rho_{max} = 2.5\% on any face.
  • Positive steel at a joint face is not less than 50% of the negative steel there.
  • Along the span, neither positive nor negative capacity is less than 25% of the maximum capacity at either joint face.
  • Lap splices only in the middle half of the span, never within the joint or within 2d2d of a joint face. Not more than 50% of bars are spliced at one section and the splice is enclosed by closely spaced hoops (spacing ≤150\le 150 mm).

Transverse steel (stirrups)

  • Closed hoops with 135∘135^\circ hooks and a tail of 10ϕ10\phi (not less than 75 mm) so that they stay effective after the cover spalls.
  • Diameter ≥6\ge 6 mm (8 mm if clear span exceeds 5 m).
  • Over a length 2d2d from each joint face the spacing is the least of d/4d/4, 8ϕmin8\phi_{min} and 100 mm, with the first hoop at 50 mm. Elsewhere the spacing is ≤d/2\le d/2.
  • Stirrups are designed for the shear that develops when plastic hinges form at both ends (capacity design).
  Column |<-- 2d -->|<------ L/2 ------>|<- 2d ->| Column
  -------+-+-+-+-+-+---------------------+-+-+-+-+-------
         | | | | | |  hoops at d/2       | | | | | |
         | | | | | |                     | | | | | |
  -------+-+-+-+-+-+---------------------+-+-+-+-+-------
   50 mm, then s <= min(d/4, 8phi, 100)      lap splice only
                                              in middle half
  • Most repeated · 4 of 25 exams
  • Asked 4 times
  • 2076 Asoj · 6 marks
  • 2071 Chaitra · 6 marks
  • 2075 Asoj · 6 marks
  • 2080 Bhadra · 2 marks

Write the provisions of ductile detailing of column / special confining reinforcement for ductile detailing of column with neat sketches.

Answer

Columns must stay stable while the beams yield, so IS 13920 asks for good confinement at the ends, where plastic hinges can form.

General requirements

  • Minimum dimension 200 mm (300 mm if the unsupported length exceeds 4 m or beam span exceeds 5 m); b/D≥0.4b/D \ge 0.4.
  • Longitudinal steel 0.8% to 6% (IS 456); lap splices only in the central half of the column height, designed as tension splices, with hoop spacing ≤150\le 150 mm over the lap.

Special confining reinforcement

  • Provided over a length lol_o at both ends of each column, measured from the joint face, where lo≥l_o \ge the largest of: larger lateral dimension, h/6h/6 (clear height) and 450 mm.
  • Hoop spacing in this zone: s≤14bmins \le \tfrac14 b_{min} but between 75 mm and 100 mm.
  • Hoops are closed with 135∘135^\circ hooks, tail ≥6ϕ\ge 6\phi (not less than 65 mm). Minimum diameter 8 mm (10 mm for bars over 32 mm).
  • Area of one leg-group (rectangular hoop) per spacing:
Ash=0.18 s h fckfy(AgAk−1)A_{sh} = 0.18\, s\, h \,\frac{f_{ck}}{f_y}\left(\frac{A_g}{A_k} - 1\right)

where hh is the longer dimension of the confined core measured c/c of hoops, AgA_g is the gross area and AkA_k is the core area. For circular spirals, Ash=0.09 s Dkfckfy(AgAk−1)A_{sh} = 0.09\, s\, D_k \frac{f_{ck}}{f_y}\left(\frac{A_g}{A_k}-1\right).

  • Where a column supports a discontinued stiff member (wall), the confining steel runs over the full height of the column below.
  • Outside lol_o the spacing follows IS 456 (not more than the least lateral dimension, 16ϕ16\phi or 300 mm).
   Joint ---------------
     ^     | # # # # # |  s = 75-100 mm
     | lo  | # # # # # |  (closely spaced hoops)
     v     | # # # # # |
   ------- |#  #  #  # |  
     h-2lo | #    #    |  normal spacing (IS 456)
   ------- | # # # # # |  close spacing again
  • Asked 2 times
  • 2074 Chaitra · 6 marks
  • 2080 Baisakh · 4 marks

Explain briefly the ductile detailing requirements for beam and column with neat sketches.

Answer

Ductile detailing makes the structure deform plastically in a controlled way during an earthquake without sudden collapse. IS 13920 governs the detailing of beams, columns and joints.

Beam

  • b≥200b \ge 200 mm, b/D≥0.3b/D \ge 0.3, D≤L/4D \le L/4.
  • Two bars continuous at top and bottom; ρ\rho between 0.24fck/fy0.24\sqrt{f_{ck}}/f_y and 2.5%.
  • Bottom steel at a joint face ≥50%\ge 50\% of top steel.
  • Splices in the middle half only, with hoops at 150 mm or closer.
  • Closed stirrups with 135∘135^\circ hooks. Within 2d2d of the support, spacing ≤min⁡(d/4, 8ϕ, 100 mm)\le \min(d/4,\ 8\phi,\ 100\text{ mm}); elsewhere ≤d/2\le d/2.

Column

  • Minimum size 200 mm, b/D≥0.4b/D \ge 0.4.
  • Special confining hoops over lo=max⁡(D, h/6, 450 mm)l_o = \max(D,\ h/6,\ 450\text{ mm}) at each end, at 75-100 mm spacing and ≤bmin/4\le b_{min}/4.
  • 135∘135^\circ hooks with 6ϕ6\phi tail; splices only in the middle half.
  • Strong-column weak-beam: the columns at a joint should be stronger than the beams so that hinges form in the beams.
   BEAM                              COLUMN
  |-2d-|--- d/2 ---|-2d-|        ---------
  |||||| | | | | | ||||||        | ##### |  s=75-100
                                 | ##### |  over lo
                                 |  # #  |  s per IS456
                                 | ##### |  s=75-100
                                 ---------

Members are also designed for the shear produced by plastic hinge capacity, not only by analysis, so that shear failure (brittle) cannot precede flexural yielding (ductile).

  • Asked 2 times
  • 2082 Bhadra · 3+3 marks
  • 2079 Baisakh · 4 marks

What do you mean by ductile behaviour of structure and how is ductile behaviour induced/increased in structure?

Answer

Ductile behaviour means that a structure can deform well beyond its yield limit, absorbing and dissipating energy, while still carrying load. It gives visible warning (large cracks and deflection) before failure instead of sudden brittle collapse. Ductility is measured by the ductility ratio μ=Δu/Δy\mu = \Delta_u/\Delta_y (ultimate over yield displacement).

  Load
   |      ___________  ductile
   |    /            \
   |   /              \___
   |  /   brittle: |
   | /     ________|
   |/_____/________________ Deformation

How ductility is induced

  1. Under-reinforced sections: limit tension steel so that steel yields before concrete crushes (xu≤xu,maxx_u \le x_{u,max}, and ρ≤2.5%\rho \le 2.5\%).
  2. Compression steel: adds ductility in flexure by lowering the neutral axis depth.
  3. Confinement: closely spaced closed hoops with 135∘135^\circ hooks, especially at column ends, joints and beam ends, keep the concrete core intact.
  4. Capacity design: strong column - weak beam, and shear capacity greater than flexural capacity, so failure is controlled by yielding of beams.
  5. Proper anchorage and lap splices: bars anchored into joints, laps away from hinge zones.
  6. Good materials: Fe 415/Fe 500 with fairly high elongation, concrete not weaker than M20, and structural regularity in plan and elevation.
  7. Avoid short columns and soft storeys where deformation concentrates.
  • 2081 Bhadra · 4 marks

Draw a neat sketch of beam-column joint including ductile details.

Similar questions: Define ductility, joint detailing sketch (2072 Chaitra)

Answer

          Column above (hoops s=75-100)
                  | | | |
           +------#########------+
 top bars  =====>#  joint  #<====  top bars
 anchored  |     #  hoops   #     |  continuous
 Ld from   |     #  s<=100  #     |
 inner face|=====>#         #<====|
 + 90 bend +------#########------+
 (10 phi)         | | | |
          Column below (hoops s=75-100)

  Beam: hoops 50 mm from face, s <= d/4, 8phi, 100

Ductile details shown:

  • Column confining hoops (closed, 135∘135^\circ hooks, 6ϕ6\phi tail) run continuously through the joint at ≤100\le 100 mm (up to 150 mm if beams frame in on all four faces).
  • Beam longitudinal bars at an exterior joint extend to the far face of the column, are anchored for LdL_d measured from the inside face, and end in a 90∘90^\circ bend with a standing leg of ≥10ϕ\ge 10\phi turned down.
  • Column bars are continuous through the joint; no lap splice within the joint or within 2d2d of its face.
  • Beam stirrups start 50 mm from the joint face, spacing ≤min⁡(d/4, 8ϕ, 100 mm)\le \min(d/4,\ 8\phi,\ 100\text{ mm}) over 2d2d.
  • Strong-column weak-beam proportioning, so the joint remains elastic.
  • 2072 Chaitra · 1+4 marks

Define the term ductility in RC design. Draw a neat sketch of a beam-column joint including ductile details.

Similar questions: Beam-column joint with ductile details (2081 Bhadra)

Answer

Ductility

Ductility is the property of a structure or member to undergo large plastic (inelastic) deformation before failure without a significant reduction in load capacity. It is expressed by the ductility ratio μ=Δu/Δy\mu = \Delta_u/\Delta_y or curvature ductility ϕu/ϕy\phi_u/\phi_y.

Beam-column joint with ductile details

          Column above (hoops s=75-100)
                  | | | |
           +------#########------+
 top bars  =====>#  joint  #<====  top bars
 anchored  |     #  hoops   #     |  continuous
 Ld from   |     #  s<=100  #     |
 inner face|=====>#         #<====|
 + 90 bend +------#########------+
 (10 phi)         | | | |
          Column below (hoops s=75-100)

  Beam: hoops 50 mm from face, s <= d/4, 8phi, 100

Ductile details shown:

  • Column confining hoops (closed, 135∘135^\circ hooks, 6ϕ6\phi tail) run continuously through the joint at ≤100\le 100 mm (up to 150 mm if beams frame in on all four faces).
  • Beam longitudinal bars at an exterior joint extend to the far face of the column, are anchored for LdL_d measured from the inside face, and end in a 90∘90^\circ bend with a standing leg of ≥10ϕ\ge 10\phi turned down.
  • Column bars are continuous through the joint; no lap splice within the joint or within 2d2d of its face.
  • Beam stirrups start 50 mm from the joint face, spacing ≤min⁡(d/4, 8ϕ, 100 mm)\le \min(d/4,\ 8\phi,\ 100\text{ mm}) over 2d2d.
  • Strong-column weak-beam proportioning, so the joint remains elastic.
  • 2080 Baisakh · 4 marks

Why is ductile detailing needed in joints?

Answer

A beam-column joint transfers the moments and shears of beams into columns. During an earthquake it is subjected to very high horizontal and vertical shear and bond demands, and its failure can bring down the whole frame. Ductile detailing is therefore needed because:

  • High shear in the joint core: the opposite stresses from beam top and bottom bars produce a large diagonal tension that can crack the core.
  • Bond and anchorage stress: bars pass through the joint with yielding on one side and compression on the other, so they may slip. Hence the beam bars must be anchored by their full development length from the inside face of the column, with a 90∘90^\circ bend.
  • Loss of confinement: the joint concrete spalls under cyclic reversals. Closed hoops with 135∘135^\circ hooks keep the core and the bars together.
  • Joint should not yield first: a joint failure is brittle and cannot be repaired, so it must be stronger than the adjoining members.
  • Cyclic loading: stiffness and strength degrade quickly in unconfined joints.

As per IS 13920, the special confining hoops of the column ends are continued through the joint at 75-100 mm spacing (up to 150 mm when beams frame on all four sides). Lap splices are never made in the joint.

  • 2076 Chaitra · 1+4 marks

Define ductility. Describe the ductility requirements in different joints of RCC structure.

Answer

Ductility

Ductility is the capacity of a member or structure to deform inelastically by a large amount (beyond yield) without losing strength appreciably, thereby absorbing seismic energy. Ratio: μ=Δu/Δy\mu = \Delta_u/\Delta_y.

Ductility requirements in joints (IS 13920)

  1. Confinement of the joint core: special confining hoops (closed, 135∘135^\circ hooks, 6ϕ6\phi tail) of the column end zone are continued through the joint at spacing ≤100\le 100 mm (relaxed to 150 mm where beams frame into all four faces of the joint).
  2. Anchorage of beam bars: in an exterior joint, bars are anchored in the column for development length LdL_d measured from the inside face of the column, plus a 90∘90^\circ bend with 10ϕ10\phi standing leg. Bars should not be bent up or bent into the joint region in any way that opens the core.
  3. Continuity of column bars: no lap splice in the joint or within 2d2d of its face; laps only in the central half of the column.
  4. Strong column - weak beam: at each joint the flexural strength of the columns should exceed that of the beams so that hinges form in beams, not in joints or columns.
  5. Joint shear check: the core must resist the shear induced by beam bars yielding, with shear stress limited as per IS 13920 (about 1.2fck1.2\sqrt{f_{ck}} for joints confined on all faces).
  6. Bar diameter and bond: large beam bars passing through interior joints should be limited relative to column depth to prevent slipping.
   Column ##### s=100       Beam bars anchored
   -------+=====+-------    from inner face + bend
   hoops continue through
   the joint   ##### s=100
  • 2069 Chaitra · 6 marks

What are the ductility requirements for beam, column and joints of R.C.C structures?

Answer

Ductility requirements follow IS 13920, and are meant to force plastic hinges into the beams and to prevent brittle shear or bond failure.

Beam

  • b≥200b \ge 200 mm, b/D≥0.3b/D \ge 0.3, D≤L/4D \le L/4.
  • ρmin=0.24fck/fy\rho_{min} = 0.24\sqrt{f_{ck}}/f_y, ρmax=2.5%\rho_{max} = 2.5\%; two bars continuous top and bottom; bottom steel at the joint face ≥\ge 50% of top steel.
  • Lap splices only in the middle half, with hoops at ≤150\le 150 mm.
  • Closed hoops with 135∘135^\circ hooks: s≤min⁡(d/4,8ϕ,100)s \le \min(d/4, 8\phi, 100) mm within 2d2d of supports; s≤d/2s \le d/2 elsewhere.

Column

  • Size ≥200\ge 200 mm (300 mm for long members), b/D≥0.4b/D \ge 0.4.
  • Confining hoops over lo=max⁡(D,h/6,450 mm)l_o = \max(D, h/6, 450\text{ mm}) at each end with spacing 75-100 mm and ≤bmin/4\le b_{min}/4; area from Ash=0.18 s h (fck/fy)(Ag/Ak−1)A_{sh} = 0.18\,s\,h\,(f_{ck}/f_y)(A_g/A_k - 1).
  • Splices in the middle half only; design shear based on beam hinge moments.

Joint

  • Column confining hoops continue through the joint at ≤100\le 100 mm (150 mm if beams on all four sides).
  • Beam bars anchored for LdL_d from the inside face of the column plus a 90∘90^\circ bend of 10ϕ10\phi.
  • No splices in the joint.

Together, the strong-column weak-beam rule and shear capacity above flexural capacity give the ductile mechanism.

  • 2073 Shrawan · 2+3 marks

What is ductility? What are the significances of ductility in RC structures?

Answer

Meaning

Ductility is the ability of a structure or member to undergo large deformation beyond the elastic limit, without a sudden loss of strength, so that it can absorb and dissipate energy. Ductility ratio μ=Δu/Δy\mu = \Delta_u/\Delta_y.

Significance in RC structures

  • Warning before failure: large cracks and deflections occur first, so occupants can escape; brittle failure gives no warning.
  • Earthquake resistance: a ductile building can be designed for a force much smaller than the elastic demand, using the response reduction factor RR (IS 1893) because yielding dissipates energy. Without ductility, the structure would need to stay elastic at a huge cost.
  • Moment redistribution: ductile sections allow redistribution of moments in continuous beams, giving economy.
  • Resistance to overload and unforeseen actions such as settlement, blast, impact or temperature.
  • Prevents collapse: hinges form in beams first (strong column-weak beam), keeping the vertical load path intact.
  • Better use of material: yielding steel and confined concrete use their full strain capacity.
  • 2078 Bhadra · 6 marks

What are the factors affecting the ductility? Explain the ductility requirements of R.C.C. beam as per IS 13920.

Answer

Factors affecting ductility

  1. Tension steel ratio: higher ρ\rho gives lower ductility; under-reinforced sections are ductile.
  2. Compression steel: reduces neutral axis depth and raises ductility.
  3. Grade of steel: high-strength steel with small elongation reduces ductility; Fe 415/500 with good elongation is preferred.
  4. Grade of concrete: higher-strength concrete is more brittle (smaller ultimate strain).
  5. Confinement: closely spaced stirrups/hoops increase concrete strain capacity.
  6. Axial load: high axial load reduces ductility of columns.
  7. Shear and bond: shear or bond failure prevents flexural ductility from developing.
  8. Detailing of anchorage and lap: poor detailing causes slip.

Ductility requirements of beams (IS 13920)

  • b≥200b \ge 200 mm, b/D≥0.3b/D \ge 0.3, D≤L/4D \le L/4.
  • ρmin=0.24fck/fy\rho_{min} = 0.24\sqrt{f_{ck}}/f_y, ρmax=2.5%\rho_{max} = 2.5\%.
  • At least two 12 mm bars continuous at top and bottom.
  • Bottom steel at a joint face ≥50%\ge 50\% of top steel; capacity anywhere ≥25%\ge 25\% of the maximum end capacity.
  • Splices in the middle half only, hoops ≤150\le 150 mm over the lap; none in the joint or within 2d2d.
  • Closed stirrups with 135∘135^\circ hooks, tail 10ϕ10\phi; diameter ≥6\ge 6 mm (8 mm for span > 5 m).
  • Spacing: min⁡(d/4, 8ϕ, 100)\min(d/4,\ 8\phi,\ 100) mm within 2d2d of supports, first stirrup at 50 mm; ≤d/2\le d/2 elsewhere.
  • Shear design for hinge capacity.
  • 2082 Bhadra · 2+2+2 marks

Perform the ductile design and detailing requirements of flexural reinforcement in beam and for axial load as well as biaxial bending moments in columns as per IS 13920. Explain with neat drawings.

Answer

Ductile design of beam flexural reinforcement

  1. Analyse the frame for gravity and seismic load combinations (1.5(DL±EL)1.5(DL\pm EL), 1.2(DL+LL±EL)1.2(DL+LL\pm EL), 0.9DL±1.5EL0.9DL \pm 1.5EL) and get design hogging and sagging moments at the faces of supports.
  2. Check geometry: b≥200b \ge 200 mm, b/D≥0.3b/D \ge 0.3, D≤L/4D \le L/4.
  3. Design the steel for MuM_u using IS 456 limit state design, keeping xu≤xu,maxx_u \le x_{u,max}.
  4. Detail it: ρmin=0.24fck/fy≤ρ≤2.5%\rho_{min} = 0.24\sqrt{f_{ck}}/f_y \le \rho \le 2.5\%; two bars continuous at top and bottom; bottom steel at joint face ≥50%\ge 50\% of top steel; capacity at any section ≥25%\ge 25\% of maximum end capacity.
  5. Shear: design for the shear from hinge capacities,
Vu=Vu,aD+L±1.4 Mu,limAs+Mu,limBhLABV_{u} = V_{u,a}^{D+L} \pm 1.4\,\frac{M_{u,lim}^{As} + M_{u,lim}^{Bh}}{L_{AB}}

where Mu,limM_{u,lim} are the moments of resistance of the sagging and hogging steel provided at the two ends A and B. Provide closed stirrups with 135∘135^\circ hooks, spacing ≤min⁡(d/4, 8ϕ, 100)\le \min(d/4,\ 8\phi,\ 100) within 2d2d of the joint.

Ductile design of columns (axial load plus biaxial bending)

  1. Size: b≥200b \ge 200 mm and b/D≥0.4b/D \ge 0.4.
  2. Design for PuP_u and biaxial moments MuxM_{ux}, MuyM_{uy} using IS 456 cl. 39.6:
(MuxMux1)αn+(MuyMuy1)αn≤1\left(\frac{M_{ux}}{M_{ux1}}\right)^{\alpha_n} + \left(\frac{M_{uy}}{M_{uy1}}\right)^{\alpha_n} \le 1

with αn\alpha_n from Pu/PuzP_u/P_{uz} (1.0 to 2.0). Steel between 0.8% and 6% (4% at laps). 3. Strong column-weak beam: ∑Mc≥1.1 (to 1.4)∑Mb\sum M_{c} \ge 1.1\ (\text{to}\ 1.4)\sum M_b at each joint. 4. Column shear: Vu=1.4 Mu,limbL+Mu,limbRhstV_u = 1.4\,\dfrac{M_{u,lim}^{bL} + M_{u,lim}^{bR}}{h_{st}}; provide confining hoops over lo=max⁡(D, h/6, 450)l_o = \max(D,\ h/6,\ 450) at 75-100 mm, with Ash=0.18 s h (fck/fy)(Ag/Ak−1)A_{sh} = 0.18\,s\,h\,(f_{ck}/f_y)(A_g/A_k-1).

 BEAM: |hoops 2d @ <=100|   d/2    |hoops 2d @ <=100|
 COLUMN: hoops lo @ 75-100 | normal | hoops lo @ 75-100
  • 2081 Baisakh · 5 marks

Describe importance of ductile detailing in RC structures with neat sketches of ductile detailing for beams and columns.

Answer

Ductile detailing is the arrangement of reinforcement (IS 13920) that lets RC members deform plastically in an earthquake without brittle failure.

Importance

  • Allows design for a reduced seismic force (RR factor in IS 1893), so the building is economical.
  • Dissipates energy through hinges, preventing sudden collapse and saving lives.
  • Gives warning before failure through large deformation.
  • Confined concrete has greater strain capacity and strength.
  • Prevents brittle shear, bond and joint failures.
  • Moves hinges to the beams, keeping the columns, which carry gravity load, intact.

Beam detailing

 |-2d-|------- d/2 --------|-2d-|
 ||||| |  |  |  |  |  |  | |||||   closed hoops
 =====================================  2 bars continuous
 ===  =====================  ===      top / bottom
  s<=min(d/4,8phi,100)       lap in middle half
  • Closed stirrups with 135∘135^\circ hooks and 10ϕ10\phi tails; first at 50 mm; s≤min⁡(d/4, 8ϕ, 100)s \le \min(d/4,\ 8\phi,\ 100) over 2d2d; ≤d/2\le d/2 elsewhere.
  • Bottom bars at the joint face ≥\ge 50% of top bars.

Column detailing

  --------------
  | ##########  |  lo = max(D, h/6, 450)
  | ##########  |  s = 75-100 mm
  |     #  #     |  normal spacing in
  |     #  #     |  mid-height
  | ##########  |  lo again
  --------------
  • Hoops with 135∘135^\circ hooks, tail 6ϕ6\phi; splices only in the middle half.
  • Strong column - weak beam at each joint.
  • 2080 Baisakh · 4+4 marks

What is the philosophy of design of structures in earthquake prone region? Explain about design for strength and ductility.

Answer

Philosophy of design in earthquake-prone regions

It is uneconomical to design buildings to remain elastic in a severe earthquake. The accepted philosophy (IS 1893, NBC 105) is:

  • Minor, frequent shaking: the structure should suffer no damage (stays elastic).
  • Moderate shaking: structural damage is limited and repairable; some non-structural damage is acceptable.
  • Severe, rare shaking (design earthquake): the structure may be heavily damaged but should not collapse, so life is protected.

This is achieved by combining adequate strength, stiffness and, above all, ductility.

Design for strength

The structure is designed for the design lateral force instead of the full elastic force:

Ah=Z2⋅IR⋅Sag,VB=AhWA_h = \frac{Z}{2}\cdot\frac{I}{R}\cdot\frac{S_a}{g}, \qquad V_B = A_h W

where ZZ is the zone factor, II the importance factor, RR the response reduction factor and Sa/gS_a/g the spectral acceleration. The base shear is distributed over the height (Qi=VB Wihi2/∑Wjhj2Q_i = V_B\,W_i h_i^2/\sum W_j h_j^2) and members are designed with load combinations such as 1.2(DL+LL±EL)1.2(DL+LL\pm EL), 1.5(DL±EL)1.5(DL\pm EL) and 0.9DL±1.5EL0.9DL \pm 1.5EL.

Design for ductility

Because R>1R > 1 allows lower strength, the structure must be able to yield and deform inelastically in a controlled manner. This is ensured by:

  • under-reinforced sections and limited steel;
  • strong column - weak beam, with hinges forming in beams;
  • capacity design for shear (shear capacity greater than flexural);
  • confined hoops (closely spaced, 135∘135^\circ hooks) at beam and column ends and joints;
  • proper anchorage and splice locations (IS 13920);
  • regular configuration with no soft storey or short column.
  • 2072 Kartik · 4 marks

How do you consider earthquake loads while designing RCC structures? Explain briefly.

Answer

Earthquake loads are considered as equivalent static lateral forces (or by response spectrum analysis for tall or irregular buildings), as per IS 1893 (Part 1) or NBC 105:2020 in Nepal.

Steps

  1. Seismic weight WW = dead load + a percentage of live load (25% if live load ≤3\le 3 kN/m2^2, 50% if more; roof live load is neglected).
  2. Time period of a bare RC frame: T=0.075 h0.75T = 0.075\,h^{0.75} (s), hh in m.
  3. Design base shear:
VB=AhW,Ah=Z2IRSagV_B = A_h W,\qquad A_h = \frac{Z}{2}\frac{I}{R}\frac{S_a}{g}

with ZZ from the zone map, II importance factor, RR response reduction factor (5 for special moment resisting RC frames, 3 for ordinary) and Sa/gS_a/g from the spectrum for soil type. 4. Distribute over height: Qi=VBWihi2∑Wjhj2Q_i = V_B \dfrac{W_i h_i^2}{\sum W_j h_j^2} and apply at each floor in both directions (plus 30% of the orthogonal force). 5. Load combinations (IS 456 cl. 18.2): 1.5(DL+LL)1.5(DL+LL), 1.2(DL+LL±EL)1.2(DL+LL\pm EL), 1.5(DL±EL)1.5(DL\pm EL), 0.9DL±1.5EL0.9DL\pm 1.5EL. 6. Design and detail members for the worst combination and provide ductile detailing as per IS 13920.

Questions from Old Question Collection (CE 702) (IOE exam papers from 2065 to 2082 (CE 702, BCE IV/I)) and Old Question Collection (CE 702) (4 IOE papers 2075 to 2079 (only 2079 Baisakh not already in the other file)). Answers are written for this site; check them against your class notes.

Chapter titles and hours from the IOE syllabus ↗