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Chapter 2 · 5 hours

Method of Estimating

IOE past exam questions

Past questions and answers

20 questions set from this chapter, 7 of them more than once; 4 are most repeated (set, or a close variant set, in 3 or more exams). Most repeated first.

  • Most repeated · 6 of 22 exams
  • Asked 6 times
  • 2075 Asoj · 4 marks
  • 2070 Chaitra · 4 marks
  • 2080 Baisakh · 4 marks
  • 2078 Bhadra · 4 marks
  • 2082 Bhadra · 1 mark
  • 2074 Chaitra · 5 marks

What are the various methods of taking out quantities? Explain briefly.

Answer

Quantities of a building (mainly walls and foundation) are taken out by the following methods.

1. Long wall and short wall method

  • Walls running in the long direction are called long walls; those running in the short direction are short walls.
  • Long wall length (out-to-out) = centre-to-centre length + half the width of the trench/wall at each end.
  • Short wall length (in-to-in) = centre-to-centre length - half the width at each end.
  • Each wall is multiplied by its own width and depth. It is accurate but needs more calculation; it suits walls of different thicknesses.

2. Centre line method

  • The total centre-line length of all walls is found and multiplied by the section (width x depth) of the wall or foundation.
  • Where walls meet (junctions), a deduction of half the width of the wall for each junction is made from the total length.
  • It is quick and best for buildings with uniform walls and rooms of the same type.

3. Crossing (partition) wall method

  • Separate cross-walls are measured by their own lengths and multiplied by the section; useful when walls differ in thickness.

4. Individual wall (separate wall) method

  • Each wall is measured one by one.

5. Bay method

  • The building is divided into bays between columns, and each bay is measured, used for framed structures and sheds.

6. Unit (approximate) methods

  • Cost per unit area/volume for a quick estimate.

In practice, the long wall-short wall and centre line methods are the two used in building estimates in Nepal.

  • Most repeated · 5 of 22 exams
  • Asked 5 times
  • 2082 Bhadra · 2 marks
  • 2076 Asoj · 2 marks
  • 2071 Chaitra · 3 marks
  • 2065 Shrawan (old course) · 2 marks
  • 2068 Baisakh (old course)

What is Bill of Quantities (BOQ)? State its importance.

Answer

Bill of quantities (BOQ)

A bill of quantities is a document that lists, item by item, all the works of a project with their description, unit and quantity, derived from the drawings and specifications. In a priced BOQ the rate and amount for each item are added.

A typical BOQ has these columns:

SNDescription of itemUnitQuantityRateAmount

The total amount (plus contingency and VAT) is the project cost.

Importance

  1. Basis of tendering: all bidders price the same list of quantities, so bids can be compared fairly.
  2. Cost estimate: the BOQ with rates gives the abstract of cost and the total estimate.
  3. Contract document: in a unit-rate contract it is the basis of the contract price.
  4. Payment: interim and final bills are prepared against the BOQ items; variations are valued at the BOQ rates.
  5. Planning: gives quantities of materials, labour and plant for procurement and scheduling.
  6. Cost control: actual quantities and costs are checked against the BOQ.
  7. Variation valuation: additions and omissions can be priced easily.
  • Most repeated · 4 of 22 exams
  • Asked 4 times
  • 2074 Asoj · 6 marks
  • 2073 Shrawan
  • 2068 Baisakh (old course) · 4 marks
  • 2082 Bhadra · 2 marks

Describe how you will prepare a detailed estimate of a building.

Answer

A detailed estimate is prepared by dividing the building into items of work, taking out the quantities of each item from the drawings, and applying rates. The steps are:

  1. Study the drawings and specifications: plan, section, elevation, foundation and structural drawings, and door/window schedules.
  2. List the items in the order of construction: earthwork, PCC, foundation masonry/RCC, DPC, superstructure masonry, columns, beams, slab, doors and windows, plastering, flooring, painting, roofing, sanitary and electrical works.
  3. Take out quantities of each item using the long wall-short wall or centre line method. Use the dimension columns: number x length x breadth x height, and make deductions for openings. A quantity sheet looks like this:
ItemNo.LBHQuantity
  1. Abstract the quantities (collect similar items) in a bill of quantities.
  2. Rate analysis: adopt rates from the District Rate or analyse them using DUDBC norms and local rates.
  3. Abstract of cost: quantity x rate for each item gives the amount; sum of all items is the base cost.
  4. Add provisions: contingency (3 to 5%), work-charged establishment/supervision, and VAT (13%) to get the total estimated cost.
  5. Prepare the report: a brief report with the specifications, assumptions, drawings, and the cost summary.
  • Most repeated · 3 of 22 exams
  • Asked 3 times
  • 2076 Chaitra · 2 marks
  • 2076 Asoj · 2 marks
  • 2080 Bhadra · 4 marks

Explain the rules for deductions from plastering for openings in brick surfaces (as per IS 1200).

Answer

Plastering is measured over the wall surface in m². For openings in brick surfaces, IS 1200 (Part 12) gives the following rules.

Size of openingDeductionReveals (jambs, sills, soffits)
Up to 0.5 m²No deductionNo addition
More than 0.5 m² and up to 3 m²Deduct on one face only (the area of the opening is deducted from one side)Not added
More than 3 m²Deduct both faces (full opening on each plastered face)Measured and added separately

Other points:

  • Where the plaster is on one face only, the opening is deducted from that face as per the same limits.
  • For ends of walls, jambs, sills and soffits of larger openings, the plastering of the reveal is measured by width x girth and added.
  • No deduction is made for the ends of beams, joists, or rafters, and for small holes.
  • Many Nepali offices, for simplicity, deduct the full area of every opening on the plastered face and then add the reveals.

Example: a wall 4 m x 3 m has a window 1.2 m x 1.2 m (1.44 m²) and plaster on both faces. The deduction is 1.44 m² once (one face only), so the net plaster = 2 x 12 - 1.44 = 22.56 m².

  • Asked 2 times
  • 2080 Baisakh · 4 marks
  • 2081 Baisakh · 4 marks

What are the sub-heads of various items of work for a building project?

Answer

A building estimate is divided into sub-heads (groups of similar items), arranged in the order of construction. This makes quantity taking and checking easy.

SNSub-headTypical items
1Site preparation and earthworkSite clearance, setting out, excavation, backfilling, disposal
2Concrete work (plain)PCC in foundation, brick/stone soling, DPC
3Foundation and masonryBrick/stone masonry in foundation, plinth, superstructure, partition walls
4Reinforced concrete workConcrete in footings, columns, beams, slabs, stairs, lintels; formwork; reinforcement
5Doors, windows and woodworkFrames, shutters, ventilators, hardware, grills
6RoofingRoof truss, CGI/tile roofing, waterproofing, parapet
7FlooringFloor base, tiles/terrazzo/cement punning, skirting, dado
8Plastering and pointingInternal and external plaster, pointing
9FinishingWhitewash, distemper, painting of doors, windows, walls
10Water supply and sanitary worksPipes, fittings, W.C., basin, septic tank, drainage
11Electrical worksWiring, fixtures, switches, earthing
12Miscellaneous and external worksBoundary wall, gate, drain, paving, landscaping, lightning conductor

Finally, contingency, VAT and work-charged establishment are added to the total of all sub-heads.

  • Asked 2 times
  • 2075 Chaitra · 4 marks
  • 2076 Chaitra · 2 marks

Explain Bill of quantities and abstract of cost, and enumerate the relationship and differences between the Bill of quantities and the Abstract of estimated cost.

Answer

Bill of quantities (BOQ)

The BOQ lists all items of work with their description, unit and quantity (and, once priced, rate and amount). It is used in tendering and as the basis of the contract and payment.

Abstract of cost (AOC)

The abstract of cost is a summary sheet in which the quantity of each item (from the BOQ or quantity sheet) is multiplied by its rate to obtain the amount; the total of all items, with contingency and taxes, gives the estimated cost of the project.

Relationship

  • Both are built from the same quantity calculation sheets.
  • The BOQ gives quantities; adding rates to the BOQ gives the AOC (a priced BOQ is, in effect, an abstract of cost).
  • The totals of both must agree.

Differences

BasisBill of quantitiesAbstract of cost
ContentItem, unit, quantity (rate optional)Item, quantity, rate, amount
PurposeTender document and contractCost estimate for approval
PreparedBefore tender, for biddersIn the estimate, by the owner
Who pricesBidder fills in the ratesEstimator uses the analysed rates
Shows total costOnly after pricingAlways, with contingency and tax
  • Asked 2 times
  • 2067 Poush (old course) · 5 marks
  • 2067 Asar (old course) · 4 marks

How are the following items of work measured? i) Plaster work ii) Cornice work.

Answer

i) Plaster work

  • Unit: m² (measurement and payment).
  • Method: the length and height of the wall surface are measured on each plastered face (floor to ceiling or the top of the plastered area). Each face is measured separately, as internal and external plaster have different mortar mixes and thicknesses.
  • Deductions (IS 1200 Part 12): openings up to 0.5 m² - no deduction; 0.5 to 3 m² - deduct one face only; above 3 m² - deduct both faces. Reveals are not added for openings up to 3 m², and are measured and added for larger openings.
  • Plaster of skirting, dado, ceiling, band, and curved surfaces is measured separately where the rate differs. The thickness (12 or 15 mm), the mortar (1:4, 1:6) and the type of surface (brick, concrete) are stated in the item.
  • Example: wall 5 m x 3 m with a door 1 m x 2.1 m on both plastered faces: area = 2 x (5 x 3) - 2.1 (once, as the opening is 0.5 to 3 m²) = 27.9 m².

ii) Cornice work

  • Unit: running metre (m) for a cornice of given profile and girth. Where the cornice is large, it may be measured in m³ for masonry/concrete and m² for plaster.
  • Method: the length is measured along the centre line of the cornice, over the wall faces on which it runs, without deduction for corners; the size (girth, projection, depth) and the mortar are stated in the description.
  • Plastering of the cornice surface is measured along its girth, m x girth in m², unless included in the running metre item.
  • 2081 Bhadra · 5 marks

Write down the general method of taking out quantities in a load bearing brick masonry building with their suitability.

Answer

In a load bearing brick masonry building the walls carry the load and the foundation is a continuous strip below them. The quantities of earthwork, PCC, foundation masonry and superstructure are taken out for each wall by one of these methods.

1. Long wall - short wall method

  • Choose the walls running in the longer direction as long walls, the others as short walls.
  • Length of long wall (out-to-out) = centre-to-centre length + half the foundation (or wall) width at each end, =Lc+b= L_c + b.
  • Length of short wall (in-to-in) = centre-to-centre length - half the width at each end, =Lc−b= L_c - b.
  • Quantity = length x breadth x depth for each wall at every level (trench, PCC, footing, plinth, wall), because the widths change with depth.
  • Suitable for: buildings with several rooms, walls of different thicknesses, and where the foundation has different widths for different walls.

2. Centre line method

  • Find the total centre-line length of all walls (main and partition).
  • Deduct for the junctions: for each T-junction/cross-junction deduct half of the wall width.
  • Quantity = corrected total length x width x depth of each section.
  • Suitable for: buildings having walls of the same section throughout, rectangular rooms, quick estimates. It is not accurate where the sections differ.

Procedure for both

  1. Mark the walls on the plan with their centre lines.
  2. Calculate the length of each as per the chosen method.
  3. Take out earthwork, PCC, masonry up to plinth, DPC, then superstructure masonry.
  4. Deduct for the openings (doors, windows, ventilators), lintels, and beams, to get net masonry.

In Nepal both methods are accepted; the centre line is quicker, and long wall-short wall is preferred for exactness.

  • 2078 Bhadra · 2 marks

State the different factors considered during detailed estimation.

Answer

The main factors considered in a detailed estimate are:

  1. Completeness and accuracy of the drawings and specifications.
  2. Quantities of each item, measured by the standard rules of measurement and the correct units.
  3. Rates of materials, labour and transport (lead), based on the District Rate and DUDBC norms.
  4. Site conditions: soil type, water table, access, haulage distance and availability of water and labour.
  5. Method of construction and equipment to be used.
  6. Time of construction and season, which influence rates and productivity.
  7. Wastage allowances, overhead, profit, contingency and taxes (VAT 13%).
  8. Local rules, safety and environmental requirements.
  • 2079 Bhadra · 4 marks

You are working for a design project of a building. Your Team Leader instructs you to perform a work break down structure for the quantity calculation work. How are you planning to do so for the frame structure building project?

Answer

A work breakdown structure (WBS) divides the whole quantity-calculation job into smaller, manageable work packages, each with a clear owner and output. For an RCC frame building I would plan it as follows.

Step 1: Understand the scope

Collect the architectural and structural drawings (plans, sections, column layout, beam and slab details, schedules), the specifications and the BOQ format.

Step 2: Break down into levels

Level 0  Frame building project
 |
 +-- 1 Substructure
 |    1.1 Earthwork   1.2 PCC/soling
 |    1.3 Footings    1.4 Columns to plinth
 |    1.5 Plinth beam 1.6 Backfill, DPC
 +-- 2 Superstructure (per floor)
 |    2.1 Columns  2.2 Beams  2.3 Slab
 |    2.4 Stair    2.5 Brick/block walls
 |    2.6 Lintel, sunshade, parapet
 +-- 3 Finishing
 |    plaster, floor, paint, doors, windows
 +-- 4 Services (water, sanitary, electrical)
 +-- 5 External works (boundary, drain, road)

Step 3: Define each work package

For every package: concrete, formwork and reinforcement are taken separately (m³, m², kg), with the drawing reference, the formula, and the check procedure.

Step 4: Assign and schedule

Distribute the packages among the team members, set deadlines in the order of construction, and use a common quantity sheet format.

Step 5: Check and compile

Cross-check totals (for example concrete from columns + beams + slabs against the structural volume), consolidate into the BOQ, and prepare the abstract of cost.

  • 2079 Bhadra · 4 marks

What are the necessary points that need to be considered while measuring earthwork?

Answer

The following points are considered when measuring earthwork:

  1. Classification of soil: ordinary soil, soft rock, hard rock, and water-bearing strata are measured separately because their rates differ.
  2. Dimensions: length x breadth x depth of the trench or pit, measured as the net volume in place (m³). The width of the foundation plus the working space (at least 0.15 to 0.3 m each side) and the depth to the bottom of the PCC.
  3. Depth range: excavation is classified by depth (0 to 1.5 m, 1.5 to 3 m, and so on), and the lift and lead are specified.
  4. Slopes and benching: side slopes in deep trenches, and benching, are added if allowed in the specification, otherwise the vertical sides are taken with shoring.
  5. Lead and lift: the distance and the height of carrying the excavated soil away or to the filling site.
  6. Dewatering, shoring and strutting when needed, measured as separate items.
  7. Backfilling and disposal: the quantity of backfill = excavated volume - volume of foundation work below ground level. The surplus soil is disposed of or used for filling plinth.
  8. Bulking and shrinkage: soil swells (about 20 to 30%) on excavation and compacts on filling.
  9. No deduction for small items such as pipes, and no addition for the loosening of the soil.
  10. Units: m³ for excavation/filling, m² for surface dressing, m for trimming along a line (as per the specification).
  • 2075 Asoj · 4+4 marks

What are the components of a complete estimate? Prepare a sample of abstract of cost.

Answer

Components of a complete estimate

A complete estimate gives the total final cost of the project, including all costs related to the building besides the main construction cost:

  1. Land cost and compensation, including legal charges.
  2. Cost of the main building (civil works), from the detailed estimate.
  3. Water supply, sanitary and drainage works.
  4. Electrical installation (wiring, fittings, earthing, lightning conductor, lift).
  5. Architectural treatment and special finishing.
  6. External works: approach road, compound wall, gate, landscaping, septic tank.
  7. Furniture, equipment and fittings.
  8. Planning, design and supervision charges (consultant fees), and establishment.
  9. Contingency (3 to 5%) and work-charged establishment.
  10. Taxes (VAT 13%), interest during construction, and price escalation provisions.

Sample abstract of cost

(Illustrative quantities and rates)

SNItemQtyUnitRate (Rs)Amount (Rs)
1Earthwork in excavation100m³60060,000
2PCC 1:3:610m³11,500115,000
3Brickwork 1:640m³15,500620,000
4RCC M20 (concrete)25m³18,000450,000
5Reinforcement Fe 5002,500kg150375,000
6Plaster 12.5 mm300m²480144,000
7Flooring100m²90090,000
Sub-total1,854,000
Contingency 5%92,700
Total1,946,700
VAT 13%253,071
Grand total2,199,771

Rates are illustrative; actual rates are taken from the District Rate.

  • 2071 Chaitra · 3 marks

Prepare tables of quantity sheet and abstract of cost for a residential building.

Answer

Assumed: a single-room residential building, clear size 4 m x 3 m, 230 mm brick walls, 3.0 m high, one door 1.0 x 2.1 m and one window 1.2 x 1.2 m; trench 0.9 m wide x 1.0 m deep; centre line length L=2(4.23+3.23)=14.92L = 2(4.23 + 3.23) = 14.92 m.

Quantity sheet (detailed measurement)

ItemNo.L (m)B (m)H (m)Quantity
Excavation114.920.901.0013.43 m³
PCC 1:3:6114.920.900.152.01 m³
Brickwork in foundation and plinth114.920.350.753.92 m³
DPC114.920.23-3.43 m²
Brickwork in superstructure114.920.233.0010.29 m³
Deduct door-11.000.232.10-0.48 m³
Deduct window-11.200.231.20-0.33 m³
Net superstructure brickwork9.48 m³
Plaster inside 2(4+3) x 3 less openings 3.5438.46 m²
Plaster outside 2(4.46+3.46) x 3 less openings 3.5443.98 m²
Flooring14.03.0-12.00 m²

Abstract of cost (rates illustrative)

SNItemQtyUnitRate (Rs)Amount (Rs)
1Excavation13.43m³6008,058
2PCC 1:3:62.01m³11,50023,115
3Brickwork 1:6 in foundation3.92m³14,00054,880
4DPC3.43m²6502,230
5Brickwork 1:6 in superstructure9.48m³15,500146,940
6Plaster 12.5 mm, both faces82.44m²48039,571
7Flooring12.00m²90010,800
Total285,594

Contingency, VAT and the other items (RCC slab, roofing, doors, painting) would be added in the same way.

  • 2080 Bhadra · 6 marks

For a construction project the following quantities of works need to be executed with the given cost. Prepare Abstract of Cost (AOC), Bill of Quantities (BOQ) and Summary of cost including 5% contingency and 13% taxes.
SNItems of WorksQuantityUnitUnit Rate
1Earthwork in excavation150Cum150
2Earthwork for backfilling100Cum200
3PCC of work for foundation5Cum9000
42nd class Brickwork for foundation2.5Cum12000
51st class Brickwork for superstructure25Cum15000
6(1:5) Plastering work450Sqm200
7PCC for RCC work10Cum16000
8Fe-415 reinforcement1300Kg150

Answer

Abstract of cost (AOC)

Amount = quantity x unit rate.

SNItem of workQuantityUnitRate (Rs)Amount (Rs)
1Earthwork in excavation150Cum15022,500.00
2Earthwork for backfilling100Cum20020,000.00
3PCC work for foundation5Cum9,00045,000.00
42nd class brickwork for foundation2.50Cum12,00030,000.00
51st class brickwork for superstructure25Cum15,000375,000.00
6(1:5) Plastering work450Sqm20090,000.00
7PCC for RCC work10Cum16,000160,000.00
8Fe-415 reinforcement1,300Kg150195,000.00
Total of all items937,500.00

Bill of quantities (BOQ)

SNDescription of itemUnitQuantity
1Earthwork in excavationCum150
2Earthwork for backfillingCum100
3PCC work for foundationCum5
42nd class brickwork for foundationCum2.50
51st class brickwork for superstructureCum25
6(1:5) Plastering workSqm450
7PCC for RCC workCum10
8Fe-415 reinforcementKg1,300

(The rate and amount columns of the BOQ are filled by the bidder; with the rates above it becomes the priced BOQ shown in the abstract.)

Summary of cost

DescriptionAmount (Rs)
Total cost of works (sum of AOC)937,500.00
Add contingency 5%46,875.00
Cost including contingency984,375.00
Add VAT 13% on 984,375.00127,968.75
Grand total1,112,343.75

The 13% VAT is applied on the cost including contingency, as is the usual Nepal practice.

Answer: Total of works = Rs 937,500.00; with 5% contingency = Rs 984,375.00; grand total with 13% VAT = Rs 1,112,343.75.

  • 2073 Shrawan

Prepare a bill of quantities from the following data for the construction of an RCC T-beam decking bridge.
Quantity of workDetail of workRate per unit of work
108 m³PCC (1:1:2) for RCC worksRs 13,200.00
3240 m²Formwork for RCC worksRs 750.00
21600 kgSteel reinforcement for RCC worksRs 115.00
18 m³PCC (1:2:4) wearing coatRs 12090.00

Answer

A bill of quantities lists each item with its description, unit, quantity, rate and amount (amount = quantity x rate).

SNDescription of workUnitQuantityRate (Rs)Amount (Rs)
1PCC (1:1:2) for RCC worksm³10813,200.001,425,600.00
2Formwork for RCC worksm²3,240750.002,430,000.00
3Steel reinforcement for RCC workskg21,600115.002,484,000.00
4PCC (1:2:4) wearing coatm³1812,090.00217,620.00
Total6,557,220.00

Working of the amounts:

  • PCC for RCC: 108 x 13,200 = 1,425,600.00
  • Formwork: 3,240 x 750 = 2,430,000.00
  • Reinforcement: 21,600 x 115 = 2,484,000.00
  • Wearing coat: 18 x 12,090 = 217,620.00

Answer: Total cost of the T-beam decking works = Rs 6,557,220.00. Contingency and VAT are added to this total if required.

  • 2082 Baisakh · 5 marks

Explain the rules for deduction in quantities for brickwork, plastering and painting works with an example.

Answer

Quantities are measured net, so openings and voids are deducted as per IS 1200 and the Nepal practice. The rules depend on the size of the opening.

Brickwork (IS 1200 Part 3)

  • Deduct all openings (doors, windows, ventilators) in full volume: opening area x wall thickness.
  • Openings up to 0.1 m²: no deduction. Bearing of lintels and beams that are of concrete are deducted; the end of joists, rafters and so on: no deduction.
  • Reinforced concrete lintels, beams, columns inside the wall are deducted from brickwork.

Plastering (IS 1200 Part 12)

OpeningDeduction
up to 0.5 m²none
0.5 to 3 m²one face only, no addition for reveals
above 3 m²both faces, and reveals measured and added

Painting (IS 1200 Part 15)

  • Painting on plastered walls follows the plaster rule; openings up to 0.5 m² are not deducted.
  • For doors and windows, painting is measured on the opening area with the multiplying factors of IS 1200 (for example 1.30 for panelled, 1.80 for louvered).

Example

Brick wall 6 m x 3 m x 0.23 m thick, with a window 1.2 x 1.2 m (1.44 m²) and a door 1.0 x 2.1 m (2.10 m²), plastered on both faces.

  • Brickwork: 6 x 3 x 0.23 = 4.14 m³; deduct (1.44 + 2.10) x 0.23 = 0.814 m³; net = 3.33 m³.
  • Plaster (both faces): gross = 2 x 18 = 36 m². Both openings are between 0.5 and 3 m², so deduct one face only: 36 - 3.54 = 32.46 m².
  • Painting of the plastered surface: same as the plaster quantity, 32.46 m².
  • 2076 Asoj · 2 marks

Explain the multiplying factors adopted in painting of panelled door, flush door, louver door and glazed window.

Answer

Painting of doors and windows is measured as the area of the opening (length x breadth, including the frame), taken on one face. As the surface is much more than the plain area (panels, mouldings, louvers, edges, frame, etc.), the area is multiplied by a factor that accounts for the extra surface. Typical factors as per IS 1200 (Part 15), for each side painted:

Type of door/windowMultiplying factor
Panelled, framed and braced door1.30
Flush door1.20
Louvered (venetian) door1.80
Glazed (fully glazed/sash) window or door0.80

Reasons: a panelled door has recessed panels and mouldings, so surface area exceeds the plane area by 30%. A flush door has both flat faces plus edges, so the factor is slightly above 1. A louvered door has slats at an angle with both sides exposed, so the factor is large. A glazed one has part of the opening covered by glass, so less surface needs painting, but the frame, bars and edges still do.

Example: panelled door 1.0 x 2.1 m = 2.1 m²; painting area per side = 2.1 x 1.30 = 2.73 m². The factors should be checked against the current edition of the IS code or the Nepal norms used.

  • 2076 Chaitra · 2 marks

Explain the multiplying factors adopted for panelled door and louver door.

Answer

Doors are painted over a larger surface than the plain opening area because of panels, mouldings and slats. To simplify measurement, the area of the door opening (including the frame) is multiplied by a factor.

DoorMultiplying factor (IS 1200 Part 15, per side)Reason
Panelled door1.30Recessed panels, mouldings and rails give about 30% extra surface
Louvered (venetian) door1.80Inclined slats are exposed on both faces and their edges; the surface is nearly double

Use: painting quantity = width x height of the door opening x factor (for each painted side). For example, a panelled door of 1.0 x 2.1 m painted on one side = 2.1 x 1.30 = 2.73 m², and a louvered door of the same size = 2.1 x 1.80 = 3.78 m².

  • 2066 Bhadra (old course) · 2 marks

Write a short note on the centre line method.

Answer

The centre line method is a quick way of finding the quantities of earthwork, foundation and wall in a building that has walls of the same section.

Procedure

  1. Find the total centre-line length of all the walls (main and partitions), measured along the middle of the walls.
  2. Deduct for the junctions where walls meet: each T-junction takes away half of the width of the wall (the part counted twice); a cross-junction deducts the same on each side.
  3. Multiply the corrected length by the width and the depth of each section (trench, PCC, footing, plinth masonry, superstructure).

Formula

Lcorrected=Ltotal−n×b2L_{corrected} = L_{total} - n \times \frac{b}{2}

where nn is the number of junctions and bb the width of the wall at that level.

Example

For a room 4 m x 3 m (clear) with a 0.23 m wall: L=2(4.23+3.23)=14.92L = 2(4.23 + 3.23) = 14.92 m. A partition with two T-junctions would deduct 2×0.23/2=0.232 \times 0.23/2 = 0.23 m. The trench volume = 14.92×0.9×1.0=13.4314.92 \times 0.9 \times 1.0 = 13.43 m³.

Merits and limits

It is fast and simple, and suited to uniform rectangular buildings; it is not accurate where the wall sections differ, for which the long wall-short wall method is used.

  • 2071 Chaitra · 4 marks

Explain with neat sketches how to work out the quantity of a semi-circular arch (span, thickness and rise of arch given).

Answer

A semicircular arch has a rise equal to half the span. The brickwork quantity of the arch is the volume of the arch ring (the area between the intrados and the extrados) multiplied by the wall thickness.

        extrados  R = r + t
      .-----------.
    .' .---------. '.
   /  /  intrados \  \
  |  |     r      |  |
  |__|____________|__|
     <---- span --->
        S = 2r

Method

  1. Span S=2rS = 2r, so the radius of the intrados is r=S/2r = S/2 and the rise equals rr.
  2. Radius of the extrados: R=r+tR = r + t, where tt is the thickness (depth) of the arch ring.
  3. Area of the arch ring (half annulus):
A=π2(R2−r2)A = \frac{\pi}{2}\left(R^2 - r^2\right)
  1. Quantity of arch masonry: V=A×bV = A \times b, where bb is the thickness of the wall (the width of the arch along the wall).
  2. Brickwork above the opening (solid wall between the arch and the lintel level) is measured separately; the opening below the springing line is deducted from the wall as a rectangle S×S \times height up to springing, and the semicircle πr22×b\frac{\pi r^2}{2} \times b is deducted above it, and then the arch ring is added at the arch masonry rate.

Worked example (assumed values)

Span 2.0 m (r=1.0r = 1.0 m), arch thickness t=0.30t = 0.30 m (R=1.30R = 1.30 m), wall thickness b=0.23b = 0.23 m.

A=π2(1.302−1.002)=1.0838 m2,V=1.0838×0.23=0.249 m3A = \frac{\pi}{2}(1.30^2 - 1.00^2) = 1.0838\ \text{m}^2, \qquad V = 1.0838 \times 0.23 = 0.249\ \text{m}^3

Opening to be deducted from the wall (semicircle above the springing line): π2(1.0)2×0.23=0.361\frac{\pi}{2}(1.0)^2 \times 0.23 = 0.361 m³.

Answer: Arch ring masonry = 0.249 m³ (for the assumed dimensions).

Questions from Old Question Collection (CE 705) (IOE exam papers from 2065 Shrawan to 2082 Bhadra (22 papers; 2065-2068 are the older Estimating and Valuation syllabus)). Answers are written for this site; check them against your class notes.

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